GET URL parameter in PHP
PhpUrlRedirectPhp Problem Overview
I'm trying to pass a URL as a url parameter in php but when I try to get this parameter I get nothing
I'm using the following url form:
http://localhost/dispatch.php?link=www.google.com
I'm trying to get it through:
$_GET['link'];
But nothing returned. What is the problem?
Php Solutions
Solution 1 - Php
$_GET is not a function or language construct—it's just a variable (an array). Try:
<?php
echo $_GET['link'];
In particular, it's a superglobal: a built-in variable that's populated by PHP and is available in all scopes (you can use it from inside a function without the global keyword).
Since the variable might not exist, you could (and should) ensure your code does not trigger notices with:
<?php
if (isset($_GET['link'])) {
echo $_GET['link'];
} else {
// Fallback behaviour goes here
}
Alternatively, if you want to skip manual index checks and maybe add further validations you can use the filter extension:
<?php
echo filter_input(INPUT_GET, 'link', FILTER_SANITIZE_URL);
Last but not least, you can use the null coalescing operator (available since PHP/7.0) to handle missing parameters:
echo $_GET['link'] ?? 'Fallback value';
Solution 2 - Php
Please post your code,
<?php
echo $_GET['link'];
?>
or
<?php
echo $_REQUEST['link'];
?>
do work...
Solution 3 - Php
Use this:
$parameter = $_SERVER['QUERY_STRING'];
echo $parameter;
Or just use:
$parameter = $_GET['link'];
echo $parameter ;
Solution 4 - Php
To make sure you're always on the safe side, without getting all kinds of unwanted code insertion use FILTERS:
echo filter_input(INPUT_GET,"link",FILTER_SANITIZE_STRING);
More reading on php.net function filter_input, or check out the description of the different filters
Solution 5 - Php
The accepted answer is good. But if you have a scenario like this:
http://www.mydomain.me/index.php?state=California.php#Berkeley
You can treat the named anchor as a query string like this:
http://www.mydomain.me/index.php?state=California.php&city=Berkeley
Then, access it like this:
$Url = $_GET['state']."#".$_GET['city'];
Solution 6 - Php
$Query_String = explode("&", explode("?", $_SERVER['REQUEST_URI'])[1] );
var_dump($Query_String)
>Array ( [ 0] => link=www.google.com )
Solution 7 - Php
I was getting nothing for any $_GET["..."] (e.g print_r($_GET) gave an empty array) yet $_SERVER['REQUEST_URI'] showed stuff should be there. In the end it turned out that I was only getting to the web page because my .htaccess was redirecting it there (my 404 handler was the same .php file, and I had made a typo in the browser when testing).
Simply changing the name meant the same php code worked once the 404 redirection wasn't kicking in!
So there are ways $_GET can return nothing even though the php code may be correct.
Solution 8 - Php
This is what I done with the problem, and I went a step further and used that parameter to set a cookie, and then redirect to a clean URL.
if (isset ($_GET['referrer'])) {
$referrer = $_GET['referrer'];
// check db if refer exists
$shareLinkTrue = (new queries)->checkNewReferralExists($conn, $referrer);
// if exists, set cookie
if ($shareLinkTrue == 1) {
setcookie('_referrer_link', $referrer, 1,
isset($params['path']),
isset($params['domain']),
isset($params['secure']),
isset($params['httponly']));
header('Location: register.php');
}
}
Works perfect
Solution 9 - Php
As Alvaro said, $_GET is not a function but an array containing the parameters So you can retrieve one element from that array using
<?php
$link = $_GET['link'];
echo $link;
?>
Expected OP:
www.google.com
Solution 10 - Php
Whomever gets nothing back, I think he just has to enclose the result in html tags,
Like this:
<html>
<head></head>
<body>
<?php
echo $_GET['link'];
?>
<body>
</html>