I had the same issue after copying my key pair from one machine to another. The solution for me was the set the trust level of the keys:

    gpg --edit-key &lt;KEY_ID&gt;
    gpg&gt; trust

You will be asked to select the trust level from the following:

    1 = I don&#39;t know or won&#39;t say
    2 = I do NOT trust
    3 = I trust marginally
    4 = I trust fully
    5 = I trust ultimately
    m = back to the main menu

I selected 5 since I created the key so of course I trust it ultimately :). It will ask you to confirm your decision:

    Your decision? 5
    Do you really want to set this key to ultimate trust? (y/N) y

After confirming, quit with:

    gpg&gt; quit

You should then be able to encrypt using that key.

Before upgrading Xcode to 7.2, I was using Xcode 7.1.1 to build and distribute apps. I have upgraded to Xcode 7.2 and none of my provisioning profiles (matched to that particular app&#39;s bundle ID) match my installed certificates that were working in Xcode 7.1.1. 

I only get:
&gt;Your build settings specify a provisioning profile with the UUID “some_number”, however, no such provisioning profile was found.

I have tried regenerating a `.certSigningRequest` to generate a new Certificate and Profile and made sure the Team in the General tab of the target is correct. Whenever I select a Provision Profile, all of my Code Signing Identities appear in the Identities in Keychain, but none of them will pair correctly.

It seems setting the Provision Profile to Automatic and the Code Signing Identity to iOS Developer will resolve this error, but the advantage of managing my Provisioning Profiles is gone as I believe Xcode then manages these.

Any thoughts on why setting my Provisioning Profiles and Code Signing Identities to anything but Automatic and iOS Developer produces this error?

Xcode 7.2 no matching provisioning profiles found

What is the best way to get exceptions&#39; messages from components of standard library in Python?

I noticed that in some cases you can get it via `message` field like this:

    try:
      pass
    except Exception as ex:
      print(ex.message)

but in some cases (for example, in case of socket errors) you have to do something like this:


    try:
      pass
    except socket.error as ex:
      print(ex)

I wondered is there any standard way to cover most of these situations?

How to get exception message in Python properly

I&#39;m trying to use interesting password management [tool][1] named Pass.

I did the following:

 1. Installed gpg tool `$ sudo dnf install gpg`
 2. Generated a key using `$ gpg --gen-key` 
 3. Typed `$ pass init &quot;foobar id of my gpg key&quot;` as stated [here][1]
 4. Got
 
`mkdir: created directory ‘/home/chichivica/.password-store/’
 Password store initialized for foobar@email.com`

 5. Tried to add a simple password 

`$ pass insert foo
Enter password for foo: 
Retype password for foo:`

 6. And there is the problem

`gpg: A45A123C: There is no assurance this key belongs to the named user
gpg: [stdin]: encryption failed: Unusable public key`


Could anyone give me some advice?

  [1]: http://www.passwordstore.org/

gnupg: There is no assurance this key belongs to the named user

I'm trying to use interesting password management <a href="http://www.passwordstore.org/" target="_blank" rel="noopener noreferrer">tool</a> named Pass.
I did the following:
<ol>
<li>Installed gpg tool <code>$ sudo dnf install gpg</code></li>
<li>Generated a key using <code>$ gpg --gen-key</code></li>
<li>Typed <code>$ pass init "foobar id of my gpg key"</code> as stated <a href="http://www.passwordstore.org/" target="_blank" rel="noopener noreferrer">here</a></li>
<li>Got</li>
</ol>
<code>mkdir: created directory ‘/home/chichivica/.password-store/’ Password store initialized for foobar@email.com</code>
<ol start="5">
<li>Tried to add a simple password</li>
</ol>
<code>$ pass insert foo Enter password for foo: Retype password for foo:</code>
<ol start="6">
<li>And there is the problem</li>
</ol>
<code>gpg: A45A123C: There is no assurance this key belongs to the named user gpg: [stdin]: encryption failed: Unusable public key</code>
Could anyone give me some advice?

I have the following query.Could any one please suggest me a solution.

