Get the year from specified date php
PhpDatePhp Problem Overview
I have a date in this format 2068-06-15. I want to get the year from the date, using php functions. Could someone please suggest how this could be done.
Php Solutions
Solution 1 - Php
$date = DateTime::createFromFormat("Y-m-d", "2068-06-15");
echo $date->format("Y");
The DateTime class does not use an unix timestamp internally, so it han handle dates before 1970 or after 2038.
Solution 2 - Php
You can use the strtotime and date functions like this:
echo date('Y', strtotime('2068-06-15'));
Note however that PHP can handle year upto 2038
If your date is always in that format, you can also get the year like this:
$parts = explode('-', '2068-06-15');
echo $parts[0];
Solution 3 - Php
I would use this:
$parts = explode('-', '2068-06-15');
echo $parts[0];
It appears the date is coming from a source where it is always the same, much quicker this way using explode.
Solution 4 - Php
You can try strtotime() and date() functions for output in minimum code and using standard way.
echo date('Y', strtotime('2068-06-15'));
> output: 2068
echo date('y', strtotime('2068-06-15'));
> output: 68
Solution 5 - Php
public function getYear($pdate) {
$date = DateTime::createFromFormat("Y-m-d", $pdate);
return $date->format("Y");
}
public function getMonth($pdate) {
$date = DateTime::createFromFormat("Y-m-d", $pdate);
return $date->format("m");
}
public function getDay($pdate) {
$date = DateTime::createFromFormat("Y-m-d", $pdate);
return $date->format("d");
}
Solution 6 - Php
<?php
list($year) = explode("-", "2068-06-15");
echo $year;
?>
Solution 7 - Php
You can achieve your goal by using php date() & explode() functions:
$date = date("2068-06-15");
$date_arr = explode("-", $date);
$yr = $date_arr[0];
echo $yr;
That is it. Happy coding :)
Solution 8 - Php
Assuming you have the date as a string (sorry it was unclear from your question if that is the case) could split the string on the - characters like so:
$date = "2068-06-15";
$split_date = split("-", $date);
$year = $split_date[0];
Solution 9 - Php
$Y_date = split("-","2068-06-15");
$year = $Y_date[0];
You can use explode also
Solution 10 - Php
You wrote that format can change from YYYY-mm-dd to dd-mm-YYYY you can try to find year there
$parts = explode("-","2068-06-15");
for ($i = 0; $i < count($parts); $i++)
{
if(strlen($parts[$i]) == 4)
{
$year = $parts[$i];
break;
}
}