Find Nth occurrence of a character in a string

C#String

C# Problem Overview


I need help with creating a C# method that returns the index of the Nth occurrence of a character in a string.

For instance, the 3rd occurrence of the character 't' in the string "dtststxtu" is 5.
(Note that the string has 4 ts.)

C# Solutions


Solution 1 - C#

public int GetNthIndex(string s, char t, int n)
{
    int count = 0;
    for (int i = 0; i < s.Length; i++)
    {
        if (s[i] == t)
        {
            count++;
            if (count == n)
            {
                return i;
            }
        }
    }
    return -1;
}

That could be made a lot cleaner, and there are no checks on the input.

Solution 2 - C#

There is a minor bug in previous solution.

Here is some updated code:

s.TakeWhile(c => (n -= (c == t ? 1 : 0)) > 0).Count();

Solution 3 - C#

Here's another LINQ solution:

string input = "dtststx";
char searchChar = 't';
int occurrencePosition = 3; // third occurrence of the char
var result = input.Select((c, i) => new { Char = c, Index = i })
                  .Where(item => item.Char == searchChar)
                  .Skip(occurrencePosition - 1)
                  .FirstOrDefault();

if (result != null)
{
    Console.WriteLine("Position {0} of '{1}' occurs at index: {2}",
                        occurrencePosition, searchChar, result.Index);
}
else
{
    Console.WriteLine("Position {0} of '{1}' not found!",
                        occurrencePosition, searchChar);
}


Just for fun, here's a Regex solution. I saw some people initially used Regex to count, but when the question changed no updates were made. Here is how it can be done with Regex - again, just for fun. The traditional approach is best for simplicity.

string input = "dtststx";
char searchChar = 't';
int occurrencePosition = 3; // third occurrence of the char

Match match = Regex.Matches(input, Regex.Escape(searchChar.ToString()))
                   .Cast<Match>()
                   .Skip(occurrencePosition - 1)
                   .FirstOrDefault();
                   
if (match != null)
    Console.WriteLine("Index: " + match.Index);
else
    Console.WriteLine("Match not found!");

Solution 4 - C#

Here is a recursive implementation - as an extension method, mimicing the format of the framework method(s):

public static int IndexOfNth(
    this string input, string value, int startIndex, int nth)
{
    if (nth < 1)
        throw new NotSupportedException("Param 'nth' must be greater than 0!");
    if (nth == 1)
        return input.IndexOf(value, startIndex);
    
    return input.IndexOfNth(value, input.IndexOf(value, startIndex) + 1, --nth);
}

Also, here are some (MBUnit) unit tests that might help you (to prove it is correct):

[Test]
public void TestIndexOfNthWorksForNth1()
{
    const string input = "foo<br />bar<br />baz<br />";
    Assert.AreEqual(3, input.IndexOfNth("<br />", 0, 1));
}

[Test]
public void TestIndexOfNthWorksForNth2()
{
    const string input = "foo<br />whatthedeuce<br />kthxbai<br />";
    Assert.AreEqual(21, input.IndexOfNth("<br />", 0, 2));
}

[Test]
public void TestIndexOfNthWorksForNth3()
{
    const string input = "foo<br />whatthedeuce<br />kthxbai<br />";
    Assert.AreEqual(34, input.IndexOfNth("<br />", 0, 3));
}

Solution 5 - C#

Update: Index of Nth occurance one-liner:

int NthOccurence(string s, char t, int n)
{
    s.TakeWhile(c => n - (c == t)?1:0 > 0).Count();
}

Use these at your own risk. This looks like homework, so I left a few bugs in there for your to find:

int CountChars(string s, char t)
{
   int count = 0;
   foreach (char c in s)
      if (s.Equals(t)) count ++;
   return count;
}

.

int CountChars(string s, char t)
{
     return s.Length - s.Replace(t.ToString(), "").Length;
}

.

int CountChars(string s, char t)
{
    Regex r = new Regex("[\\" + t + "]");
    return r.Match(s).Count;
}

Solution 6 - C#

ranomore correctly commented that Joel Coehoorn's one-liner doesn't work.

Here is a two-liner that does work, a string extension method that returns the 0-based index of the nth occurrence of a character, or -1 if no nth occurrence exists:

public static class StringExtensions
{
    public static int NthIndexOf(this string s, char c, int n)
    {
        var takeCount = s.TakeWhile(x => (n -= (x == c ? 1 : 0)) > 0).Count();
        return takeCount == s.Length ? -1 : takeCount;
    }
}

Solution 7 - C#

Joel's answer is good (and I upvoted it). Here is a LINQ-based solution:

yourString.Where(c => c == 't').Count();

