Get person's age in Ruby
Ruby on-RailsRubyRuby on-Rails Problem Overview
I'd like to get a person's age from its birthday. now - birthday / 365
doesn't work, because some years have 366 days. I came up with the following code:
now = Date.today
year = now.year - birth_date.year
if (date+year.year) > now
year = year - 1
end
Is there a more Ruby'ish way to calculate age?
Ruby on-Rails Solutions
Solution 1 - Ruby on-Rails
I know I'm late to the party here, but the accepted answer will break horribly when trying to work out the age of someone born on the 29th February on a leap year. This is because the call to birthday.to_date.change(:year => now.year)
creates an invalid date.
I used the following code instead:
require 'date'
def age(dob)
now = Time.now.utc.to_date
now.year - dob.year - ((now.month > dob.month || (now.month == dob.month && now.day >= dob.day)) ? 0 : 1)
end
Solution 2 - Ruby on-Rails
I've found this solution to work well and be readable for other people:
age = Date.today.year - birthday.year
age -= 1 if Date.today < birthday + age.years #for days before birthday
Easy and you don't need to worry about handling leap year and such.
Solution 3 - Ruby on-Rails
Use this:
def age
now = Time.now.utc.to_date
now.year - birthday.year - (birthday.to_date.change(:year => now.year) > now ? 1 : 0)
end
Solution 4 - Ruby on-Rails
One liner in Ruby on Rails (ActiveSupport). Handles leap years, leap seconds and all.
def age(birthday)
(Time.now.to_fs(:number).to_i - birthday.to_time.to_fs(:number).to_i)/10e9.to_i
end
Logic from here - https://stackoverflow.com/questions/9/how-do-i-calculate-someones-age-in-c/11942#11942
Assuming both dates are in same timezone, if not call utc()
before to_fs()
on both.
Solution 5 - Ruby on-Rails
(Date.today.strftime('%Y%m%d').to_i - dob.strftime('%Y%m%d').to_i) / 10000
Solution 6 - Ruby on-Rails
My suggestion:
def age(birthday)
((Time.now - birthday.to_time)/(60*60*24*365)).floor
end
The trick is that the minus operation with Time returns seconds
Solution 7 - Ruby on-Rails
The answers so far are kinda weird. Your original attempt was pretty close to the right way to do this:
birthday = DateTime.new(1900, 1, 1)
age = (DateTime.now - birthday) / 365.25 # or (1.year / 1.day)
You will get a fractional result, so feel free to convert the result to an integer with to_i
. This is a better solution because it correctly treats the date difference as a time period measured in days (or seconds in the case of the related Time class) since the event. Then a simple division by the number of days in a year gives you the age. When calculating age in years this way, as long as you retain the original DOB value, no allowance needs to be made for leap years.
Solution 8 - Ruby on-Rails
This answer is the best, upvote it instead.
I like @philnash's solution, but the conditional could be compacter. What that boolean expression does is comparing [month, day] pairs using lexicographic order, so one could just use ruby's string comparison instead:
def age(dob)
now = Date.today
now.year - dob.year - (now.strftime('%m%d') < dob.strftime('%m%d') ? 1 : 0)
end
Solution 9 - Ruby on-Rails
I like this one:
now = Date.current
age = now.year - dob.year
age -= 1 if now.yday < dob.yday
Solution 10 - Ruby on-Rails
This is a conversion of this answer (it's received a lot of votes):
# convert dates to yyyymmdd format
today = (Date.current.year * 100 + Date.current.month) * 100 + Date.today.day
dob = (dob.year * 100 + dob.month) * 100 + dob.day
# NOTE: could also use `.strftime('%Y%m%d').to_i`
# convert to age in years
years_old = (today - dob) / 10000
It's definitely unique in its approach but makes perfect sense when you realise what it does:
today = 20140702 # 2 July 2014
# person born this time last year is a 1 year old
years = (today - 20130702) / 10000
# person born a year ago tomorrow is still only 0 years old
years = (today - 20130703) / 10000
# person born today is 0
years = (today - 20140702) / 10000 # person born today is 0 years old
# person born in a leap year (eg. 1984) comparing with non-leap year
years = (20140228 - 19840229) / 10000 # 29 - a full year hasn't yet elapsed even though some leap year babies think it has, technically this is the last day of the previous year
years = (20140301 - 19840229) / 10000 # 30
# person born in a leap year (eg. 1984) comparing with leap year (eg. 2016)
years = (20160229 - 19840229) / 10000 # 32
Solution 11 - Ruby on-Rails
Because Ruby on Rails is tagged, the dotiw gem overrides the Rails built-in distance_of_times_in_words and provides distance_of_times_in_words_hash which can be used to determine the age. Leap years are handled fine for the years portion although be aware that Feb 29 does have an effect on the days portion that warrants understanding if that level of detail is needed. Also, if you don't like how dotiw changes the format of distance_of_time_in_words, use the :vague option to revert to the original format.
Add dotiw to the Gemfile:
gem 'dotiw'
On the command line:
bundle
Include the DateHelper in the appropriate model to gain access to distance_of_time_in_words and distance_of_time_in_words_hash. In this example the model is 'User' and the birthday field is 'birthday.
class User < ActiveRecord::Base
include ActionView::Helpers::DateHelper
Add this method to that same model.
def age
return nil if self.birthday.nil?
date_today = Date.today
age = distance_of_time_in_words_hash(date_today, self.birthday).fetch("years", 0)
age *= -1 if self.birthday > date_today
return age
end
Usage:
u = User.new("birthday(1i)" => "2011", "birthday(2i)" => "10", "birthday(3i)" => "23")
u.age
Solution 12 - Ruby on-Rails
I believe this is functionally equivalent to @philnash's answer, but IMO more easily understandable.
class BirthDate
def initialize(birth_date)
@birth_date = birth_date
@now = Time.now.utc.to_date
end
def time_ago_in_years
if today_is_before_birthday_in_same_year?
age_based_on_years - 1
else
age_based_on_years
end
end
private
def age_based_on_years
@now.year - @birth_date.year
end
def today_is_before_birthday_in_same_year?
