Get name of property as a string

C#ReflectionProperties

C# Problem Overview


(See below solution I created using the answer I accepted)

I'm trying to improve the maintainability of some code involving reflection. The app has a .NET Remoting interface exposing (among other things) a method called Execute for accessing parts of the app not included in its published remote interface.

Here is how the app designates properties (a static one in this example) which are meant to be accessible via Execute:

RemoteMgr.ExposeProperty("SomeSecret", typeof(SomeClass), "SomeProperty");

So a remote user could call:

string response = remoteObject.Execute("SomeSecret");

and the app would use reflection to find SomeClass.SomeProperty and return its value as a string.

Unfortunately, if someone renames SomeProperty and forgets to change the 3rd parm of ExposeProperty(), it breaks this mechanism.

I need to the equivalent of:

SomeClass.SomeProperty.GetTheNameOfThisPropertyAsAString()

to use as the 3rd parm in ExposeProperty so refactoring tools would take care of renames.

Is there a way to do this?

Okay, here's what I ended up creating (based upon the answer I selected and the question he referenced):

// <summary>
// Get the name of a static or instance property from a property access lambda.
// </summary>
// <typeparam name="T">Type of the property</typeparam>
// <param name="propertyLambda">lambda expression of the form: '() => Class.Property' or '() => object.Property'</param>
// <returns>The name of the property</returns>
public string GetPropertyName<T>(Expression<Func<T>> propertyLambda)
{
    var me = propertyLambda.Body as MemberExpression;

    if (me == null)
    {
        throw new ArgumentException("You must pass a lambda of the form: '() => Class.Property' or '() => object.Property'");
    }

    return me.Member.Name;
 }

Usage:

// Static Property
string name = GetPropertyName(() => SomeClass.SomeProperty);

// Instance Property
string name = GetPropertyName(() => someObject.SomeProperty);

Now with this cool capability, it's time to simplify the ExposeProperty method. Polishing doorknobs is dangerous work...

C# Solutions


Solution 1 - C#

With C# 6.0, this is now a non-issue as you can do:

nameof(SomeProperty)

This expression is resolved at compile-time to "SomeProperty".

MSDN documentation of nameof.

Solution 2 - C#

Using GetMemberInfo from here: https://stackoverflow.com/questions/671968/retrieving-property-name-from-lambda-expression you can do something like this:

RemoteMgr.ExposeProperty(() => SomeClass.SomeProperty)

public class SomeClass
{
    public static string SomeProperty
    {
        get { return "Foo"; }
    }
}

public class RemoteMgr
{
    public static void ExposeProperty<T>(Expression<Func<T>> property)
    {
        var expression = GetMemberInfo(property);
        string path = string.Concat(expression.Member.DeclaringType.FullName,
            ".", expression.Member.Name);
        // Do ExposeProperty work here...
    }
}

public class Program
{
    public static void Main()
    {
        RemoteMgr.ExposeProperty("SomeSecret", () => SomeClass.SomeProperty);
    }
}

Solution 3 - C#

Okay, here's what I ended up creating (based upon the answer I selected and the question he referenced):

// <summary>
// Get the name of a static or instance property from a property access lambda.
// </summary>
// <typeparam name="T">Type of the property</typeparam>
// <param name="propertyLambda">lambda expression of the form: '() => Class.Property' or '() => object.Property'</param>
// <returns>The name of the property</returns>

public string GetPropertyName<T>(Expression<Func<T>> propertyLambda)
{
    var me = propertyLambda.Body as MemberExpression;

    if (me == null)
    {
        throw new ArgumentException("You must pass a lambda of the form: '() => Class.Property' or '() => object.Property'");
    }

    return me.Member.Name;
 }

Usage:

// Static Property
string name = GetPropertyName(() => SomeClass.SomeProperty);

// Instance Property
string name = GetPropertyName(() => someObject.SomeProperty);

Solution 4 - C#

There's a well-known hack to extract it from lambda expression (this is from the PropertyObserver class, by Josh Smith, in his MVVM foundation):

    private static string GetPropertyName<TPropertySource>
        (Expression<Func<TPropertySource, object>> expression)
    {
        var lambda = expression as LambdaExpression;
        MemberExpression memberExpression;
        if (lambda.Body is UnaryExpression)
        {
            var unaryExpression = lambda.Body as UnaryExpression;
            memberExpression = unaryExpression.Operand as MemberExpression;
        }
        else
        {
            memberExpression = lambda.Body as MemberExpression;
        }

        Debug.Assert(memberExpression != null, 
           "Please provide a lambda expression like 'n => n.PropertyName'");

        if (memberExpression != null)
        {
            var propertyInfo = memberExpression.Member as PropertyInfo;

            return propertyInfo.Name;
        }

        return null;
    }

Sorry, this was missing some context. This was part of a larger class where TPropertySource is the class containing the property. You could make the function generic in TPropertySource to extract it from the class. I recommend taking a look at the full code from the MVVM Foundation.