I&#39;m working on encryption and decryption of file for first time.

I have encrypted file through command prompt using the command:

    openssl enc -aes-256-cbc -in file.txt -out file.enc -k &quot;key value&quot; -iv &quot;iv value&quot;

I have to decrypt it programmatically. So I have written the program for it, but it is throwing the following error:

    ./exe_file enc_file_directory
    ...
    error: 06065064: digital envelope routines: EVP_DecryptFInal_ex: bad decrypt: evp_enc.c

----

The program below takes input as directory path and search for encrypted file &quot;.enc&quot; and try to decrypt it read into buffer.

Code:

	#include &lt;stdio.h&gt;
	#include &lt;string.h&gt;
	#include &lt;stdlib.h&gt;
	#include &lt;dirent.h&gt;
	#include &lt;sys/stat.h&gt;
	#include &lt;sys/types.h&gt;
	#include &lt;openssl/evp.h&gt;
	#include &lt;openssl/err.h&gt;
	#include &lt;openssl/conf.h&gt;
	#include &lt;libxml/globals.h&gt;

	void handleErrors(char *msg)
	{
	    {
        	ERR_print_errors_fp(stderr);
	        printf(&quot;%s&quot;, msg);
	        abort(); 
	    }
	}

	void freeMemory(char *mem)
	{
	    if (NULL != mem)
	    {
        	free(mem);
	        mem = NULL;
	    }
	}

	/* Function to decrypt the XML files */

	int decryptXML(unsigned char *indata, unsigned char *outdata, int fsize)
	{

	    int outlen1 = 0, outlen2 = 0;
    
	    unsigned char iv[] = &quot;b63e541bc9ece19a1339df4f8720dcc3&quot;;
	    unsigned char ckey[] = &quot;70bbc518c57acca2c2001694648c40ddaf19e3b4fe1376ad656de8887a0a5ec2&quot; ;
  
	    if (NULL == indata)
	    {
	        printf (&quot;input data is empty\n&quot;);
	        return 0;
	    }
    
	    if (0 &gt;= fsize)
	    {
	        printf (&quot;file size is zero\n&quot;);
        	return 0;
	    }

	    outdata = (char *) malloc (sizeof (char) * fsize * 2);

	    EVP_CIPHER_CTX ctx;
 
	    EVP_CIPHER_CTX_init(&amp;ctx);

	    if (! EVP_DecryptInit_ex (&amp;ctx, EVP_aes_256_cbc(), NULL, ckey, iv))
	    {
	        EVP_CIPHER_CTX_cleanup(&amp;ctx);
		handleErrors(&quot;DInit&quot;);
	    }

	    if (! EVP_DecryptUpdate (&amp;ctx, outdata, &amp;outlen1, indata, fsize))
	    {
        	EVP_CIPHER_CTX_cleanup(&amp;ctx);
	        handleErrors(&quot;DUpdate&quot;);
	    }

	    if (! EVP_DecryptFinal_ex (&amp;ctx, outdata + outlen1, &amp;outlen2))
	    {

	        EVP_CIPHER_CTX_cleanup(&amp;ctx);
        	handleErrors(&quot;DFinal&quot;);
	    }

	    EVP_CIPHER_CTX_cleanup(&amp;ctx);

	    return outlen1+outlen2;

	}

	int isDirectory(char *path)
	{
	    DIR *dir = NULL;
	    FILE *fin = NULL, *fout = NULL;
	    int enc_len = 0, dec_len = 0, fsize = 0, ksize = 0;
	    unsigned char *indata = NULL, *outdata = NULL;
	    char buff[BUFFER_SIZE], file_path[BUFFER_SIZE], cur_dir[BUFFER_SIZE];

	    struct dirent *in_dir;
	    struct stat s;

	    if (NULL == (dir = opendir(path)))
	    {
	        printf (&quot;ERROR: Failed to open the directory %s\n&quot;, path);
	        perror(&quot;cannot open.&quot;);
        	exit(1);
	    }

