Get value from SimpleXMLElement Object
PhpSimplexmlPhp Problem Overview
I have something like this:
$url = "http://ws.geonames.org/findNearbyPostalCodes?country=pl&placename=";
$url .= rawurlencode($city[$i]);
$xml = simplexml_load_file($url);
echo $url."\n";
$cityCode[] = array(
'city' => $city[$i],
'lat' => $xml->code[0]->lat,
'lng' => $xml->code[0]->lng
);
It's supposed to download XML from geonames. If I do print_r($xml) I get :
SimpleXMLElement Object
(
[code] => Array
(
[0] => SimpleXMLElement Object
(
[postalcode] => 01-935
[name] => Warszawa
[countryCode] => PL
[lat] => 52.25
[lng] => 21.0
[adminCode1] => SimpleXMLElement Object
(
)
[adminName1] => Mazowieckie
[adminCode2] => SimpleXMLElement Object
(
)
[adminName2] => Warszawa
[adminCode3] => SimpleXMLElement Object
(
)
[adminName3] => SimpleXMLElement Object
(
)
[distance] => 0.0
)
I do as you can see $xml->code[0]->lat and it returns an object. How can i get the value?
Php Solutions
Solution 1 - Php
You have to cast simpleXML Object to a string.
$value = (string) $xml->code[0]->lat;
Solution 2 - Php
You can also use the magic method __toString()
$xml->code[0]->lat->__toString()
Solution 3 - Php
If you know that the value of the XML element is a float number (latitude, longitude, distance), you can use (float)
$value = (float) $xml->code[0]->lat;
Also, (int) for integer number:
$value = (int) $xml->code[0]->distance;
Solution 4 - Php
if you don't know the value of XML Element, you can use
$value = (string) $xml->code[0]->lat;
if (ctype_digit($value)) {
// the value is probably an integer because consists only of digits
}
It works when you need to determine if value is a number, because (string) will always return string and is_int($value) returns false
Solution 5 - Php
For me its easier to use arrays than objects,
So, I convert an Xml-Object,
$xml = simplexml_load_file('xml_file.xml');
$json_string = json_encode($xml);
$result_array = json_decode($json_string, TRUE);
Solution 6 - Php
This is the function that has always helped me convert the xml related values to array
function _xml2array ( $xmlObject, $out = array () ){
foreach ( (array) $xmlObject as $index => $node )
$out[$index] = ( is_object ( $node ) ) ? _xml2array ( $node ) : $node;
return $out;
}
Solution 7 - Php
try current($xml->code[0]->lat)
it returns element under current pointer of array, which is 0, so you will get value
Solution 8 - Php
you can use the '{}' to access you property, and then you can do as you wish. Save it or display the content.
$varName = $xml->{'key'};
From your example her's the code
$filePath = __DIR__ . 'Your path ';
$fileName = 'YourFilename.xml';
if (file_exists($filePath . $fileName)) {
$xml = simplexml_load_file($filePath . $fileName);
$mainNode = $xml->{'code'};
$cityArray = array();
foreach ($mainNode as $key => $data) {
$cityArray[..] = $mainNode[$key]['cityCode'];
....
}
}
Solution 9 - Php
header("Content-Type: text/html; charset=utf8");
$url = simplexml_load_file("http://URI.com");
foreach ($url->PRODUCT as $product) {
foreach($urun->attributes() as $k => $v) {
echo $k." : ".$v.' <br />';
}
echo '<hr/>';
}
Solution 10 - Php
you can convert array with this function
function xml2array($xml){
$arr = array();
foreach ($xml->children() as $r)
{
$t = array();
if(count($r->children()) == 0)
{
$arr[$r->getName()] = strval($r);
}
else
{
$arr[$r->getName()][] = xml2array($r);
}
}
return $arr;
}
Solution 11 - Php
$codeZero = null;
foreach ($xml->code->children() as $child) {
$codeZero = $child;
}
$lat = null;
foreach ($codeZero->children() as $child) {
if (isset($child->lat)) {
$lat = $child->lat;
}
}
Solution 12 - Php
foreach($xml->code as $vals )
{
unset($geonames);
$vals=(array)$vals;
foreach($vals as $key => $value)
{
$value=(array)$value;
$geonames[$key]=$value[0];
}
}
print_r($geonames);