Solution 8 - C#

I add another answer that run pretty fast compared to others methods

private static int IndexOfNth(string str, char c, int nth, int startPosition = 0)
{
    int index = str.IndexOf(c, startPosition);
    if (index >= 0 && nth > 1)
    {
        return  IndexOfNth(str, c, nth - 1, index + 1);
    }

    return index;
}

Solution 9 - C#

Here is a fun way to do it

     int i = 0;
     string s="asdasdasd";
     int n = 3;
     s.Where(b => (b == 'd') && (i++ == n));
     return i;

Solution 10 - C#

public int GetNthOccurrenceOfChar(string s, char c, int occ)
{
    return String.Join(c.ToString(), s.Split(new char[] { c }, StringSplitOptions.None).Take(occ)).Length;
}

Solution 11 - C#

string result = "i am '[email protected]'"; // string

int in1 = result.IndexOf('\''); // get the index of first quote

int in2 = result.IndexOf('\'', in1 + 1); // get the index of second
 
string quoted_text = result.Substring(in1 + 1, in2 - in1); // get the string between quotes

Solution 12 - C#

Here's another, maybe simpler implementation of string IndexOfNth() with strings implementation.

Here's the string match version:

public static int IndexOfNth(this string source, string matchString, 
                             int charInstance, 
                             StringComparison stringComparison = StringComparison.CurrentCulture)
{
    if (string.IsNullOrEmpty(source))
        return -1;

    int lastPos = 0;
    int count = 0;
       
    while (count < charInstance )
    {
        var len = source.Length - lastPos;
        lastPos = source.IndexOf(matchString, lastPos,len,stringComparison);
        if (lastPos == -1)
            break;

        count++;
        if (count == charInstance)
            return lastPos;

        lastPos += matchString.Length;
    }
    return -1;
}

and the char match version:

public static int IndexOfNth(string source, char matchChar, int charInstance)        
{
    if (string.IsNullOrEmpty(source))
        return -1;

    if (charInstance < 1)
        return -1;

    int count = 0;
    for (int i = 0; i < source.Length; i++)
    {
        if (source[i] == matchChar)
        {
            count++;
            if (count == charInstance)                 
                return i;                 
        }
    }
    return -1;
}

I think for such a low level implementation you'd want to stay away from using LINQ, RegEx or recursion to reduce overhead.

Solution 13 - C#

you can do this work with Regular Expressions.

        string input = "dtststx";
        char searching_char = 't';
        int output = Regex.Matches(input, "["+ searching_char +"]")[2].Index;

best regard.

Solution 14 - C#

Since the built-in IndexOf function is already optimized for searching a character within a string, an even faster version would be (as extension method):

public static int NthIndexOf(this string input, char value, int n)
{
	if (n <= 0) throw new ArgumentOutOfRangeException("n", n, "n is less than zero.");

	int i = -1;
	do
	{
		i = input.IndexOf(value, i + 1);
		n--;
	}
	while (i != -1 && n > 0);

	return i;
}

Or to search from the end of the string using LastIndexOf:

public static int NthLastIndexOf(this string input, char value, int n)
{
	if (n <= 0) throw new ArgumentOutOfRangeException("n", n, "n is less than zero.");

	int i = input.Length;
	do
	{
		i = input.LastIndexOf(value, i - 1);
		n--;
	}
	while (i != -1 && n > 0);

	return i;
}

Searching for a string instead of a character is as simple as changing the parameter type from char to string and optionally add an overload to specify the StringComparison.

Solution 15 - C#

if your interested you can also create string extension methods like so:

     public static int Search(this string yourString, string yourMarker, int yourInst = 1, bool caseSensitive = true)
    {
        //returns the placement of a string in another string
        int num = 0;
        int currentInst = 0;
        //if optional argument, case sensitive is false convert string and marker to lowercase
        if (!caseSensitive) { yourString = yourString.ToLower(); yourMarker = yourMarker.ToLower(); }
        int myReturnValue = -1; //if nothing is found the returned integer is negative 1
        while ((num + yourMarker.Length) <= yourString.Length)
        {
            string testString = yourString.Substring(num, yourMarker.Length);

            if (testString == yourMarker)
            {
                currentInst++;
                if (currentInst == yourInst)
                {
                    myReturnValue = num;
                    break;
                }
            }
            num++;
        }           
       return myReturnValue;
    }

   public static int Search(this string yourString, char yourMarker, int yourInst = 1, bool caseSensitive = true)
    {
        //returns the placement of a string in another string
        int num = 0;
        int currentInst = 0;
        var charArray = yourString.ToArray<char>();
        int myReturnValue = -1;
        if (!caseSensitive)
        {
            yourString = yourString.ToLower();
            yourMarker = Char.ToLower(yourMarker);
        }
        while (num <= charArray.Length)
        {                
            if (charArray[num] == yourMarker)
            {
                currentInst++;
                if (currentInst == yourInst)
                {
                    myReturnValue = num;
                    break;
                }
            }
            num++;
        }
        return myReturnValue;
    }

Solution 16 - C#

Another RegEx-based solution (untested):

int NthIndexOf(string s, char t, int n) {
   if(n < 0) { throw new ArgumentException(); }
   if(n==1) { return s.IndexOf(t); }
   if(t=="") { return 0; }
   string et = RegEx.Escape(t);
   string pat = "(?<="
      + Microsoft.VisualBasic.StrDup(n-1, et + @"[.\n]*") + ")"
      + et;
   Match m = RegEx.Match(s, pat);
   return m.Success ? m.Index : -1;
}

This should be slightly more optimal than requiring RegEx to create a Matches collection, only to discard all but one match.

