How are tuples unpacked in for loops?
PythonPython 3.xTuplesIterable UnpackingPython Problem Overview
I stumbled across the following code:
for i, a in enumerate(attributes):
labels.append(Label(root, text = a, justify = LEFT).grid(sticky = W))
e = Entry(root)
e.grid(column=1, row=i)
entries.append(e)
entries[i].insert(INSERT,"text to insert")
I don't understand the i, a
bit, and searching for information on for
didn't yield any useful results. When I try and experiment with the code I get the error:
> ValueError: need more than 1 value to unpack
Does anyone know what it does, or a more specific term associated with it that I can google to learn more?
Python Solutions
Solution 1 - Python
You could google "tuple unpacking". This can be used in various places in Python. The simplest is in assignment:
>>> x = (1,2)
>>> a, b = x
>>> a
1
>>> b
2
In a for-loop it works similarly. If each element of the iterable is a tuple
, then you can specify two variables, and each element in the loop will be unpacked to the two.
>>> x = [(1,2), (3,4), (5,6)]
>>> for item in x:
... print "A tuple", item
A tuple (1, 2)
A tuple (3, 4)
A tuple (5, 6)
>>> for a, b in x:
... print "First", a, "then", b
First 1 then 2
First 3 then 4
First 5 then 6
The enumerate
function creates an iterable of tuples, so it can be used this way.
Solution 2 - Python
Enumerate basically gives you an index to work with in the for loop. So:
for i,a in enumerate([4, 5, 6, 7]):
print(i, ": ", a)
Would print:
0: 4
1: 5
2: 6
3: 7
Solution 3 - Python
Take this code as an example:
elements = ['a', 'b', 'c', 'd', 'e']
index = 0
for element in elements:
print element, index
index += 1
You loop over the list and store an index variable as well. enumerate()
does the same thing, but more concisely:
elements = ['a', 'b', 'c', 'd', 'e']
for index, element in enumerate(elements):
print element, index
The index, element
notation is required because enumerate
returns a tuple ((1, 'a')
, (2, 'b')
, ...) that is unpacked into two different variables.
Solution 4 - Python
[i for i in enumerate(['a','b','c'])]
Result:
[(0, 'a'), (1, 'b'), (2, 'c')]
Solution 5 - Python
You can combine the for index,value
approach with direct unpacking of tuples using ( )
. This is useful where you want to set up several related values in your loop that can be expressed without an intermediate tuple variable or dictionary, e.g.
users = [ ('alice', '[email protected]', 'dog'), ('bob', '[email protected]', 'cat'), ('fred', '[email protected]', 'parrot'),]
for index, (name, addr, pet) in enumerate(users):
print(index, name, addr, pet)
prints
0 alice alice@example.com dog
1 bob bob@example.com cat
2 fred fred@example.com parrot
Solution 6 - Python
The enumerate
function returns a generator object which, at each iteration, yields a tuple containing the index of the element (i
), numbered starting from 0
by default, coupled with the element itself (a
), and the for
loop conveniently allows you to access both fields of those generated tuples and assign variable names to them.
Solution 7 - Python
Short answer, unpacking tuples from a list in a for loop works. enumerate() creates a tuple using the current index and the entire current item, such as (0, ('bob', 3))
I created some test code to demonstrate this:
list = [('bob', 3), ('alice', 0), ('john', 5), ('chris', 4), ('alex', 2)]
print("Displaying Enumerated List")
for name, num in enumerate(list):
print("{0}: {1}".format(name, num))
print("Display Normal Iteration though List")
for name, num in list:
print("{0}: {1}".format(name, num))
The simplicity of Tuple unpacking is probably one of my favourite things about Python :D
Solution 8 - Python
let's get it through with an example:
list = [chips, drinks, and, some, coding]
i = 0
while i < len(list):
if i % 2 != 0:
print(i)
i+=1
output:[drinks,some]
now using EMUNERATE fuction:(precise)
list = [chips, drinks, and, coding]
for index,items in enumerate(list):
print(index,":",items)
OUTPUT: 0:drinks
1:chips
2:drinks
3:and
4:coding