Get parent directory of running script
PhpDirectoryPhp Problem Overview
In PHP, what would be the cleanest way to get the parent directory of the current running script relative to the www root? Assume I have:
$_SERVER['SCRIPT_NAME'] == '/relative/path/to/script/index.php'
Or just:
$something_else == '/relative/path/to/script/'
And I need to get /relative/path/to/
with slashes properly inserted. What would you suggest? A one liner is preferred.
EDIT
I need to get a path relative to the www root, dirname(__FILE__)
gives me an absolute path in the filesystem so that won't work. $_SERVER['SCRIPT_NAME']
on the other hand 'starts' at the www root.
Php Solutions
Solution 1 - Php
If your script is located in /var/www/dir/index.php
then the following would return:
dirname(__FILE__); // /var/www/dir
or
dirname( dirname(__FILE__) ); // /var/www
Edit
This is a technique used in many frameworks to determine relative paths from the app_root.
File structure:
/var/ www/ index.php subdir/ library.php
index.php is my dispatcher/boostrap file that all requests are routed to:
define(ROOT_PATH, dirname(__FILE__) ); // /var/www
library.php is some file located an extra directory down and I need to determine the path relative to the app root (/var/www/).
$path_current = dirname( __FILE__ ); // /var/www/subdir
$path_relative = str_replace(ROOT_PATH, '', $path_current); // /subdir
There's probably a better way to calculate the relative path then str_replace()
but you get the idea.
Solution 2 - Php
As of PHP 5.3.0 you can use __DIR__
for this purpose.
> The directory of the file. If used inside an include, the directory of > the included file is returned. This is equivalent to > dirname(__ FILE__).
See PHP Magic constants.
C:\www>php --version
PHP 5.5.6 (cli) (built: Nov 12 2013 11:33:44)
Copyright (c) 1997-2013 The PHP Group
Zend Engine v2.5.0, Copyright (c) 1998-2013 Zend Technologies
C:\www>php -r "echo __DIR__;"
C:\www
Solution 3 - Php
To get the parentdir of the current script.
$parent_dir = dirname(__DIR__);
Solution 4 - Php
If I properly understood your question, supposing your running script is
/relative/path/to/script/index.php
This would give you the parent directory of your running script relative to the document www:
$parent_dir = dirname(dirname($_SERVER['SCRIPT_NAME'])) . '/';
//$parent_dir will be '/relative/path/to/'
If you want the parent directory of your running script relative to server root:
$parent_dir = dirname(dirname($_SERVER['SCRIPT_FILENAME'])) . '/';
//$parent_dir will be '/root/some/path/relative/path/to/'
Solution 5 - Php
Fugly, but this will do it:
substr($_SERVER['SCRIPT_NAME'], 0, strpos($_SERVER['SCRIPT_NAME'],basename($_SERVER['SCRIPT_NAME'])))
Solution 6 - Php
I Hope this will help you.
echo getcwd().'<br>'; // getcwd() will return current working directory
echo dirname(getcwd(),1).'<br>';
echo dirname(getcwd(),2).'<br>';
echo dirname(getcwd(),3).'<br>';
Output :
C:\wamp64\www\public_html\step
C:\wamp64\www\public_html
C:\wamp64\www
C:\wamp64
Solution 7 - Php
$dir = dirname($file) . DIRECTORY_SEPARATOR;
Solution 8 - Php
Here is what I use since I am not running > 5.2
function getCurrentOrParentDirectory($type='current')
{
if ($type == 'current') {
$path = dirname(__FILE__);
} else {
$path = dirname(dirname(__FILE__));
}
$position = strrpos($path, '/') + 1;
return substr($path, $position);
}
Double dirname with file as suggested by @mike b for the parent directory, and current directory is found by just using that syntax once.
Note this function only returns the NAME, slashes have to be added afterwards.
Solution 9 - Php
This is a function that I use. Created it once so I always have this functionality:
function getDir(){
$directory = dirname(__FILE__);
$directory = explode("/",$directory);
$findTarget = 0;
$targetPath = "";
foreach($directory as $dir){
if($findTarget == 1){
$targetPath = "".$targetPath."/".$dir."";
}
if($dir == "public_html"){
$findTarget = 1;
}
}
return "http://www.".$_SERVER['SERVER_NAME']."".$targetPath."";
}
Solution 10 - Php
Try this. Works on both windows or linux server..
str_replace('\','/',dirname(dirname(__FILE__)))
Solution 11 - Php
This is also a possible solution
$relative = '/relative/path/to/script/';
$absolute = __DIR__. '/../' .$relative;
Solution 12 - Php
I hope this will help
function get_directory(){
$s = empty($_SERVER["HTTPS"]) ? '' : ($_SERVER["HTTPS"] == "on") ? "s" : "";
$protocol = substr(strtolower($_SERVER["SERVER_PROTOCOL"]), 0, strpos(strtolower($_SERVER["SERVER_PROTOCOL"]), "/")) . $s;
$port = ($_SERVER["SERVER_PORT"] == "80") ? "" : (":".$_SERVER["SERVER_PORT"]);
return $protocol . "://" . $_SERVER['SERVER_NAME'] . dirname($_SERVER['PHP_SELF']);
}
define("ROOT_PATH", get_directory()."/" );
echo ROOT_PATH;
Solution 13 - Php
Got it myself, it's a bit kludgy but it works:
substr(dirname($_SERVER['SCRIPT_NAME']), 0, strrpos(dirname($_SERVER['SCRIPT_NAME']), '/') + 1)
So if I have /path/to/folder/index.php
, this results in /path/to/
.