Form inside a table
HtmlFirebugHtml TableFormsHtml Problem Overview
I'm including some forms inside a HTML table to add new rows and update current rows. The problem that I'm getting is that when I inspect the forms in my dev tools, I see that the form elements are closed immediately after opening (inputs, etc are not included within the form).
As such, submitting a form fails to include the fields.
The table row and inputs are as follows:
<tr>
<form method="post" action="">
<td>
<input type="text" name="job_num">
</td>
<td>
<input type="text" name="desc">
</td>
</form>
</tr>
Any help would be great, thank you.
Html Solutions
Solution 1 - Html
A form is not allowed to be a child element of a table, tbody or tr. Attempting to put one there will tend to cause the browser to move the form to it appears after the table (while leaving its contents — table rows, table cells, inputs, etc — behind).
You can have an entire table inside a form. You can have a form inside a table cell. You cannot have part of a table inside a form.
Use one form around the entire table. Then either use the clicked submit button to determine which row to process (to be quick) or process every row (allowing bulk updates).
HTML 5 introduces the form attribute. This allows you to provide one form per row outside the table and then associate all the form control in a given row with one of those forms using its id.
Solution 2 - Html
Use the "form" attribute, if you want to save your markup:
<form method="GET" id="my_form"></form>
<table>
<tr>
<td>
<input type="text" name="company" form="my_form" />
<button type="button" form="my_form">ok</button>
</td>
</tr>
</table>
(*Form fields outside of the < form > tag)
Solution 3 - Html
If you want a "editable grid" i.e. a table like structure that allows you to make any of the rows a form, use CSS that mimics the TABLE tag's layout: display:table, display:table-row, and display:table-cell.
There is no need to wrap your whole table in a form and no need to create a separate form and table for each apparent row of your table.
Try this instead:
<style>
DIV.table
{
display:table;
}
FORM.tr, DIV.tr
{
display:table-row;
}
SPAN.td
{
display:table-cell;
}
</style>
...
<div class="table">
<form class="tr" method="post" action="blah.html">
<span class="td"><input type="text"/></span>
<span class="td"><input type="text"/></span>
</form>
<div class="tr">
<span class="td">(cell data)</span>
<span class="td">(cell data)</span>
</div>
...
</div>
The problem with wrapping the whole TABLE in a FORM is that any and all form elements will be sent on submit (maybe that is desired but probably not). This method allows you to define a form for each "row" and send only that row of data on submit.
The problem with wrapping a FORM tag around a TR tag (or TR around a FORM) is that it's invalid HTML. The FORM will still allow submit as usual but at this point the DOM is broken. Note: Try getting the child elements of your FORM or TR with JavaScript, it can lead to unexpected results.
Note that IE7 doesn't support these CSS table styles and IE8 will need a doctype declaration to get it into "standards" mode: (try this one or something equivalent)
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
Any other browser that supports display:table, display:table-row and display:table-cell should display your css data table the same as it would if you were using the TABLE, TR and TD tags. Most of them do.
Note that you can also mimic THEAD, TBODY, TFOOT by wrapping your row groups in another DIV with display: table-header-group, table-row-group and table-footer-group respectively.
NOTE: The only thing you cannot do with this method is colspan.
Check out this illustration: http://jsfiddle.net/ZRQPP/