Get total number of rows when using LIMIT?

Mysql

Mysql Problem Overview


> Possible Duplicate:
> Find total number of results in mySQL query with offset+limit

I have a very complex sql query which returns results that are paginated. The problem is to get the total row count before LIMIT I have to run the sql query twice. The first time without the limit clause to get the total row count. The sql query is really complex and I think they must be a better way of doing this without running the query twice.

Mysql Solutions


Solution 1 - Mysql

Luckily since MySQL 4.0.0 you can use SQL_CALC_FOUND_ROWS option in your query which will tell MySQL to count total number of rows disregarding LIMIT clause. You still need to execute a second query in order to retrieve row count, but it’s a simple query and not as complex as your query which retrieved the data. Usage is pretty simple. In you main query you need to add SQL_CALC_FOUND_ROWS option just after SELECT and in second query you need to use FOUND_ROWS() function to get total number of rows. Queries would look like this:

SELECT SQL_CALC_FOUND_ROWS name, email FROM users WHERE name LIKE 'a%' LIMIT 10;

SELECT FOUND_ROWS();

The only limitation is that you must call second query immediately after the first one because SQL_CALC_FOUND_ROWS does not save number of rows anywhere. Although this solution also requires two queries it’s much faster, as you execute the main query only once. You can read more about SQL_CALC_FOUND_ROWS and FOUND_ROWS() in MySQL docs.

EDIT: You should note that in most cases running the query twice is actually faster than SQL_CALC_FOUND_ROWS. see here

EDIT 2019: >The SQL_CALC_FOUND_ROWS query modifier and accompanying FOUND_ROWS() function are deprecated as of MySQL 8.0.17 and will be removed in a future MySQL version.

https://dev.mysql.com/doc/refman/8.0/en/information-functions.html#function_found-rows

It's recommended to use COUNT instead

SELECT * FROM tbl_name WHERE id > 100 LIMIT 10;
SELECT COUNT(*) WHERE id > 100;

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionFavourite OnwuemeneView Question on Stackoverflow
Solution 1 - MysqlFavourite OnwuemeneView Answer on Stackoverflow