Get Date in YYYYMMDD format in windows batch file

I need to get the date in YYYYMMDD format in batch file.

I am doing this using :

set mydate=%date:~6,4%%date:~3,2%%date:~0,2%
echo %mydate%

I need it to be consistent across system, even on changing the time settings.

Please advise.

If, after reading the other questions and viewing the links mentioned in the comment sections, you still can't figure it out, read on.

First of all, where you're going wrong is the offset.

It should look more like this...

set mydate=%date:~10,4%%date:~6,2%/%date:~4,2%
echo %mydate%

If the date was Tue 12/02/2013 then it would display it as 2013/02/12.

To remove the slashes, the code would look more like

set mydate=%date:~10,4%%date:~7,2%%date:~4,2%
echo %mydate%

which would output 20130212

And a hint for doing it in the future, if mydate equals something like %date:~10,4%%date:~7,2% or the like, you probably forgot a tilde (~).

You can try this ! This should work on windows machines.

for /F "usebackq tokens=1,2,3 delims=-" %%I IN (`echo %date%`) do echo "%%I" "%%J" "%%K"