Func<T>() vs Func<T>.Invoke()

C#InvokeFunc

C# Problem Overview

I'm curious about the differences between calling a Func<T> directly vs. using Invoke() on it. Is there a difference? Is the first syntactical sugar and calls Invoke() underneath anyway?

public T DoWork<T>(Func<T> method)
{
    return (T)method.Invoke();
}

vs.

public T DoWork<T>(Func<T> method)
{
    return (T)method();
}

Or am I on the wrong track entirely?

C# Solutions

Solution 1 - C#

There's no difference at all. The second is just a shorthand for Invoke, provided by the compiler. They compile to the same IL.

Solution 2 - C#

Invoke works well with new C# 6 null propagation operator, now you can do

T result = method?.Invoke();

instead of

T result = method != null ? method() : null;
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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestiontrisView Question on Stackoverflow
Solution 1 - C#Jon SkeetView Answer on Stackoverflow
Solution 2 - C#sanjuroView Answer on Stackoverflow