(@now.month < @birth_date.month) || ((@now.month == @birth_date.month) && (@now.day < @birth_date.day))
end
end
Usage:
> BirthDate.new(Date.parse('1988-02-29')).time_ago_in_years
=> 31
Solution 13 - Ruby on-Rails
class User
def age
return unless birthdate
(Time.zone.now - birthdate.to_time) / 1.year
end
end
Can be checked with the following test:
RSpec.describe User do
describe "#age" do
context "when born 29 years ago" do
let!(:user) { create(:user, birthdate: 29.years.ago) }
it "has an age of 29" do
expect(user.age.round).to eq(29)
end
end
end
end
Solution 14 - Ruby on-Rails
The following seems to work (but I'd appreciate it if it was checked).
age = now.year - bday.year
age -= 1 if now.to_a[7] < bday.to_a[7]
Solution 15 - Ruby on-Rails
If you don't care about a day or two, this would be shorter and pretty self-explanitory.
(Time.now - Time.gm(1986, 1, 27).to_i).year - 1970
Solution 16 - Ruby on-Rails
Ok what about this:
def age
return unless dob
t = Date.today
age = t.year - dob.year
b4bday = t.strftime('%m%d') < dob.strftime('%m%d')
age - (b4bday ? 1 : 0)
end
This is assuming we are using rails, calling the age
method on a model, and the model has a date database column dob
. This is different from other answers because this method uses strings to determine if we are before this year's birthday.
For example, if dob
is 2004/2/28 and today
is 2014/2/28, age
will be 2014 - 2004
or 10
. The floats will be 0228
and 0229
. b4bday
will be "0228" < "0229"
or true
. Finally, we will subtract 1
from age
and get 9
.
This would be the normal way to compare the two times.
def age
return unless dob
t = Date.today
age = today.year - dob.year
b4bday = Date.new(2016, t.month, t.day) < Date.new(2016, dob.month, dob.day)
age - (b4bday ? 1 : 0)
end
This works the same, but the b4bday
line is too long. The 2016
year is also unnecessary. The string comparison at the beginning was the result.
You can also do this
Date::DATE_FORMATS[:md] = '%m%d'
def age
return unless dob
t = Date.today
age = t.year - dob.year
b4bday = t.to_s(:md) < dob.to_s(:md)
age - (b4bday ? 1 : 0)
end
If you aren't using rails, try this
def age(dob)
t = Time.now
age = t.year - dob.year
b4bday = t.strftime('%m%d') < dob.strftime('%m%d')
age - (b4bday ? 1 : 0)
end
ļļ¼
Solution 17 - Ruby on-Rails
I think it's alot better to do not count months, because you can get exact day of a year by using Time.zone.now.yday
.
def age
years = Time.zone.now.year - birthday.year
y_days = Time.zone.now.yday - birthday.yday
y_days < 0 ? years - 1 : years
end
Solution 18 - Ruby on-Rails
Came up with a Rails variation of this solution
def age(dob)
now = Date.today
age = now.year - dob.year
age -= 1 if dob > now.years_ago(age)
age
end
Solution 19 - Ruby on-Rails
DateHelper can be used to get years only
puts time_ago_in_words '1999-08-22'
> almost 20 years
Solution 20 - Ruby on-Rails
def computed_age
if birth_date.present?
current_time.year - birth_date.year - (age_by_bday || check_if_newborn ? 0 : 1)
else
age.presence || 0
end
end
private
def current_time
Time.now.utc.to_date
end
def age_by_bday
current_time.month > birth_date.month
end
def check_if_newborn
(current_time.month == birth_date.month && current_time.day >= birth_date.day)
end```
Solution 21 - Ruby on-Rails
def birthday(user)
today = Date.today
new = user.birthday.to_date.change(:year => today.year)
user = user.birthday
if Date.civil_to_jd(today.year, today.month, today.day) >= Date.civil_to_jd(new.year, new.month, new.day)
age = today.year - user.year
else
age = (today.year - user.year) -1
end
age
end
Solution 22 - Ruby on-Rails
Time.now.year - self.birthdate.year - (birthdate.to_date.change(:year => Time.now.year) > Time.now.to_date ? 1 : 0)
Solution 23 - Ruby on-Rails
To account for leap years (and assuming activesupport presence):
def age
return unless birthday
now = Time.now.utc.to_date
years = now.year - birthday.year
years - (birthday.years_since(years) > now ? 1 : 0)
end
years_since
will correctly modify the date to take into account non-leap years (when birthday is 02-29
).
Solution 24 - Ruby on-Rails
Here's my solution which also allows calculating the age at a specific date:
def age on = Date.today
(_ = on.year - birthday.year) - (on < birthday.since(_.years) ? 1 : 0)
end
Solution 25 - Ruby on-Rails
I had to deal with this too, but for months. Became way too complicated. The simplest way I could think of was:
def month_number(today = Date.today)
n = 0
while (dob >> n+1) <= today
n += 1
end
n
end
You could do the same with 12 months:
def age(today = Date.today)
n = 0
while (dob >> n+12) <= today
n += 1
end
n
end
This will use Date class to increment the month, which will deal with 28 days and leap year etc.