Firebase Cloud Messaging - Handling logout

AndroidFirebaseFirebase Cloud-Messaging

Android Problem Overview


How do I handle situation, when user logs out of my application and I no longer want him to receive notifications to the device.

I tried

FirebaseInstanceId.getInstance().deleteToken(FirebaseInstanceId.getInstance().getId(), FirebaseMessaging.INSTANCE_ID_SCOPE)

But I still receive the notifications to my device's registration_id.

I also made sure that this is the token I should delete:

FirebaseInstanceId.getInstance().getToken(FirebaseInstanceId.getInstance().getId(), FirebaseMessaging.INSTANCE_ID_SCOPE)

or simply FirebaseInstanceId.getInstance().getToken()).

I also tried FirebaseInstanceId.getInstance().deleteInstanceId(), but then the next time I call FirebaseInstanceId.getInstance.getToken I receive null (it works on the second try).

I guess, after deleteInstanceId I could immediately call getToken() again, but it looks like a hack. And also there's this answer which states that it shouldn't be done, but it proposes deleting the token which apparently doesn't work.

So what is the right method to handle this?

Android Solutions


Solution 1 - Android

Okay. So I managed to do some testing and have concluded the following:

  1. deleteToken() is the counterpart of getToken(String, String), but not for getToken().

It only works if the Sender ID you are passing is a different Sender ID (not the same ID that can be seen in your google-services.json). For example, you want to allow a different Server to send to your app, you call getToken("THEIR_SENDER_ID", "FCM") to give them authorization to send to your app. This will return a different registration token that corresponds only to that specific sender.

In the future, if you chose to remove their authorization to send to your app, you'll then have to make use of deleteToken("THEIR_SENDER_ID", "FCM"). This will invalidate the corresponding token, and when the Sender attempts to send a message, as the intended behavior, they will receive a NotRegistered error.

  1. In order to delete the token for your own Sender, the correct handling is to use deleteInstanceId().

Special mentioning this answer by @Prince, specifically the code sample for helping me with this.

As @MichałK already doing in his post, after calling the deleteInstanceId(), getToken() should be called in order to send a request for a new token. However, you don't have to call it the second time. So long as onTokenRefresh() onNewToken() is implemented, it should automatically trigger providing you the new token.

For short, deleteInstanceId() > getToken() > check onTokenRefresh() onNewToken().

Note: Calling deleteInstanceId() will not only delete the token for your own app. It will delete all topic subscriptions and all other tokens associated with the app instance.


Are you positive you're calling deleteToken() properly? The value for audience should be (also seen from my answer that you linked) is "set to the app server's sender ID". You're passing the getId() value which is not the same as the Sender ID (it contains the app instance id value). Also, how are you sending the message (App Server or Notifications Console)?

getToken() and getToken(String, String) returns different tokens. See my answer here.

> I also tried FirebaseInstanceId.getInstance().deleteInstanceId(), but then the next time I call FirebaseInstanceId.getInstance.getToken I receive null (it works on the second try).

It's probably because the first time you're calling the getToken(), it's still being generated. It's just the intended behavior.

> I guess, after deleteInstanceId I could immediately call getToken() again, but it looks like a hack.

Not really. It's how you'll get the new generated (provided that it is already generated) token. So I think it's fine.

Solution 2 - Android

I did a brief research on what would be the most elegant solution to get back the full control (subscribe and unsubscribe to FCM) as before. Enable and disable the FCM after the user logged in or out.

Step 1. - Prevent auto initialization

Firebase now handle the InstanceID and everything else which need to generate a registration token. First of all you need to prevent auto initialization. Based on the official set-up documentation you need to add these meta-data values to your AndroidManifest.xml:

<?xml version="1.0" encoding="utf-8"?>
<application>

  <!-- FCM: Disable auto-init -->
  <meta-data android:name="firebase_messaging_auto_init_enabled"
             android:value="false" />
  <meta-data android:name="firebase_analytics_collection_enabled"
             android:value="false" />

  <!-- FCM: Receive token and messages -->
  <service android:name=".FCMService">
	<intent-filter>
		<action android:name="com.google.firebase.MESSAGING_EVENT"/>
	</intent-filter>
  </service>

</application>

Now you disabled the automatic token request process. At the same time you have an option to enable it again at runtime by code.