Solution 5 - C#

The PropertyInfo class should help you achieve this, if I understand correctly.

  1. Type.GetProperties() method

    PropertyInfo[] propInfos = typeof(ReflectedType).GetProperties();
    propInfos.ToList().ForEach(p => 
        Console.WriteLine(string.Format("Property name: {0}", p.Name));
    

Is this what you need?

Solution 6 - C#

You can use Reflection to obtain the actual names of the properties.

http://www.csharp-examples.net/reflection-property-names/

If you need a way to assign a "String Name" to a property, why don't you write an attribute that you can reflect over to get the string name?

[StringName("MyStringName")]
private string MyProperty
{
    get { ... }
}

Solution 7 - C#

I modified your solution to chain over multiple properties:

public static string GetPropertyName<T>(Expression<Func<T>> propertyLambda)
{
    MemberExpression me = propertyLambda.Body as MemberExpression;
    if (me == null)
    {
        throw new ArgumentException("You must pass a lambda of the form: '() => Class.Property' or '() => object.Property'");
    }

    string result = string.Empty;
    do
    {
        result = me.Member.Name + "." + result;
        me = me.Expression as MemberExpression;
    } while (me != null);

    result = result.Remove(result.Length - 1); // remove the trailing "."
    return result;
}

Usage:

string name = GetPropertyName(() => someObject.SomeProperty.SomeOtherProperty);
// returns "SomeProperty.SomeOtherProperty"

Solution 8 - C#

Old question, but another answer to this question is to create a static function in a helper class that uses the CallerMemberNameAttribute.

public static string GetPropertyName([CallerMemberName] String propertyName = null) {
  return propertyName;
}

And then use it like:

public string MyProperty {
  get { Console.WriteLine("{0} was called", GetPropertyName()); return _myProperty; }
}

Solution 9 - C#

Based on the answer which is already in the question and on this article: https://handcraftsman.wordpress.com/2008/11/11/how-to-get-c-property-names-without-magic-strings/ I am presenting my solution to this problem:

public static class PropertyNameHelper
{
    /// <summary>
    /// A static method to get the Propertyname String of a Property
    /// It eliminates the need for "Magic Strings" and assures type safety when renaming properties.
    /// See: http://stackoverflow.com/questions/2820660/get-name-of-property-as-a-string
    /// </summary>
    /// <example>
    /// // Static Property
    /// string name = PropertyNameHelper.GetPropertyName(() => SomeClass.SomeProperty);
    /// // Instance Property
    /// string name = PropertyNameHelper.GetPropertyName(() => someObject.SomeProperty);
    /// </example>
    /// <typeparam name="T"></typeparam>
    /// <param name="propertyLambda"></param>
    /// <returns></returns>
    public static string GetPropertyName<T>(Expression<Func<T>> propertyLambda)
    {
        var me = propertyLambda.Body as MemberExpression;

        if (me == null)
        {
            throw new ArgumentException("You must pass a lambda of the form: '() => Class.Property' or '() => object.Property'");
        }

        return me.Member.Name;
    }
    /// <summary>
    /// Another way to get Instance Property names as strings.
    /// With this method you don't need to create a instance first.
    /// See the example.
    /// See: https://handcraftsman.wordpress.com/2008/11/11/how-to-get-c-property-names-without-magic-strings/
    /// </summary>
    /// <example>
    /// string name = PropertyNameHelper((Firma f) => f.Firmenumsatz_Waehrung);
    /// </example>
    /// <typeparam name="T"></typeparam>
    /// <typeparam name="TReturn"></typeparam>
    /// <param name="expression"></param>
    /// <returns></returns>
    public static string GetPropertyName<T, TReturn>(Expression<Func<T, TReturn>> expression)
    {
        MemberExpression body = (MemberExpression)expression.Body;
        return body.Member.Name;
    }
}

And a Test which also shows the usage for instance and static properties:

[TestClass]
public class PropertyNameHelperTest
{
    private class TestClass
    {
        public static string StaticString { get; set; }
        public string InstanceString { get; set; }
    }

    [TestMethod]
    public void TestGetPropertyName()
    {
        Assert.AreEqual("StaticString", PropertyNameHelper.GetPropertyName(() => TestClass.StaticString));

        Assert.AreEqual("InstanceString", PropertyNameHelper.GetPropertyName((TestClass t) => t.InstanceString));
    }
}

Solution 10 - C#

You can use the StackTrace class to get the name of the current function, (or if you put the code in a function, then step down a level and get the calling function).

