Getting the array length of a 2D array in Java
JavaArraysMultidimensional ArrayJava Problem Overview
I need to get the length of a 2D array for both the row and column. I’ve successfully done this, using the following code:
public class MyClass {
public static void main(String args[])
{
int[][] test;
test = new int[5][10];
int row = test.length;
int col = test[0].length;
System.out.println(row);
System.out.println(col);
}
}
This prints out 5, 10 as expected.
Now take a look at this line:
int col = test[0].length;
Notice that I actually have to reference a particular row, in order to get the column length. To me, this seems incredibly ugly. Additionally, if the array was defined as:
test = new int[0][10];
Then the code would fail when trying to get the length. Is there a different (more intelligent) way to do this?
Java Solutions
Solution 1 - Java
Consider
public static void main(String[] args) {
int[][] foo = new int[][] {
new int[] { 1, 2, 3 },
new int[] { 1, 2, 3, 4},
};
System.out.println(foo.length); //2
System.out.println(foo[0].length); //3
System.out.println(foo[1].length); //4
}
Column lengths differ per row. If you're backing some data by a fixed size 2D array, then provide getters to the fixed values in a wrapper class.
Solution 2 - Java
A 2D array is not a rectangular grid. Or maybe better, there is no such thing as a 2D array in Java.
import java.util.Arrays;
public class Main {
public static void main(String args[]) {
int[][] test;
test = new int[5][];//'2D array'
for (int i=0;i<test.length;i++)
test[i] = new int[i];
System.out.println(Arrays.deepToString(test));
Object[] test2;
test2 = new Object[5];//array of objects
for (int i=0;i<test2.length;i++)
test2[i] = new int[i];//array is a object too
System.out.println(Arrays.deepToString(test2));
}
}
Outputs
[[], [0], [0, 0], [0, 0, 0], [0, 0, 0, 0]]
[[], [0], [0, 0], [0, 0, 0], [0, 0, 0, 0]]
The arrays test and test2 are (more or less) the same.
Solution 3 - Java
It was really hard to remember that
int numberOfColumns = arr.length;
int numberOfRows = arr[0].length;
Let's understand why this is so and how we can figure this out when we're given an array problem. From the below code we can see that rows = 4 and columns = 3:
int[][] arr = { {1, 1, 1, 1},
{2, 2, 2, 2},
{3, 3, 3, 3} };
arr has multiple arrays in it, and these arrays can be arranged in a vertical manner to get the number of columns. To get the number of rows, we need to access the first array and consider its length. In this case, we access [1, 1, 1, 1] and thus, the number of rows = 4. When you're given a problem where you can't see the array, you can visualize the array as a rectangle with n X m dimensions and conclude that we can get the number of rows by accessing the first array then its length. The other one (arr.length) is for the columns.
Solution 4 - Java
Java allows you to create "ragged arrays" where each "row" has different lengths. If you know you have a square array, you can use your code modified to protect against an empty array like this:
if (row > 0) col = test[0].length;
Solution 5 - Java
If you have this array:
String [][] example = {{{"Please!", "Thanks"}, {"Hello!", "Hey", "Hi!"}},
{{"Why?", "Where?", "When?", "Who?"}, {"Yes!"}}};
You can do this:
example.length;
= 2
example[0].length;
= 2
example[1].length;
= 2
example[0][1].length;
= 3
example[1][0].length;
= 4
Solution 6 - Java
There's not a cleaner way at the language level because not all multidimensional arrays are rectangular. Sometimes jagged (differing column lengths) arrays are necessary.
You could easy create your own class to abstract the functionality you need.
If you aren't limited to arrays, then perhaps some of the various collection classes would work as well, like a Multimap.
Solution 7 - Java
.length = number of rows / column length
[0].length = number of columns / row length
Solution 8 - Java
Example Array 1:
int arr[][] = { { 1, 3, 1, 5 },
{ 2, 2, 4, 1 },
{ 5, 0, 2, 3 },
{ 0, 6, 1, 2 } };
Example Array 2:
int arr[][] = { { 1, 3, 1 },
{ 2, 2, 4 },
{ 5, 0, 2 },
{ 0, 6, 1 } };
Below function will work for any Symmetric and Asymmetric Array Matrix
row_Count = arr.length
column_Count = arr[0].length
Solution 9 - Java
Try this following program for 2d array in java:
public class ArrayTwo2 {
public static void main(String[] args) throws IOException,NumberFormatException{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int[][] a;
int sum=0;
a=new int[3][2];
System.out.println("Enter array with 5 elements");
for(int i=0;i<a.length;i++)
{
for(int j=0;j<a[0].length;j++)
{
a[i][j]=Integer.parseInt(br.readLine());
}
}
for(int i=0;i<a.length;i++)
{
for(int j=0;j<a[0].length;j++)
{
System.out.print(a[i][j]+" ");
sum=sum+a[i][j];
}
System.out.println();
//System.out.println("Array Sum: "+sum);
sum=0;
}
}
}
Solution 10 - Java
import java.util.Arrays;
public class Main {
public static void main(String[] args)
{
double[][] test = { {100}, {200}, {300}, {400}, {500}, {600}, {700}, {800}, {900}, {1000}};
int [][] removeRow = { {0}, {1}, {3}, {4}, };
double[][] newTest = new double[test.length - removeRow.length][test[0].length];
for (int i = 0, j = 0, k = 0; i < test.length; i++) {
if (j < removeRow.length) {
if (i == removeRow[j][0]) {
j++;
continue;
}
}
newTest[k][0] = test[i][0];
k++;
}
System.out.println(Arrays.deepToString(newTest));
}
}
Solution 11 - Java
With Java 8, allow you doing something more elegant like this:
int[][] foo = new int[][] {
new int[] { 1, 2, 3 },
new int[] { 1, 2, 3, 4},
};
int length = Arrays.stream(array).max(Comparator.comparingInt(ArrayUtils::getLength)).get().length
Solution 12 - Java
public class Array_2D {
int arr[][];
public Array_2D() {
Random r=new Random(10);
arr = new int[5][10];
for(int i=0;i<5;i++)
{
for(int j=0;j<10;j++)
{
arr[i][j]=(int)r.nextInt(10);
}
}
}
public void display()
{
for(int i=0;i<5;i++)
{
for(int j=0;j<10;j++)
{
System.out.print(arr[i][j]+" ");
}
System.out.println("");
}
}
public static void main(String[] args) {
Array_2D s=new Array_2D();
s.display();
}
}