Flask at first run: Do not use the development server in a production environment
PythonFlaskPython Problem Overview
I installed the Flask plugin in PyCharm Community Edition and I just have this simple code in my flask app:
from flask import Flask
app = Flask(__name__)
@app.route('/')
def index():
return '<h1>Hello!</h1>'
if __name__ == "__main__":
app.run(debug=True)
And I get this message:
WARNING: This is a development server. Do not use it in a production deployment.
Use a production WSGI server instead
* Restarting with stat
* Debugger is active!
* Debugger PIN: 123-456-789
* Running on http://127.0.0.1:5000/
Why am I getting this error when I run Flask?
A previous version of the message read "Do not use the development server in a production environment."
Python Solutions
Solution 1 - Python
For deploying an application to production, one option is to use Waitress, a production WSGI server.
Here is an example of using waitress in the code.
from flask import Flask
app = Flask(__name__)
@app.route("/")
def index():
return "<h1>Hello!</h1>"
if __name__ == "__main__":
from waitress import serve
serve(app, host="0.0.0.0", port=8080)
Running the application:
$ python hello.py
Waitress also provides a command line utility waitress-serve. To use that, you can modify the code to the following:
from flask import Flask
app = Flask(__name__)
@app.route("/")
def index():
return "<h1>Hello!</h1>"
def create_app():
return app
Then we can use waitress-serve as the following:
waitress-serve --port=8080 --call hello:create_app
And BTW, 8080 is the default port.
To validate the deployment, open a separate window:
% curl localhost:8080
<h1>Hello!</h1>%
Or directly in your browser <http://localhost:8080/>;.
Other alternatives to deploy your app include Gunicorn and uWSGI. For more details, please refer to the flask deploy doc.
Solution 2 - Python
Unless you tell the development server that it's running in development mode, it will assume you're using it in production and warn you not to. The development server is not intended for use in production. It is not designed to be particularly efficient, stable, or secure.
Enable development mode by setting the FLASK_ENV environment variable to development.
$ export FLASK_APP=example
$ export FLASK_ENV=development
$ flask run
If you're running in PyCharm (or probably any other IDE) you can set environment variables in the run configuration.
Development mode enables the debugger and reloader by default. If you don't want these, pass --no-debugger or --no-reloader to the run command.
That warning is just a warning though, it's not an error preventing your app from running. If your app isn't working, there's something else wrong with your code.
Solution 3 - Python
If for some people (like me earlier) the above answers don't work, I think the following answer would work (for Mac users I think) Enter the following commands to do flask run
$ export FLASK_APP = hello.py
$ export FLASK_ENV = development
$ flask run
Alternatively you can do the following (I haven't tried this but one resource online talks about it)
$ export FLASK_APP = hello.py
$ python -m flask run
source: For more
Solution 4 - Python
To avoid these messsages, inside the CLI (Command Line Interface), run these commands.
export FLASK_APP=app.py
export FLASK_ENV=development
export FLASK_DEBUG=0
flask run
Solution 5 - Python
This worked for me on windows:
$env:FLASK_APP="flask_project.py"
$env:FLASK_ENV="development"
flask run
flask_project.py is on the same path as my virtual environment.