See http://msdn.microsoft.com/en-us/library/system.diagnostics.stacktrace(VS.71).aspx

Solution 11 - C#

I've been using this answer to great effect: https://stackoverflow.com/questions/2789504/get-the-property-as-a-string-from-an-expressionfunctmodel-tproperty/2789606#2789606

I realize I already answered this question a while back. The only advantage my other answer has is that it works for static properties. I find the syntax in this answer much more useful because you don't have to create a variable of the type you want to reflect.

Solution 12 - C#

I had some difficulty using the solutions already suggested for my specific use case, but figured it out eventually. I don't think my specific case is worthy of a new question, so I am posting my solution here for reference. (This is very closely related to the question and provides a solution for anyone else with a similar case to mine).

The code I ended up with looks like this:

public class HideableControl<T>: Control where T: class
{
    private string _propertyName;
    private PropertyInfo _propertyInfo;

    public string PropertyName
    {
        get { return _propertyName; }
        set
        {
            _propertyName = value;
            _propertyInfo = typeof(T).GetProperty(value);
        }
    }

    protected override bool GetIsVisible(IRenderContext context)
    {
        if (_propertyInfo == null)
            return false;

        var model = context.Get<T>();

        if (model == null)
            return false;

        return (bool)_propertyInfo.GetValue(model, null);
    }

    protected void SetIsVisibleProperty(Expression<Func<T, bool>> propertyLambda)
    {
        var expression = propertyLambda.Body as MemberExpression;
        if (expression == null)
            throw new ArgumentException("You must pass a lambda of the form: 'vm => vm.Property'");

        PropertyName = expression.Member.Name;
    }
}

public interface ICompanyViewModel
{
    string CompanyName { get; }
    bool IsVisible { get; }
}

public class CompanyControl: HideableControl<ICompanyViewModel>
{
    public CompanyControl()
    {
        SetIsVisibleProperty(vm => vm.IsVisible);
    }
}

The important part for me is that in the CompanyControl class the compiler will only allow me to choose a boolean property of ICompanyViewModel which makes it easier for other developers to get it right.

The main difference between my solution and the accepted answer is that my class is generic and I only want to match properties from the generic type that are boolean.

Solution 13 - C#

it's how I implemented it , the reason behind is if the class that you want to get the name from it's member is not static then you need to create an instanse of that and then get the member's name. so generic here comes to help

public static string GetName<TClass>(Expression<Func<TClass, object>> exp)
{
    MemberExpression body = exp.Body as MemberExpression;

    if (body == null)
    {
         UnaryExpression ubody = (UnaryExpression)exp.Body;
         body = ubody.Operand as MemberExpression;
    }

     return body.Member.Name;
}

the usage is like this

var label = ClassExtension.GetName<SomeClass>(x => x.Label); //x is refering to 'SomeClass'

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionJim CView Question on Stackoverflow
Solution 1 - C#James KoView Answer on Stackoverflow
Solution 2 - C#Daniel RenshawView Answer on Stackoverflow
Solution 3 - C#Jim CView Answer on Stackoverflow
Solution 4 - C#Dan BryantView Answer on Stackoverflow
Solution 5 - C#Will MarcouillerView Answer on Stackoverflow
Solution 6 - C#Robert HarveyView Answer on Stackoverflow
Solution 7 - C#hypehumanView Answer on Stackoverflow
Solution 8 - C#Jim PedidView Answer on Stackoverflow
Solution 9 - C#ThomasView Answer on Stackoverflow
Solution 10 - C#SprottyView Answer on Stackoverflow
Solution 11 - C#hypehumanView Answer on Stackoverflow
Solution 12 - C#bikeman868View Answer on Stackoverflow
Solution 13 - C#Mohammad Hossein AmriView Answer on Stackoverflow