Getting only 1 decimal place

PythonRounding

Python Problem Overview

How do I convert 45.34531 to 45.3?

Python Solutions

Solution 1 - Python

Are you trying to represent it with only one digit:

print("{:.1f}".format(number)) # Python3
print "%.1f" % number          # Python2

or actually round off the other decimal places?

round(number,1)

or even round strictly down?

math.floor(number*10)/10

Solution 2 - Python

>>> "{:.1f}".format(45.34531)
'45.3'

Or use the builtin round:

>>> round(45.34531, 1)
45.299999999999997

Solution 3 - Python

round(number, 1)
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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionAlex GordonView Question on Stackoverflow
Solution 1 - PythonreletView Answer on Stackoverflow
Solution 2 - PythonmikuView Answer on Stackoverflow
Solution 3 - PythonDixonDView Answer on Stackoverflow