How can I access an object property named as a variable in php?
PhpJsonGoogle ApiPhp Problem Overview
A Google APIs encoded in JSON returned an object such as this
[updated] => stdClass Object
(
[$t] => 2010-08-18T19:17:42.026Z
)
Anyone knows how can I access the $t value?
$object->$t obviously returns
> Notice: Undefined variable: t in /usr/local/...
>
> Fatal error: Cannot access empty property in /....
Php Solutions
Solution 1 - Php
Since the name of your property is the string '$t', you can access it like this:
echo $object->{'$t'};
Alternatively, you can put the name of the property in a variable and use it like this:
$property_name = '$t';
echo $object->$property_name;
You can see both of these in action on repl.it: https://repl.it/@jrunning/SpiritedTroubledWorkspace
Solution 2 - Php
Correct answer (also for PHP7) is:
$obj->{$field}
Solution 3 - Php
Have you tried:
$t = '$t'; // Single quotes are important.
$object->$t;
Solution 4 - Php
I'm using php7 and the following works fine for me:
class User {
public $name = 'john';
}
$u = new User();
$attr = 'name';
print $u->$attr;
Solution 5 - Php
this works on php 5 and 7
$props=get_object_vars($object);
echo $props[$t];