You can use the `-r`(recursive) and `-I`(ignore binary) options in `grep`:

    $ grep -rI &quot;TEXTSEARCH&quot; .



&gt; * `-I`     Process a binary file as if it did not contain matching data; this is equivalent to the `--binary-files=without-match` option.
&gt; * `-r`     Read all files under each directory, recursively; this is equivalent to the `-d recurse` option.


Another, less elegant solution than kevs, is, to chain -exec commands in find together, without xargs and cut:

    find . -type f -exec bash -c &quot;file -bi {} | grep -q text&quot; \; -exec grep TEXTSEARCH {} &quot;;&quot; 



If you know what the file extension is that you want to search, then a very simple way to search all *.txt files from the current dir, recursively through all subdirs, case insensitive:

`grep -ri --include=*.txt &quot;sometext&quot; *`


 


i&#39;ve got an integration test that grabs some json result from a 3rd party server. It&#39;s really simple and works great.

I was hoping to stop actually hitting this server and using `Moq` (or any Mocking library, like ninject, etc) to hijack and force the return result.

is this possible?

Here is some sample code :-

    public Foo GoGetSomeJsonForMePleaseKThxBai()
    {
        // prep stuff ...
    
        // Now get json please.
        HttpWebRequest httpWebRequest = (HttpWebRequest)WebRequest.Create(&quot;Http://some.fancypants.site/api/hiThere);
        httpWebRequest.Method = WebRequestMethods.Http.Get;
        
        string responseText;
        
        using (var httpWebResponse = (HttpWebResponse)httpWebRequest.GetResponse())
        {
        	using (var streamReader = new StreamReader(httpWebResponse.GetResponseStream()))
        	{
        		json = streamReader.ReadToEnd().ToLowerInvariant();
        	}
        }
        
        // Check the value of the json... etc..
    }

and of course, this method is called from my test.

I was thinking that maybe I need to pass into this method (or a property of the class?) a mocked `httpWebResponse` or something but wasn&#39;t too sure if this was the way. Also, the response is a output from an `httpWebRequest.GetResponse()` method .. so maybe I just need to pass in a mocked `HttpWebRequest` ?.

any suggestions with some sample code would be most aprreciated!

Is it possible to mock out a .NET HttpWebResponse?

I&#39;m new to rails and I don&#39;t understand the differences between the use of new+save methods and the create method.

    def create
        @item = Item.new(params[:item])
    
        respond_to do |format|
          if @item.save
            format.html { redirect_to @item, notice: &#39;Item was successfully created.&#39; }
            format.json { render json: @item, status: :created, location: @item }
          else
            format.html { render action: &quot;new&quot; }
            format.json { render json: @item.errors, status: :unprocessable_entity }
          end
        end
    end

and:

      def create
    
        respond_to do |format|
          if Item.create(params[:item])
            format.html { redirect_to @item, notice: &#39;Item was successfully created.&#39; }
            format.json { render json: @item, status: :created, location: @item }
          else
            format.html { render action: &quot;new&quot; }
            format.json { render json: @item.errors, status: :unprocessable_entity }
          end
        end
      end

Differences in rails between new + save and create


    find . -type f | xargs file | grep text | cut -d&#39;:&#39; -f1 | xargs grep -l &quot;TEXTSEARCH&quot; {}

it&#39;s a good solution? for find TEXTSEARCH recursively in only textual files

grep only text files

<pre><code class="hljs language-bash">find . -type f | xargs file | grep text | cut -d':' -f1 | xargs grep -l "TEXTSEARCH" {}
</code></pre>
it's a good solution? for find TEXTSEARCH recursively in only textual files

If I have a text file with a separate command on each line how would I make terminal run each line as a command? I just don&#39;t want to have to copy and paste 1 line at a time. It doesn&#39;t HAVE to be a text file... It can be any kind of file that will work.

