Get current directory name (without full path) in a Bash script
BashShellBash Problem Overview
How would I get just the current working directory name in a bash script, or even better, just a terminal command.
pwd gives the full path of the current working directory, e.g. /opt/local/bin but I only want bin
Bash Solutions
Solution 1 - Bash
No need for basename, and especially no need for a subshell running pwd (which http://mywiki.wooledge.org/SubShell">adds an extra, and expensive, fork operation); the shell can do this internally using http://www.gnu.org/software/bash/manual/html_node/Shell-Parameter-Expansion.html">parameter expansion:
result=${PWD##*/} # to assign to a variable
printf '%s\n' "${PWD##*/}" # to print to stdout
# ...more robust than echo for unusual names
# (consider a directory named -e or -n)
printf '%q\n' "${PWD##*/}" # to print to stdout, quoted for use as shell input
# ...useful to make hidden characters readable.
Note that if you're applying this technique in other circumstances (not PWD, but some other variable holding a directory name), you might need to trim any trailing slashes. The below uses bash's extglob support to work even with multiple trailing slashes:
dirname=/path/to/somewhere//
shopt -s extglob # enable +(...) glob syntax
result=${dirname%%+(/)} # trim however many trailing slashes exist
result=${result##*/} # remove everything before the last / that still remains
printf '%s\n' "$result"
Alternatively, without extglob:
dirname="/path/to/somewhere//"
result="${dirname%"${dirname##*[!/]}"}" # extglob-free multi-trailing-/ trim
result="${result##*/}" # remove everything before the last /
Solution 2 - Bash
Use the basename program. For your case:
% basename "$PWD"
bin
Solution 3 - Bash
$ echo "${PWD##*/}"
Solution 4 - Bash
You can use a combination of pwd and basename. E.g.
#!/bin/bash
CURRENT=`pwd`
BASENAME=`basename "$CURRENT"`
echo "$BASENAME"
exit;
Solution 5 - Bash
Use:
basename "$PWD"
OR
IFS=/
var=($PWD)
echo ${var[-1]}
Turn the Internal Filename Separator (IFS) back to space.
IFS=
There is one space after the IFS.
Solution 6 - Bash
How about grep:
pwd | grep -o '[^/]*$'
Solution 7 - Bash
basename $(pwd)
or
echo "$(basename $(pwd))"
Solution 8 - Bash
This thread is great! Here is one more flavor:
pwd | awk -F / '{print $NF}'
Solution 9 - Bash
I like the selected answer (Charles Duffy), but be careful if you are in a symlinked dir and you want the name of the target dir. Unfortunately I don't think it can be done in a single parameter expansion expression, perhaps I'm mistaken. This should work:
target_PWD=$(readlink -f .)
echo ${target_PWD##*/}
To see this, an experiment:
cd foo
ln -s . bar
echo ${PWD##*/}
reports "bar"
DIRNAME
To show the leading directories of a path (without incurring a fork-exec of /usr/bin/dirname):
echo ${target_PWD%/*}
This will e.g. transform foo/bar/baz -> foo/bar
Solution 10 - Bash
echo "$PWD" | sed 's!.*/!!'
If you are using Bourne shell or ${PWD##*/} is not available.
Solution 11 - Bash
Surprisingly, no one mentioned this alternative that uses only built-in bash commands:
i="$IFS";IFS='/';set -f;p=($PWD);set +f;IFS="$i";echo "${p[-1]}"
As an added bonus you can easily obtain the name of the parent directory with:
[ "${#p[@]}" -gt 1 ] && echo "${p[-2]}"
These will work on Bash 4.3-alpha or newer.
Solution 12 - Bash
There are a lots way of doing that I particularly liked Charles way because it avoid a new process, but before know this I solved it with awk
pwd | awk -F/ '{print $NF}'
Solution 13 - Bash
For the find jockeys out there like me:
find $PWD -maxdepth 0 -printf "%f\n"
Solution 14 - Bash
i usually use this in sh scripts
SCRIPTSRC=`readlink -f "$0" || echo "$0"`
RUN_PATH=`dirname "${SCRIPTSRC}" || echo .`
echo "Running from ${RUN_PATH}"
...
cd ${RUN_PATH}/subfolder
you can use this to automate things ...
Solution 15 - Bash
Just use:
pwd | xargs basename
or
basename "`pwd`"
Solution 16 - Bash
Below grep with regex is also working,
>pwd | grep -o "\w*-*$"
Solution 17 - Bash
If you want to see only the current directory in the bash prompt region, you can edit .bashrc file in ~. Change \w to \W in the line:
PS1='${debian_chroot:+($debian_chroot)}\[\033[01;32m\]\u@\h\[\033[00m\]:\[\033[01;34m\]\w\[\033[00m\]\$ '
Run source ~/.bashrc and it will only display the directory name in the prompt region.
Ref: https://superuser.com/questions/60555/show-only-current-directory-name-not-full-path-on-bash-prompt
Solution 18 - Bash
I strongly prefer using gbasename, which is part of GNU coreutils.
Solution 19 - Bash
You can use the basename utility which deletes any prefix ending in / and the suffix (if present in string) from string, and prints the result on the standard output.
$basename <path-of-directory>
Solution 20 - Bash
The following commands will result in printing your current working directory in a bash script.
pushd .
CURRENT_DIR="`cd $1; pwd`"
popd
echo $CURRENT_DIR
Solution 21 - Bash
Just remove any character until a / (or \, if you're on Windows). As the match is gonna be made greedy it will remove everything until the last /:
pwd | sed 's/.*\///g'
In your case the result is as expected:
λ a='/opt/local/bin'
λ echo $a | sed 's/.*\///g'
bin