Step 2. - Implement enableFCM() and disableFCM() functions

If you enable the auto initialization again then you received a new token immediately, so this is a perfect way to implement the enableFCM() method. All subscribe information assigned to InstanceID, so when you delete it then initiate to unsubscribe all topic. On this way you able to implement disableFCM() method, just turn back off auto-init before you delete it.

public class FCMHandler {

	public void enableFCM(){
        // Enable FCM via enable Auto-init service which generate new token and receive in FCMService
        FirebaseMessaging.getInstance().setAutoInitEnabled(true);
    }

    public void disableFCM(){
        // Disable auto init
        FirebaseMessaging.getInstance().setAutoInitEnabled(false);
        new Thread(() -> {
            try {
                // Remove InstanceID initiate to unsubscribe all topic
                // TODO: May be a better way to use FirebaseMessaging.getInstance().unsubscribeFromTopic()
                FirebaseInstanceId.getInstance().deleteInstanceId();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }).start();
    }

}

Step 3. - FCMService implementation - token and message receiving

In the last step you need to receive the new token and send direct to your server. Other hand you'll receive your data message and just do it what you want.

public class FCMService extends FirebaseMessagingService {

    @Override
    public void onNewToken(String token) {
        super.onNewToken(token);
        // TODO: send your new token to the server
    }

    @Override
    public void onMessageReceived(RemoteMessage remoteMessage) {
        super.onMessageReceived(remoteMessage);
        String from = remoteMessage.getFrom();
        Map data = remoteMessage.getData();
        if (data != null) {
            // TODO: handle your message and data
            sendMessageNotification(message, messageId);
        }
    }

    private void sendMessageNotification(String msg, long messageId) {
        // TODO: show notification using NotificationCompat
    }
}

I think this solution is clear, simple and transparent. I tested in a production environment and it's works. I hope it was helpful.

Solution 3 - Android

I was working on the same problem, when I had done my logout() from my application. But the problem was that after logging out, I was still getting push notifications from Firebase. I tried to delete the Firebase token. But after deleting the token in my logout() method, it is null when I query for it in my login() method. After working 2 days I finally got a solution.

  1. In your logout() method, delete the Firebase token in the background because you can not delete Firebase token from the main thread

    new AsyncTask<Void,Void,Void>() {
        @Override
        protected Void doInBackground(Void... params) {
            try
            {
                FirebaseInstanceId.getInstance().deleteInstanceId();
            } catch (IOException e)
            {
                e.printStackTrace();
            }
            return null;
        }
    
        @Override
        protected void onPostExecute(Void result) {
            // Call your Activity where you want to land after log out
        }
    }.execute();
    
  2. In your login() method, generate the Firebase token again.

    new AsyncTask<Void,Void,Void>() {
        @Override
        protected Void doInBackground(Void... params) {
            String token = FirebaseInstanceId.getInstance().getToken();
            // Used to get firebase token until its null so it will save you from null pointer exeption
            while(token == null) {
                token = FirebaseInstanceId.getInstance().getToken();
            }
            return null;
        }
        @Override
        protected void onPostExecute(Void result) {
        }
    }.execute();
    

Solution 4 - Android

> Developers should never unregister the client app as a mechanism for > logout or for switching between users, for the following reasons: > > - A registration token isn't associated with a particular logged in user. If the client app unregisters and then re-registers, the app can > receive the same registration token or a different registration token. > - Unregistration and re-registration may each take up to five minutes to propagate. During this time messages may be rejected due to the > unregistered state, and messages may go to the wrong user. To make > sure that messages go to the intended user: > > - The app server can maintain a mapping between the current user and the registration token. > - The client app can then check to ensure that messages it receives match the logged in user.

this quote is from a deprecated google documentation

But there is reasons to believe this is still true - even if the documentation above is deprecated.