`example.txt`:
    
    sudo command 1
    sudo command 2
    sudo command 3

Run text file as commands in Bash

I have been looking throughout the system but I cannot find it. When I do echo $PATH I get the stuff I added, plus the default path. I do not have a .profile, and I do have a .bashrc, but the default path is not in there. I am looking for it just to know where it is located because all the tutorials explain that its in .profile... but what if you don&#39;t have one? Where is it located then? Anybody have any ideas?

Where is the default terminal $PATH located on Mac?

I often use pipes in Bash, e.g.:

    dmesg | less

Although I know what this outputs, it takes `dmesg` and lets me scroll through it with `less`, I do not understand what the `|` is doing. Is it simply the opposite of `&gt;`?

- Is there a simple, or metaphorical explanation for what `|` does?
- What goes on when several pipes are used in a single line?
- Is the behavior of pipes consistent everywhere it appears in a Bash script?

What is a simple explanation for how pipes work in Bash?

I&#39;m using ```go``` as a simple bash alias for ```git checkout branchname```. The thing that I miss is the autocomplete feature that works with the full ```git checkout branchna...``` command, but not in the alias.

Is there a way to instruct Bash to &quot;inherit&quot; the autocomplete &quot;driver&quot; for another command?

Git autocomplete in bash aliases?

I was using the &quot;exit 1&quot; statement in my Bash functions to terminate the whole script and it worked fine:

    function func()
    {
       echo &quot;Goodbye&quot;
       exit 1
    }
    echo &quot;Function call will abort&quot;
    func
    echo &quot;This will never be printed&quot;

But then I realized that it doesn&#39;t do the work when called like:

    res=$(func)

I understand that I created a subshell and &quot;exit 1&quot; aborts that subshell and not the primary one....

But **is there a way to write a function which aborts the whole execution, no matter how it is called?** I just need to get the real return value (echoed by the function).





Is there a way to write a Bash function which aborts the whole execution, no matter how it is called?

I often grep CSV files with column names on the first line. Therefore, I want the output of grep to always include the first line (to get the column names) as well as any lines matching the grep pattern. What is the best way to do this?

Always include first line in grep

[grep][1] is used to search within a file to see if any line matches a given regular expression. However, I have this situation - I want to write a regular expression that will match the filename itself (and not the contents of the file). I will run this from the system&#39;s root directory, to find all those files that match the regular expression.

For example, if I want to find all [Visual Basic][2] form files that start with an &quot;f&quot; and end with .frm, I&#39;ll use the regular expression -

       &quot;f[[:alnum:]]*\.frm&quot;

Can grep do this? If not, is there a utility that would let me do this?

  [1]: https://en.wikipedia.org/wiki/Grep
  [2]: https://en.wikipedia.org/wiki/Visual_Basic




How can I &quot;grep&quot; for a filename instead of the contents of a file?

I am trying to search for a string `0.49` (with dot) using the command

    grep -r &quot;0.49&quot; *

But what happening is that I am also getting unwanted results which contains the string such as `0449`, `0949` etc,. The thing is linux considering dot(.) as any character and bringing out all the results. But I want to get the result only for &quot;0.49&quot;. 


Using grep to search for a string that has a dot in it

Given a file, for example:

    potato: 1234
    apple: 5678
    potato: 5432
    grape: 4567
    banana: 5432
    sushi: 56789

I&#39;d like to grep for all lines that start with `potato:` but only pipe the numbers that follow `potato: `.  So in the above example, the output would be:

    1234
    5432

How can I do that?



How to grep for contents after pattern?

I am searching through a Git repository and would like to include the `.git` folder.

`grep` does not include this folder if I run

    grep -r search *

What would be a grep command to include this folder?


Content Type	Original Author	Original Content on Stackoverflow
Question	stefcud	View Question on Stackoverflow
Solution 1 - Bash	kev	View Answer on Stackoverflow
Solution 2 - Bash	user unknown	View Answer on Stackoverflow
Solution 3 - Bash	Mark B	View Answer on Stackoverflow

grep only text files

Bash Problem Overview

Bash Solutions

Solution 1 - Bash

Solution 2 - Bash

Solution 3 - Bash

Differences in rails between new + save and create

Is it possible to mock out a .NET HttpWebResponse?

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