Generate a random letter in Python
PythonRandomPython 3.xPython Problem Overview
Is there a way to generate random letters in Python (like random.randint but for letters)? The range functionality of random.randint would be nice but having a generator that just outputs a random letter would be better than nothing.
Python Solutions
Solution 1 - Python
Simple:
>>> import string
>>> string.ascii_letters
'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
>>> import random
>>> random.choice(string.ascii_letters)
'j'
string.ascii_letters
returns a string containing the lower case and upper case letters according to the current locale.
random.choice
returns a single, random element from a sequence.
Solution 2 - Python
>>> import random
>>> import string
>>> random.choice(string.ascii_letters)
'g'
Solution 3 - Python
>>>def random_char(y):
return ''.join(random.choice(string.ascii_letters) for x in range(y))
>>>print (random_char(5))
>>>fxkea
to generate y number of random characters
Solution 4 - Python
>>> import random
>>> import string
>>> random.choice(string.ascii_lowercase)
'b'
Solution 5 - Python
You can use this to get one or more random letter(s)
import random
import string
random.seed(10)
letters = string.ascii_lowercase
rand_letters = random.choices(letters,k=5) # where k is the number of required rand_letters
print(rand_letters)
['o', 'l', 'p', 'f', 'v']
Solution 6 - Python
Another way, for completeness:
>>> chr(random.randrange(97, 97 + 26))
Use the fact that ascii
'a' is 97, and there are 26 letters in the alphabet.
When determining the upper and lower bound of the random.randrange()
function call, remember that random.randrange()
is exclusive on its upper bound, meaning it will only ever generate an integer up to 1 unit less that the provided value.
Solution 7 - Python
You can just make a list:
import random
list1=['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']
b=random.randint(0,7)
print(list1[b])
Solution 8 - Python
def randchar(a, b):
return chr(random.randint(ord(a), ord(b)))
Solution 9 - Python
import random
def guess_letter():
return random.choice('abcdefghijklmnopqrstuvwxyz')
Solution 10 - Python
This doesn't use any fancy modules but works fine:
''.join(chr(random.randrange(65,90)) for i in range(10))
Solution 11 - Python
import random
def Random_Alpha():
l = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
return l[random.randint(0,25)]
print(Random_Alpha())
Solution 12 - Python
You can use
map(lambda a : chr(a), np.random.randint(low=65, high=90, size=4))
Solution 13 - Python
#*A handy python password generator*
import random
letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
numbers = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
symbols = ['!', '#', '$', '%', '&', '(', ')', '*', '+']
print("Welcome to the Python Password Generator!")
l= int(input("How many letters would you like in your password?\n"))
s = int(input(f"How many symbols would you like?\n"))
n = int(input(f"How many numbers would you like?\n"))
sequence = random.sample(letters,l)
num = random.sample(numbers,n)
sym = random.sample(symbols,s)
sequence.extend(num)
sequence.extend(sym)
random.shuffle(sequence)
password = ''.join([str(elem) for elem in sequence])#listToStr
print(password)
Solution 14 - Python
import string
import random
KEY_LEN = 20
def base_str():
return (string.letters+string.digits)
def key_gen():
keylist = [random.choice(base_str()) for i in range(KEY_LEN)]
return ("".join(keylist))
You can get random strings like this:
g9CtUljUWD9wtk1z07iF
ndPbI1DDn6UvHSQoDMtd
klMFY3pTYNVWsNJ6cs34
Qgr7OEalfhXllcFDGh2l
Solution 15 - Python
def create_key(key_len):
key = ''
valid_characters_list = string.letters + string.digits
for i in range(key_len):
character = choice(valid_characters_list)
key = key + character
return key
def create_key_list(key_num):
keys = []
for i in range(key_num):
key = create_key(key_len)
if key not in keys:
keys.append(key)
return keys
Solution 16 - Python
All previous answers are correct, if you are looking for random characters of various types (i.e. alphanumeric and special characters) then here is an script that I created to demonstrate various types of creating random functions, it has three functions one for numbers, alpha- characters and special characters. The script simply generates passwords and is just an example to demonstrate various ways of generating random characters.
import string
import random
import sys
#make sure it's 3.7 or above
print(sys.version)
def create_str(str_length):
return random.sample(string.ascii_letters, str_length)
def create_num(num_length):
digits = []
for i in range(num_length):
digits.append(str(random.randint(1, 100)))
return digits
def create_special_chars(special_length):
stringSpecial = []
for i in range(special_length):
stringSpecial.append(random.choice('!$%&()*+,-.:;<=>?@[]^_`{|}~'))
return stringSpecial
print("how many characters would you like to use ? (DO NOT USE LESS THAN 8)")
str_cnt = input()
print("how many digits would you like to use ? (DO NOT USE LESS THAN 2)")
num_cnt = input()
print("how many special characters would you like to use ? (DO NOT USE LESS THAN 1)")
s_chars_cnt = input()
password_values = create_str(int(str_cnt)) +create_num(int(num_cnt)) + create_special_chars(int(s_chars_cnt))
#shuffle/mix the values
random.shuffle(password_values)
print("generated password is: ")
print(''.join(password_values))
Result:
Solution 17 - Python
A summary and improvement of some of the answers.
import numpy as np
n = 5
[chr(i) for i in np.random.randint(ord('a'), ord('z') + 1, n)]
# ['b', 'f', 'r', 'w', 't']
Solution 18 - Python
well, this is my answer! It works well. Just put the number of random letters you want in 'number'... (Python 3)
import random
def key_gen():
keylist = random.choice('abcdefghijklmnopqrstuvwxyz')
return keylist
number = 0
list_item = ''
while number < 20:
number = number + 1
list_item = list_item + key_gen()
print(list_item)
Solution 19 - Python
import string
import random
def random_char(y):
return ''.join(random.choice(string.ascii_letters+string.digits+li) for x in range(y))
no=int(input("Enter the number of character for your password= "))
li = random.choice('!@#$%^*&( )_+}{')
print(random_char(no)+li)
Solution 20 - Python
My overly complicated piece of code:
import random
letter = (random.randint(1,26))
if letter == 1:
print ('a')
elif letter == 2:
print ('b')
elif letter == 3:
print ('c')
elif letter == 4:
print ('d')
elif letter == 5:
print ('e')
elif letter == 6:
print ('f')
elif letter == 7:
print ('g')
elif letter == 8:
print ('h')
elif letter == 9:
print ('i')
elif letter == 10:
print ('j')
elif letter == 11:
print ('k')
elif letter == 12:
print ('l')
elif letter == 13:
print ('m')
elif letter == 14:
print ('n')
elif letter == 15:
print ('o')
elif letter == 16:
print ('p')
elif letter == 17:
print ('q')
elif letter == 18:
print ('r')
elif letter == 19:
print ('s')
elif letter == 20:
print ('t')
elif letter == 21:
print ('u')
elif letter == 22:
print ('v')
elif letter == 23:
print ('w')
elif letter == 24:
print ('x')
elif letter == 25:
print ('y')
elif letter == 26:
print ('z')
It basically generates a random number out of 26 and then converts into its corresponding letter. This could defiantly be improved but I am only a beginner and I am proud of this piece of code.
Solution 21 - Python
Maybe this can help you:
import random
for a in range(64,90):
h = random.randint(64, a)
e += chr(h)
print e
Solution 22 - Python
Place a python on the keyboard and let him roll over the letters until you find your preferd random combo Just kidding!
import string #This was a design above but failed to print. I remodled it.
import random
irandom = random.choice(string.ascii_letters)
print irandom