If you don&#39;t have any other indexes or sorted information for your objects, then you will have to iterate until such an object is found:

    next(obj for obj in objs if obj.val == 5)

This is however faster than a complete list comprehension. Compare these two:

    [i for i in xrange(100000) if i == 1000][0]

    next(i for i in xrange(100000) if i == 1000)

The first one needs 5.75ms, the second one 58.3&#181;s (100 times faster because the loop 100 times shorter).

    a = [100, 200, 300, 400, 500]

    def search(b):
     try:
      k = a.index(b)
      return a[k] 
     except ValueError:
        return &#39;not found&#39;

    print(search(500))

it&#39;ll return the object if found else it&#39;ll return &quot;not found&quot;



I have an input text which is this:

    &lt;div class=&quot;editor-label&quot;&gt;
        @Html.LabelFor(model =&gt; model.EmployeeId, &quot;Employee Number&quot;)
    &lt;/div&gt;
    
    &lt;div class=&quot;editor-field textBoxEmployeeNumber&quot;&gt;
        @Html.EditorFor(model =&gt; model.EmployeeId) 
        @Html.ValidationMessageFor(model =&gt; model.EmployeeId)
    &lt;/div&gt;

Which produce following html

&lt;!-- begin snippet: js hide: false console: true babel: false --&gt;

&lt;!-- language: lang-html --&gt;

    &lt;div class=&quot;editor-label&quot;&gt;
      &lt;label for=&quot;EmployeeId&quot;&gt;Employee Number&lt;/label&gt;
    &lt;/div&gt;

    &lt;div class=&quot;editor-field textBoxEmployeeNumber&quot;&gt;
      &lt;input class=&quot;text-box single-line&quot; data-val=&quot;true&quot; data-val-number=&quot;The field EmployeeId must be a number.&quot; data-val-required=&quot;The EmployeeId field is required.&quot; id=&quot;EmployeeId&quot; name=&quot;EmployeeId&quot; type=&quot;text&quot; value=&quot;&quot; /&gt;

      &lt;span class=&quot;field-validation-valid&quot; data-valmsg-for=&quot;EmployeeId&quot; data-valmsg-replace=&quot;true&quot;&gt;&lt;/span&gt;
    &lt;/div&gt;

&lt;!-- end snippet --&gt;

I want to set the value of this input text using jquery so i did this:

    &lt;script type=&quot;text/javascript&quot; language=&quot;javascript&quot;&gt;
        $(function() {
            $(&#39;.textBoxEmployeeNumber&#39;).val(&quot;fgg&quot;);
        });
    &lt;/script&gt; 
         


however, it is not working... what is the error in my syntax?

How to set value of input text using jQuery

Can somebody please explain with examples (of code) what is the difference between **deadlock** and **livelock**?

What&#39;s the difference between deadlock and livelock?

What would be the most elegant and efficient way of finding/returning the first list item that matches a certain criterion?

For example, if I have a list of objects and I would like to get the first object of those with attribute `obj.val==5`. I could of course use list comprehension, but that would incur O(n) and if n is large, it&#39;s wasteful. I could also use a loop with `break` once the criterion was met, but I thought there could be a more pythonic/elegant solution.

Find first sequence item that matches a criterion

<p>What would be the most elegant and efficient way of finding/returning the first list item that matches a certain criterion?</p>
<p>For example, if I have a list of objects and I would like to get the first object of those with attribute <code>obj.val==5</code>. I could of course use list comprehension, but that would incur O(n) and if n is large, it's wasteful. I could also use a loop with <code>break</code> once the criterion was met, but I thought there could be a more pythonic/elegant solution.</p>


&gt; **Possible Duplicate:**  
&gt; [What are &amp;ldquo;named tuples&amp;rdquo; in Python?](https://stackoverflow.com/questions/2970608/what-are-named-tuples-in-python)  

&lt;!-- End of automatically inserted text --&gt;

What is the situation where a namedtuple should be used?

When I looked into it, it looked like a way to make tuples more like dictionaries. How do they compare to dictionaries? 

Can only the same hashable types for dictionaries be used for namedtuples?

When and why should I use a namedtuple instead of a dictionary?

In Python I can define a function as follows:

```py
def func(kw1=None,kw2=None,**kwargs):
   ...
```

In this case, I can call `func` as:

```py
func(kw1=3,kw2=4,who_knows_if_this_will_be_used=7,more_kwargs=Ellipsis)
```

I can also define a function as:

```py
def func(arg1,arg2,*args):
    ...
```

which can be called as

```py
func(3,4,additional,arguments,go,here,Ellipsis)
```

Finally, I can combine the two forms

```py
def func(arg1,arg2,*args,**kwargs):
    ...
```

But, what does not work is calling:

```py
func(arg1,arg2,*args,kw1=None,kw2=None,**kwargs):  #SYNTAX ERROR (in Python 2 only, apparently this works in Python 3)
    ...
```

