Find the column name which has the maximum value for each row

PythonPandasDataframeMax

Python Problem Overview


I have a DataFrame like this one:

In [7]:
frame.head()
Out[7]:
Communications and Search	Business	General	Lifestyle
0	0.745763	0.050847	0.118644	0.084746
0	0.333333	0.000000	0.583333	0.083333
0	0.617021	0.042553	0.297872	0.042553
0	0.435897	0.000000	0.410256	0.153846
0	0.358974	0.076923	0.410256	0.153846

In here, I want to ask how to get column name which has maximum value for each row, the desired output is like this:

In [7]:
    frame.head()
    Out[7]:
    Communications and Search	Business	General	Lifestyle   Max
    0	0.745763	0.050847	0.118644	0.084746           Communications 
    0	0.333333	0.000000	0.583333	0.083333           Business	 
    0	0.617021	0.042553	0.297872	0.042553           Communications 
    0	0.435897	0.000000	0.410256	0.153846           Communications 
    0	0.358974	0.076923	0.410256	0.153846           Business	

Python Solutions


Solution 1 - Python

You can use idxmax with axis=1 to find the column with the greatest value on each row:

>>> df.idxmax(axis=1)
0    Communications
1          Business
2    Communications
3    Communications
4          Business
dtype: object

To create the new column 'Max', use df['Max'] = df.idxmax(axis=1).

To find the row index at which the maximum value occurs in each column, use df.idxmax() (or equivalently df.idxmax(axis=0)).

Solution 2 - Python

And if you want to produce a column containing the name of the column with the maximum value but considering only a subset of columns then you use a variation of @ajcr's answer:

df['Max'] = df[['Communications','Business']].idxmax(axis=1)

Solution 3 - Python

You could apply on dataframe and get argmax() of each row via axis=1

In [144]: df.apply(lambda x: x.argmax(), axis=1)
Out[144]:
0    Communications
1          Business
2    Communications
3    Communications
4          Business
dtype: object

Here's a benchmark to compare how slow apply method is to idxmax() for len(df) ~ 20K

In [146]: %timeit df.apply(lambda x: x.argmax(), axis=1)
1 loops, best of 3: 479 ms per loop

In [147]: %timeit df.idxmax(axis=1)
10 loops, best of 3: 47.3 ms per loop

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionmarkov zainView Question on Stackoverflow
Solution 1 - PythonAlex RileyView Answer on Stackoverflow
Solution 2 - Pythonuser1718097View Answer on Stackoverflow
Solution 3 - PythonZeroView Answer on Stackoverflow