	    while (NULL != (in_dir = readdir(dir)))
	    {

	        if (!strcmp (in_dir-&gt;d_name, &quot;.&quot;) || !strcmp(in_dir-&gt;d_name, &quot;..&quot;))
        	    continue;

	        sprintf (buff, &quot;%s/%s&quot;, path, in_dir-&gt;d_name);
    
    	    if (-1 == stat(buff, &amp;s))
        	{
	            perror(&quot;stat&quot;);
        	    exit(1);
	        }
        
        	if (S_ISDIR(s.st_mode))
	        {
            
        	    isDirectory(buff);
	        }
        	else
        	{
	            strcpy(file_path, buff);
	
	            if (strstr(file_path, &quot;.enc&quot;))
        	    {
	            
        	        /* File to be decrypted */
                
                	fout = fopen(file_path,&quot;rb&quot;); 

	                fseek (fout, 0L, SEEK_END);
	                fsize = ftell(fout);
	                fseek (fout, 0L, SEEK_SET);

	                indata = (char*)malloc(fsize);

	                fread (indata, sizeof(char), fsize, fout);

	                if (NULL == fout)
        	        {
                	    perror(&quot;Cannot open enc file: &quot;);
	                    return 1;
        	        }
              

	                dec_len = decryptXML (indata, outdata, fsize);
        	        outdata[dec_len] = &#39;\0&#39;;
                	printf (&quot;%s\n&quot;, outdata);
	                fclose (fin);
        	        fclose (fout);

        	    }
	        }
	    }



	    closedir(dir);
	    freeMemory(outdata);
	    freeMemory(indata);

	    return 1; 
	}


	int main(int argc, char *argv[])
	{
	    int result;
    
	    if (argc != 2)
	    {
	        printf (&quot;Usage: &lt;executable&gt; path_of_the_files\n&quot;);
        	return -1;
	    }

	    ERR_load_crypto_strings();
	    OpenSSL_add_all_algorithms();
	    OPENSSL_config(NULL);

	    /* Checking for the directory existance */

	    result = isDirectory(argv[1]);

	    EVP_cleanup();
	    ERR_free_strings();

	    if (0 == result)
        	return 1;
	    else
 	       return 0;
	}

Thank you.

How to resolve the &quot;EVP_DecryptFInal_ex: bad decrypt&quot; during file decryption

&lt;p&gt;I am new in python programming and i am a bit confused. I try to get the bytes from a string to hash and encrypt but i got&lt;/p&gt; 

    b&#39;...&#39;

&lt;p&gt;b character in front of string just like the below example. Is any way avoid this?.Can anyone give a solution? Sorry for this silly question&lt;/p&gt;

    import hashlib
    
    text = &quot;my secret data&quot;
    pw_bytes = text.encode(&#39;utf-8&#39;)
    print(&#39;print&#39;,pw_bytes)
    m = hashlib.md5()
    m.update(pw_bytes)


OUTPUT:
   

     print b&#39;my secret data&#39;


Remove &#39;b&#39; character do in front of a string literal in Python 3

The mcrypt-extension is [deprecated][1] will be removed in PHP 7.2 according to the comment posted [here][2]. So I am looking for an alternative way to encrypt passwords.

Right now I am using something like

    mcrypt_encrypt(MCRYPT_RIJNDAEL_128, md5($key, true), $string, MCRYPT_MODE_CBC, $iv)

I need your opinion for the best/strongest way to encrypt passwords, the encrypted password should of course supported by PHP 7.xx and should also be decryptable because my customers do want to have an option to &#39;recover&#39; their passwords without generating a new one. 


  [1]: http://php.net/manual/en/migration71.deprecated.php#migration71.deprecated.ext-mcrypt
  [2]: https://bugs.php.net/bug.php?id=73734

mcrypt is deprecated, what is the alternative?

Cannot login to MySQL database after fresh install with root ID and empty/no password like other older MySQL versions do

What is the default root pasword for MySQL 5.7

I have installed ubuntu 16.04 server. Mysql server was installed by default in it. When I am trying to access the mysql with `mysql -u root -p`, I am unable to log in to mysql because I dont have the password. Is there any default password?