My original thought was that this was probably because a function

```py
def func(arg1,arg2,*args,kw1=None):
    ...
```

can be called as

```py
func(1,2,3)  #kw1 will be assigned 3
```

So this would introduce some ambiguity as to whether 3 should be packed into `args` or `kwargs`. However, with Python 3, there is the ability to specify keyword only arguments:

```py
def func(a,b,*,kw=None):  # can be called as func(1,2), func(1,2,kw=3), but NOT func(1,2,3)
    ...
```

With this, it seems that there is no syntactic ambiguity with:

```py
def func(a,b,*args,*,kw1=None,**kwargs):
    ...
```

However, this still brings up a syntax error (tested with Python3.2).  Is there a reason for this that I am missing? And, is there a way to get the behavior I described above (Having `*args` with default arguments) -- I know I can simulate that behavior by manipulating the `kwargs` dictionary inside the function.


Calling a Python function with *args,**kwargs and optional / default arguments

In the [`math`](https://docs.python.org/3/library/math.html) module, I could only find `math.cos(x)`, with cos/sin/tan/acos/asin/atan. This returns the answer in radians. How can I get the answer in degrees?

Here&#39;s my code:

    import math
    
    x = math.cos(1)
    y = x * 180 / math.pi
    print(y)
    30.9570417874

My calculator, on deg, gives me:

    cos(1)
    0.9998476...

How can I convert radians to degrees with Python?

How do I calculate the derivative of a function, for example 

&gt; y = x&lt;sup&gt;2&lt;/sup&gt;+1 

using `numpy`?

Let&#39;s say, I want the value of derivative at x = 5... 

How do I compute derivative using Numpy?

I&#39;m trying to get access to the user agent with Flask, but I either can&#39;t find the documentation on it, or it doesn&#39;t tell me.

How do I get the user agent with Flask?

How can I ignore the &quot;not in list&quot; error message if I call `a.remove(x)` when `x` is not present in list `a`?

This is my situation:

    &gt;&gt;&gt; a = range(10)
    &gt;&gt;&gt; a
    [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
    &gt;&gt;&gt; a.remove(10)
    Traceback (most recent call last):
      File &quot;&lt;stdin&gt;&quot;, line 1, in &lt;module&gt;
    ValueError: list.remove(x): x not in list
    &gt;&gt;&gt; a.remove(9)

How can I ignore ValueError when I try to remove an element from a list?

Is there a way to get the list of all new/deleted/modified directories/files in local/remote repository w.r.t each other in GIT ?


GIT list of new/modified/deleted files

Lists say I have a list `List&lt;int&gt; {1,2,3,4,5}`

Rotate means: 

    =&gt; {2,3,4,5,1} =&gt; {3,4,5,1,2} =&gt; {4,5,1,2,3}

Maybe rotate is not the best word for this, but hope you understand what I means

My question, whats the easiest way (in short code, c# 4 Linq ready), and will not be hit by performance (reasonable performance)

Thanks.

Easiest way to Rotate a List in c#

I was wondering what the use of the comma was when slicing Python arrays - I have an example that appears to work, but the line that looks weird to me is

    p = 20*numpy.log10(numpy.abs(numpy.fft.rfft(data[:2048, 0])))

Now, I know that when slicing an array, the first number is start, the next is end, and the last is step, but what does the comma after the end number designate? Thanks.

Python Array Slice With Comma?

I am trying to create a nice column list in python for use with commandline admin tools which I create.

Basicly, I want a list like:

    [[&#39;a&#39;, &#39;b&#39;, &#39;c&#39;], [&#39;aaaaaaaaaa&#39;, &#39;b&#39;, &#39;c&#39;], [&#39;a&#39;, &#39;bbbbbbbbbb&#39;, &#39;c&#39;]]


To turn into:

    a            b            c
    aaaaaaaaaa   b            c
    a            bbbbbbbbbb   c


Using plain tabs wont do the trick here because I don&#39;t know the longest data in each row.

This is the same behavior as &#39;column -t&#39; in Linux..


    $ echo -e &quot;a b c\naaaaaaaaaa b c\na bbbbbbbbbb c&quot;
    a b c
    aaaaaaaaaa b c
    a bbbbbbbbbb c

    $ echo -e &quot;a b c\naaaaaaaaaa b c\na bbbbbbbbbb c&quot; | column -t
    a           b           c
    aaaaaaaaaa  b           c
    a           bbbbbbbbbb  c

I have looked around for various python libraries to do this but can&#39;t find anything useful. 

Content Type	Original Author	Original Content on Stackoverflow
Question	Jonathan Livni	View Question on Stackoverflow
Solution 1 - Python	eumiro	View Answer on Stackoverflow
Solution 2 - Python	Ashwini Chaudhary	View Answer on Stackoverflow

Find first sequence item that matches a criterion

Python Problem Overview

Python Solutions

Solution 1 - Python

Solution 2 - Python

What's the difference between deadlock and livelock?

How to set value of input text using jQuery

Attributions