You can observe this here - check out how they do it in this codelab https://github.com/firebase/functions-samples/blob/master/fcm-notifications/functions/index.js

and here https://github.com/firebase/friendlychat-web/blob/master/cloud-functions/public/scripts/main.js

Solution 5 - Android

Since the getToken() is deprecated, use getInstanceId() to regenerate new token instead. It has same effect.

public static void resetInstanceId() {
    new Thread(new Runnable() {
        @Override
        public void run() {
            try {
                FirebaseInstanceId.getInstance().deleteInstanceId();
                FirebaseInstanceId.getInstance().getInstanceId();   
                Helper.log(TAG, "InstanceId removed and regenerated.");
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }).start();
}

Solution 6 - Android

Another handy way to clear the firebase token and regenerated a new one using FirebaseMessaging.getInstance()

fun clearFirebaseToken() {
    FirebaseMessaging.getInstance().apply {
        deleteToken().addOnCompleteListener { it ->
            Log.d("TAG++", "firebase token deleted ${it.result}")
            token.addOnCompleteListener {
                Log.d("TAG++", "firebase token generated ${it.result}")
                if (it.result != null) saveTokenGenerated(it.result!!)
            }
        }
    }
}

Solution 7 - Android

Just call deleteToken method on a background Thread upon Logout:

https://firebase.google.com/docs/reference/android/com/google/firebase/iid/FirebaseInstanceId.html#public-void-deletetoken-string-senderid,-string-scope

 FirebaseInstanceId.getInstance().deleteToken(getString(R.string.gcm_defaultSenderId), "FCM")

The first argument takes the SenderID as it is defined in your FireBaseConsole

enter image description here

It takes a few seconds to update - and after that, you will no longer get FCM notifications.

Solution 8 - Android

Use this methods. This is my solution, and I referred this at here When you sign-up, use initFirebaseMessage,. and when log-out or delete use removeFirebaseMessage().

    private fun removeFirebaseMessage(){
        CoroutineScope(Dispatchers.Default).launch {
            FirebaseMessaging.getInstance().isAutoInitEnabled = false
            FirebaseInstallations.getInstance().delete()
            FirebaseMessaging.getInstance().deleteToken()
        }
    }

    private fun initFirebaseMessage(){
        val fcm = FirebaseMessaging.getInstance()
        fcm.isAutoInitEnabled = true
        fcm.subscribeToTopic("all")
        fcm.subscribeToTopic("")
    }

Solution 9 - Android

I know I am late for the party. deleteInstanceId() should be called from the background thread since it's a blocking call. Just check the method deleteInstanceId() in FirebaseInstanceId() class.

@WorkerThread
public void deleteInstanceId() throws IOException {
    if (Looper.getMainLooper() == Looper.myLooper()) {
        throw new IOException("MAIN_THREAD");
    } else {
        String var1 = zzh();
        this.zza(this.zzal.deleteInstanceId(var1));
        this.zzl();
    }
}  

You can start an IntentService to delete the instance id and the data associated with it.

Solution 10 - Android

The firebase.iid package that contains FirebaseInstanceId is now deprecated. Auto-initialization has been migrated from Firebase Instance ID to Firebase Cloud Messaging. Also its behaviour has slighly changed. Before, a call to deleteInstanceId() would automatically generate a new token if auto-initialization was enabled. Now, the new token is only generated on the next app-start or if getToken() is called explicitly.

private suspend fun loginFCM() = withContext(Dispatchers.Default) {
    val fcm = FirebaseMessaging.getInstance()
    fcm.isAutoInitEnabled = true
    fcm.token.await()
}

private suspend fun logoutFCM() = withContext(Dispatchers.Default) {
    val fcm = FirebaseMessaging.getInstance()
    fcm.isAutoInitEnabled = false // To prevent a new token to be generated automatically in the next app-start (remove if you don't care)
    fcm.deleteToken().await()
}