Solution 17 - C#

    public static int FindOccuranceOf(this string str,char @char, int occurance)
    {
       var result = str.Select((x, y) => new { Letter = x, Index = y })
            .Where(letter => letter.Letter == @char).ToList();
       if (occurence > result.Count || occurance <= 0)
       {
           throw new IndexOutOfRangeException("occurance");
       }
       return result[occurance-1].Index ;
    }

Solution 18 - C#

Hi all i have created two overload methods for finding nth occurrence of char and for text with less complexity without navigating through loop ,which increase performance of your application.

public static int NthIndexOf(string text, char searchChar, int nthindex)
{
   int index = -1;
   try
   {
      var takeCount = text.TakeWhile(x => (nthindex -= (x == searchChar ? 1 : 0)) > 0).Count();
      if (takeCount < text.Length) index = takeCount;
   }
   catch { }
   return index;
}
public static int NthIndexOf(string text, string searchText, int nthindex)
{
     int index = -1;
     try
     {
        Match m = Regex.Match(text, "((" + searchText + ").*?){" + nthindex + "}");
        if (m.Success) index = m.Groups[2].Captures[nthindex - 1].Index;
     }
     catch { }
     return index;
}

Solution 19 - C#

Marc Cals' LINQ Extended for generic.

   using System;
   using System.Collections.Generic;
   using System.Linq;

   namespace fNns
   {
       public class indexer<T> where T : IEquatable<T>
       {
           public T t { get; set; }
           public int index { get; set; }
       }
       public static class fN
       {
           public static indexer<T> findNth<T>(IEnumerable<T> tc, T t,
               int occurrencePosition) where T : IEquatable<T>
           {
               var result = tc.Select((ti, i) => new indexer<T> { t = ti, index = i })
                      .Where(item => item.t.Equals(t))
                      .Skip(occurrencePosition - 1)
                      .FirstOrDefault();
               return result;
           }
           public static indexer<T> findNthReverse<T>(IEnumerable<T> tc, T t,
       int occurrencePosition) where T : IEquatable<T>
           {
               var result = tc.Reverse<T>().Select((ti, i) => new indexer<T> {t = ti, index = i })
                      .Where(item => item.t.Equals(t))
                      .Skip(occurrencePosition - 1)
                      .FirstOrDefault();
               return result;
           }
       }
   }

Some tests.

   using System;
   using System.Collections.Generic;
   using NUnit.Framework;
   using Newtonsoft.Json;
   namespace FindNthNamespace.Tests
   {

       public class fNTests
       {
           [TestCase("pass", "dtststx", 't', 3, Result = "{\"t\":\"t\",\"index\":5}")]
           [TestCase("pass", new int[] { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
        0, 2, Result="{\"t\":0,\"index\":10}")]
           public string fNMethodTest<T>(string scenario, IEnumerable<T> tc, T t, int occurrencePosition) where T : IEquatable<T>
           {
               Console.WriteLine(scenario);
               return JsonConvert.SerializeObject(fNns.fN.findNth<T>(tc, t, occurrencePosition)).ToString();
           }

           [TestCase("pass", "dtststxx", 't', 3, Result = "{\"t\":\"t\",\"index\":6}")]
           [TestCase("pass", new int[] { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 },
        0, 2, Result = "{\"t\":0,\"index\":19}")]
           public string fNMethodTestReverse<T>(string scenario, IEnumerable<T> tc, T t, int occurrencePosition) where T : IEquatable<T>
           {
               Console.WriteLine(scenario);
               return JsonConvert.SerializeObject(fNns.fN.findNthReverse<T>(tc, t, occurrencePosition)).ToString();
           }


}

}

Solution 20 - C#

public static int IndexOfAny(this string str, string[] values, int startIndex, out string selectedItem)
    {
        int first = -1;
        selectedItem = null;
        foreach (string item in values)
        {
            int i = str.IndexOf(item, startIndex, StringComparison.OrdinalIgnoreCase);
            if (i >= 0)
            {
                if (first > 0)
                {
                    if (i < first)
                    {
                        first = i;
                        selectedItem = item;
                    }
                }
                else
                {
                    first = i;
                    selectedItem = item;
                }
            }
        }
        return first;
    }

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Solution 1 - C#Mike TwoView Answer on Stackoverflow
Solution 2 - C#shalin shahView Answer on Stackoverflow
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Solution 5 - C#Joel CoehoornView Answer on Stackoverflow
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