Find text string using jQuery?

JqueryText

Jquery Problem Overview


Say a web page has a string such as "I am a simple string" that I want to find. How would I go about this using JQuery?

Jquery Solutions


Solution 1 - Jquery

jQuery has the contains method. Here's a snippet for you:

<script type="text/javascript">
$(function() {
    var foundin = $('*:contains("I am a simple string")');
});
</script>

The selector above selects any element that contains the target string. The foundin will be a jQuery object that contains any matched element. See the API information at: https://api.jquery.com/contains-selector/

One thing to note with the '*' wildcard is that you'll get all elements, including your html an body elements, which you probably don't want. That's why most of the examples at jQuery and other places use $('div:contains("I am a simple string")')

Solution 2 - Jquery

Normally jQuery selectors do not search within the "text nodes" in the DOM. However if you use the .contents() function, text nodes will be included, then you can use the nodeType property to filter only the text nodes, and the nodeValue property to search the text string.

$('*', 'body')
.andSelf()
.contents()
.filter(function(){
return this.nodeType === 3;
})
.filter(function(){
// Only match when contains 'simple string' anywhere in the text
return this.nodeValue.indexOf('simple string') != -1;
})
.each(function(){
// Do something with this.nodeValue
});

Solution 3 - Jquery

This will select just the leaf elements that contain "I am a simple string".

$('*:contains("I am a simple string")').each(function(){
     if($(this).children().length < 1) 
          $(this).css("border","solid 2px red") });

Paste the following into the address bar to test it.

javascript: $('*:contains("I am a simple string")').each(function(){ if($(this).children().length < 1) $(this).css("border","solid 2px red") }); return false;

If you want to grab just "I am a simple string". First wrap the text in an element like so.

$('*:contains("I am a simple string")').each(function(){
     if($(this).children().length < 1) 
          $(this).html( 
               $(this).text().replace(
                    /"I am a simple string"/
                    ,'<span containsStringImLookingFor="true">"I am a simple string"</span>' 
               )  
           ) 
});

and then do this.

$('*[containsStringImLookingFor]').css("border","solid 2px red");

Solution 4 - Jquery

If you just want the node closest to the text you're searching for, you could use this:

$('*:contains("my text"):last');

This will even work if your HTML looks like this:

<p> blah blah <strong>my <em>text</em></strong></p>

Using the above selector will find the <strong> tag, since that's the last tag which contains that entire string.

Solution 5 - Jquery

Take a look at highlight (jQuery plugin).

Solution 6 - Jquery

Just adding to Tony Miller's answer as this got me 90% towards what I was looking for but still didn't work. Adding .length > 0; to the end of his code got my script working.

 $(function() {
    var foundin = $('*:contains("I am a simple string")').length > 0;
 });

Solution 7 - Jquery

this function should work. basically does a recursive lookup till we get a distinct list of leaf nodes.

function distinctNodes(search, element) {
    var d, e, ef;
    e = [];
    ef = [];

    if (element) {
        d = $(":contains(\""+ search + "\"):not(script)", element);
    }
    else {
            d = $(":contains(\""+ search + "\"):not(script)");
    }

    if (d.length == 1) {
            e.push(d[0]);
    }
    else {
        d.each(function () {
            var i, r = distinctNodes(search, this);
            if (r.length === 0) {
                e.push(this);
            }
            else {
                for (i = 0; i < r.length; ++i) {
                    e.push(r[i]);
                }
            }
        });
    }
    $.each(e, function () {
        for (var i = 0; i < ef.length; ++i) {
            if (this === ef[i]) return;
        }
        ef.push(this);
    });
    return ef;
}

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionKeith DoneganView Question on Stackoverflow
Solution 1 - JqueryTony MillerView Answer on Stackoverflow
Solution 2 - JqueryBarelyFitzView Answer on Stackoverflow
Solution 3 - JquerySlimView Answer on Stackoverflow
Solution 4 - JquerynickfView Answer on Stackoverflow
Solution 5 - JqueryChris DoggettView Answer on Stackoverflow
Solution 6 - JqueryPixelomoView Answer on Stackoverflow
Solution 7 - JquerydanatcofoView Answer on Stackoverflow