Getting Checkbutton state

PythonTkintertkinter.checkbutton

Python Problem Overview


How do I get the 'state' of a Tkinter Checkbutton? By 'state' I mean get whether or not it has a check mark in it or not.

Python Solutions


Solution 1 - Python

When you're creating it, it takes a variable keyword argument. Pass it an IntVar from Tkinter. Checking or unchecking the box will set that value contained by var to the corresponding boolean state. This can be accessed as var.get():

checked => var.get()

not checked => not var.get()

>>> root = Tkinter.Tk()
>>> var = Tkinter.IntVar()
>>> chk = Tkinter.Checkbutton(root, text='foo', variable=var)
>>> chk.pack(side=Tkinter.LEFT)
>>> var.get()  #unchecked
0
>>> var.get()  #checked
1

Solution 2 - Python

If you use the new* ttk module from tkinter, you can read and write checkbutton states without assigning variables.

import tkinter
from tkinter import ttk
tkwindow = tkinter.Tk()
chk = ttk.Checkbutton(tkwindow, text="foo")
chk.grid(column=0, row=0)

Notice that the new checkbox defaults to the "alternate", sometimes called "half-checked", state:

alternate

You can read the current state usinge the .state() method:

>>> print(chk.state())  # half-checked
('alternate',)
>>> print(chk.state())  # checked
('selected',)
>>> print(chk.state())  # not checked
()

To set the state in code:

chk.state(['selected'])  # check the checkbox
chk.state(['!selected']) # clear the checkbox
chk.state(['disabled'])  # disable the checkbox
chk.state(['!disabled','selected']) # enable the checkbox and put a check in it!

And here is a convenient way to check for a specific state:

chk.instate(['selected'])  # returns True if the box is checked

There are two tricky things I've found:

  1. The initial state is "alternate", and this state flag doesn't get cleared when adding a "selected" state flag. So, if you want to toggle your checkbutton in code, you'll first need to clear the "alternate" flag:

     chk.state(['!alternate'])
    
  2. If you disable/enable the checkbutton using

     chk.state(['disabled'])
     chk.state(['!disabled'])
    

    then everything works fine. But, if you use these common, alternate methods:

     chk.config(state=tk.DISABLED)
     chk.config(state=tk.NORMAL)
    

    then it reasserts the 'alternate' flag.

    This behavior doesn't happen if you assign a variable to the checkbutton, but then, if you wanted to assign a variable then this answer probably won't help you :)


* ttk became available in Python 2.7 (Tk 8.5). This question talks about the differences between the old standard widgets and the newer, "themed" ones.

Solution 3 - Python

bitsmack answer doesn't exactly agree with what I am seeing.

chk.state() returns a tuple which has two elements when selected: ('focus','selected')

import tkinter as tk
from tkinter import ttk
def p(event):
    st = ck.state()
    print (f'is tuple {type(st) is tuple}  {len(st)}-----------------------------------------')
    if 'selected' in st:
        print ('got selected')
    for i,pst in enumerate(st) :
        print(f'{i}, {pst}')

    
root = tk.Tk()
root.geometry('200x200+300+200')
root.grid_rowconfigure(0, weight = 1)

ck = ttk.Checkbutton(root,text = 'tryme')
ck.grid()
root.bind('<Return>',p)
root.mainloop()

yields this result:

is tuple True 1----------------------------------------

0, alternate is tuple True 2-----------------------------------------

got selected 0, focus 1, selected is tuple True 1-----------------------------------------

0, focus

So, to determine if the checkbox is selected:

if 'selected' in chk.state()

for alternate:

if 'alternate' in chk.state()

for not selected:

if not ('selected' in chk.state or 'alternate' in chk.state)

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionrectangletangleView Question on Stackoverflow
Solution 1 - PythonaaronasterlingView Answer on Stackoverflow
Solution 2 - PythonbitsmackView Answer on Stackoverflow
Solution 3 - PythonJim RobinsonView Answer on Stackoverflow