Getting request doesn't pass access control check: No 'Access-Control-Allow-Origin' header is present on the requested resource

JavascriptAjax

Javascript Problem Overview


I am trying to send an Ajax request to a Tomcat server from my application, but I am getting this error (my web app is running on Chrome):

>Response to preflight request doesn't pass access control check: No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'null' is therefore not allowed access. The response had HTTP status code 403.

I have tried using

'Access-Control-Allow-Origin' : 'http://localhost:8080/app',

but it didn't work.

My Ajax code:

 var arr = [1];
   $.ajax({ 
   url: 'http://localhost:8080/app',
   type: 'POST',
   contentType:'application/json',
   headers: {
   'Access-Control-Allow-Origin' : 'http://localhost:8080',
   },
       data: JSON.stringify(arr[0]),
       success: function(data){
        //On ajax success do this
             alert(data);
          }
     });

Javascript Solutions


Solution 1 - Javascript

Basically, to make a cross domain AJAX requests, the requested server should allow the cross origin sharing of resources (CORS). You can read more about that from here: http://www.html5rocks.com/en/tutorials/cors/

In your scenario, you are setting the headers in the client which in fact needs to be set into http://localhost:8080/app server side code.

If you are using PHP Apache server, then you will need to add following in your .htaccess file:

Header set Access-Control-Allow-Origin "*"

Solution 2 - Javascript

In case of Request to a REST Service:

You need to allow the CORS (cross origin sharing of resources) on the endpoint of your REST Service with Spring annotation:

@CrossOrigin(origins = "http://localhost:8080")

Very good tutorial: https://spring.io/guides/gs/rest-service-cors/

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionLabeoView Question on Stackoverflow
Solution 1 - JavascriptChandanView Answer on Stackoverflow
Solution 2 - JavascriptL01cView Answer on Stackoverflow