I have also tried with `--skip-grant-tables`, even this does not work. Even trying to log in with just `mysql -u root` is a failure.


Default password of mysql in ubuntu server 16.04

I&#39;ve been using this in order to edit the User Account Info:

    $this-&gt;validate($request, [
        &#39;password&#39; =&gt; &#39;min:6&#39;,
        &#39;password_confirmation&#39; =&gt; &#39;required_with:password|same:password|min:6&#39;
    ]);

This worked fine in a Laravel 5.2 Application but does not work in a 5.4 Application.

[![image][1]][1]

What&#39;s wrong here, or what is the correct way in order to only make the `password` required if either the `password` or `password_confirmation` field is set?


  [1]: https://i.stack.imgur.com/8Hhd6.png

Laravel Password &amp; Password_Confirmation Validation

I want to create a new user in MySQL with the syntax:

    create user &#39;demo&#39;@&#39;localhost&#39; identified by &#39;password&#39;;

But it returns an error: 

&gt; Your password does not satisfy the current policy requirements.

I have tried many passwords but they don&#39;t work. How can I fix this?

Your password does not satisfy the current policy requirements

Would it be possible for the GPG password to be saved, so that I am not prompted for the passphrase everytime I make a git commit?

Remember GPG password when signing git commits

I just started using git and I install git and gpg via homebrew.
For some reason, I get this error when i do `git commit`
I looked at so many other stackoverflow questions regarding this topic and none of them worked for me.
How can I fix this error so that I can upload successfully. 

    error: gpg failed to sign the data
    fatal: failed to write commit object


Git error - gpg failed to sign data

I installed GPG from brew.

    brew install gpg

It is gnupg2-2.0.30_2.

When I commit, I do get a error message:

    You need a passphrase to unlock the secret key for
    user: &quot;Max Mustermann (mycomment) &lt;mm@test.de&gt;&quot;
    2048-bit RSA key, ID 1111AAAA, created 2017-01-05 
    
    error: gpg failed to sign the data
    fatal: failed to write commit object

I used the command:

    gpg --list-secret-keys | grep ^sec

and it gives me back:

    sec   2048R/1111AAAA 2017-01-05

Then I used this command:

    git config --global user.signingkey 1111AAAA

commit gives me back the same error message.

How can I solve this problem?


git - gpg onto mac osx: error: gpg failed to sign the data

I am having a problem while trying to decrypt some keys using GPG. The following output is given to me:

    gpg: can&#39;t connect to the agent: IPC connect call failed

I already edited some files, pointed in this tutorial: https://michaelheap.com/gpg-cant-connect-to-the-agent-ipc-connect-call-failed/ but with no success.

Possible reasons for that?

Thanks in advance

gpg: can&#39;t connect to the agent: IPC connect call failed

I&#39;m automating my Docker installation. Something like this:

    if apt-key fingerprint 0EBFCD88 | grep &quot;Key fingerprint = 9DC8 5822 9FC7 DD38 854A E2D8 8D81 803C 0EBF CD88&quot; &gt; /dev/null
    then
      # proceed
    fi

This worked fine in older versions of `apt-key`, but recent versions have two issues:

1. A different output format: I can hack around that
2. A warning:

        Warning: apt-key output should not be parsed (stdout is not a terminal)

Clearly, I can hack around this as well, just redirect `stderr` to `/dev/null`. It just made me curious:

**How do these fine folks suggest I verify my key fingerprints?** Or am I getting this fundamentally wrong by wanting to automate it, does that defeat the point? (I think not, since I still manually lifted the expected fingerprint from the website, but feel free to tell me otherwise...)

Content Type	Original Author	Original Content on Stackoverflow
Question	Ivan Talalaev	View Question on Stackoverflow
Solution 1 - Encryption	Jon	View Answer on Stackoverflow

gnupg: There is no assurance this key belongs to the named user

Encryption Problem Overview

Encryption Solutions

Solution 1 - Encryption

How to get exception message in Python properly

Xcode 7.2 no matching provisioning profiles found

Attributions