Generate array of all letters and digits
RubyRuby Problem Overview
Using ruby, is it possible to make an array of each letter in the alphabet and 0-9 easily?
Ruby Solutions
Solution 1 - Ruby
[*('a'..'z'), *('0'..'9')] # doesn't work in Ruby 1.8
or
('a'..'z').to_a + ('0'..'9').to_a
or
(0...36).map{ |i| i.to_s 36 }
(the Integer#to_s
method converts a number to a string representing it in a desired numeral system)
Solution 2 - Ruby
for letters or numbers you can form ranges and iterate over them. try this to get a general idea:
("a".."z").each { |letter| p letter }
to get an array out of it, just try the following:
("a".."z").to_a
Solution 3 - Ruby
You can also do it this way:
'a'.upto('z').to_a + 0.upto(9).to_a
Solution 4 - Ruby
Try this:
alphabet_array = [*'a'..'z', *'A'..'Z', *'0'..'9']
Or as string:
alphabet_string = alphabet_array.join
Solution 5 - Ruby
myarr = [*?a..?z] #generates an array of strings for each letter a to z
myarr = [*?a..?z] + [*?0..?9] # array of strings a-z and 0-9
Solution 6 - Ruby
You can just do this:
("0".."Z").map { |i| i }
Solution 7 - Ruby
letters = *('a'..'z')
=> ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]