If you want to logout completely from Firebase you can just delete the whole installation afterwards:

private suspend fun logoutFirebase() = withContext(Dispatchers.Default) {
    logoutFCM()
    val firebase = FirebaseInstallations.getInstance()
    firebase.delete().await()
}

Solution 11 - Android

To wrap it all up, use background thread to delete the instanceID, the next time you login keep an eye on the Firestore/Realtime DB (if you save your tokens there), they will refresh

public void Logout() {

        new Thread(){
            @Override
            public void run() {
                super.run();
                try {
                    FirebaseInstanceId.getInstance().deleteInstanceId();
                    FirebaseInstanceId.getInstance().getInstanceId();
                } catch (final IOException e) {
                    runOnUiThread(new Runnable() {
                        @Override
                        public void run() {
                            Toast.makeText(Flags.this, e.getMessage(), Toast.LENGTH_SHORT).show();
                        }
                    });
                }
            }
        }.start();
        FirebaseMessaging.getInstance().setAutoInitEnabled(false);
        FirebaseAuth.getInstance().signOut();
        SharedPreferences sharedPreferences = getDefaultSharedPreferences(Flags.this);
        SharedPreferences.Editor editor = sharedPreferences.edit();
        editor.clear();
        editor.apply();
        startActivity(new Intent(Flags.this, MainActivity.class));
        Flags.this.finish();
    }

Solution 12 - Android

This code below I used it and it helps me, and I used Kotlin coroutine instead of Thread(Runnable{}).start() because it less cost than creating a new thread object

 private fun logoutFromFCM() {
    GlobalScope.launch(Dispatchers.IO) {
        FirebaseInstallations.getInstance().delete()
        FirebaseMessaging.getInstance().deleteToken()

        FirebaseMessaging.getInstance().token.addOnCompleteListener(OnCompleteListener { task ->
            if (!task.isSuccessful) {
                Log.w(TAG, "Fetching FCM registration token failed", task.exception)
                return@OnCompleteListener
            }

            // Get new FCM registration token
            val token = task.result
            saveFirebaseToken(token)
            Log.w(TAG, "Token Updated - newToken> $token")
        })
    }
}

Solution 13 - Android

For many situations where the notifications requirements are simple, the issue of handling log out can be implemented much more easily. For example, in my case every user is subscribed to only two topics:

  • Global alerts topic
  • User specific topic defined as the users email (with replacement of @ with - because @ is not allowed in topic string)

For such simple scenarios simply unsubscribe from the unwanted topics on log out:

Future<void> signOut() async {
  messaging.unsubscribeFromTopic(emailToTopic(_firebaseAuth.currentUser.email));
  await _firebaseAuth.signOut();
}

And of course subscribe to topics only on successful log in or sign up:

Future<String> signIn({String email, String password}) async {
  try {
    await _firebaseAuth.signInWithEmailAndPassword(
        email: email, password: password);
    messaging.subscribeToTopic(emailToTopic(email));
    return "Signed in";
  } on FirebaseAuthException catch (e) {
    return e.message;
  }
}

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionMichał KlimczakView Question on Stackoverflow
Solution 1 - AndroidAL.View Answer on Stackoverflow
Solution 2 - AndroidJános Sicz-MesziárView Answer on Stackoverflow
Solution 3 - AndroidSunilView Answer on Stackoverflow
Solution 4 - AndroidDan AlboteanuView Answer on Stackoverflow
Solution 5 - AndroidReedy CreekerView Answer on Stackoverflow
Solution 6 - Androidvikas kumarView Answer on Stackoverflow
Solution 7 - AndroidGal RomView Answer on Stackoverflow
Solution 8 - AndroidjakchangView Answer on Stackoverflow
Solution 9 - AndroidSarweshkumar C RView Answer on Stackoverflow
Solution 10 - AndroidDavid MiguelView Answer on Stackoverflow
Solution 11 - AndroidZextroView Answer on Stackoverflow
Solution 12 - AndroidMohamedHarmoushView Answer on Stackoverflow
Solution 13 - AndroiddsalajView Answer on Stackoverflow