Find and remove objects in an array based on a key value in JavaScript

JavascriptJqueryArraysObject

Javascript Problem Overview


I have been trying several approaches on how to find an object in an array, where ID = var, and if found, remove the object from the array and return the new array of objects.

Data:

[    {"id":"88","name":"Lets go testing"},    {"id":"99","name":"Have fun boys and girls"},    {"id":"108","name":"You are awesome!"}]

I'm able to search the array using jQuery $grep;

var id = 88;

var result = $.grep(data, function(e){
     return e.id == id;
});

But how can I delete the entire object when id == 88, and return data like the following?

Data:

[    {"id":"99", "name":"Have fun boys and girls"},    {"id":"108", "name":"You are awesome!"}]

Javascript Solutions


Solution 1 - Javascript

Here is a solution if you are not using jQuery:

myArray = myArray.filter(function( obj ) {
  return obj.id !== id;
});

Solution 2 - Javascript

> I can grep the array for the id, but how can I delete the entire object where id == 88

Simply filter by the opposite predicate:

var data = $.grep(data, function(e){ 
     return e.id != id; 
});

Solution 3 - Javascript

You can simplify this, and there isn't really any need for using jQuery here.

var id = 88;

for(var i = 0; i < data.length; i++) {
    if(data[i].id == id) {
        data.splice(i, 1);
        break;
    }
}

Just iterate through the list, find the matching id, splice, and then break to exit your loop.

Solution 4 - Javascript

There's a new method to do this in ES6/2015 using findIndex and the array spread operator:

const index = data.findIndex(obj => obj.id === id);
const newData = [
    ...data.slice(0, index),
    ...data.slice(index + 1)
]

You can turn it into a function for later reuse like this:

function remove(array, key, value) {
    const index = array.findIndex(obj => obj[key] === value);
    return index >= 0 ? [
        ...array.slice(0, index),
        ...array.slice(index + 1)
    ] : array;
}

This way, you can remove items by different keys using one method (and if there's no object that meets the criteria, you get original array returned):

const newData = remove(data, "id", "88");
const newData2 = remove(data, "name", "You are awesome!");

Or you can put it on your Array.prototype:

Array.prototype.remove = function (key, value) {
    const index = this.findIndex(obj => obj[key] === value);
    return index >= 0 ? [
        ...this.slice(0, index),
        ...this.slice(index + 1)
    ] : this;
};

And use it this way:

const newData = data.remove("id", "88");
const newData2 = data.remove("name", "You are awesome!");

Solution 5 - Javascript

var items = [
  {"id":"88","name":"Lets go testing"},
  {"id":"99","name":"Have fun boys and girls"},
  {"id":"108","name":"You are awesome!"}
];

If you are using jQuery, use jQuery.grep like this:

items = $.grep(items, function(item) { 
  return item.id !== '88';
});
// items => [{ id: "99" }, { id: "108" }]

Using ES5 Array.prototype.filter:

items = items.filter(function(item) { 
  return item.id !== '88'; 
});
// items => [{ id: "99" }, { id: "108" }]

Solution 6 - Javascript

Assuming that ids are unique and you'll only have to remove the one element splice should do the trick:

var data = [
  {"id":"88","name":"Lets go testing"},
  {"id":"99","name":"Have fun boys and girls"},
  {"id":"108","name":"You are awesome!"}
],
id = 88;

console.table(data);

$.each(data, function(i, el){
  if (this.id == id){
    data.splice(i, 1);
  }
});

console.table(data);

Solution 7 - Javascript

Native ES6 solution:

const pos = data.findIndex(el => el.id === ID_TO_REMOVE);
if (pos >= 0)
    data.splice(pos, 1);

If you know that the element is in the array for sure:

data.splice(data.findIndex(el => el.id === ID_TO_REMOVE), 1);

Prototype:

Array.prototype.removeByProp = function(prop,val) {
    const pos = this.findIndex(x => x[prop] === val);
    if (pos >= 0)
        return this.splice(pos, 1);
};

// usage:
ar.removeByProp('id', ID_TO_REMOVE);

http://jsfiddle.net/oriadam/72kgprw5/

Note: this removes the item in-place. If you need a new array, use filter as mentioned in previous answers.

Solution 8 - Javascript

const data = [
    {"id":"88","name":"Lets go testing"},
    {"id":"99","name":"Have fun boys and girls"},
    {"id":"108","name":"You are awesome!"}
];

Here we get the index of the object whose value of the id is "88"

const index = data.findIndex(item => item.id === "88");
console.log(index); // 0

We use splice function to remove the specified object from data array

data.splice(index,1);
console.log(data); // [{"id":"99","name":"Have fun boys and girls"},{"id":"108","name":"You are awesome!"}]

Solution 9 - Javascript

Maybe you are looking for $.grep() function:

arr = [
  {"id":"88","name":"Lets go testing"},
  {"id":"99","name":"Have fun boys and girls"},
  {"id":"108","name":"You are awesome!"}
];

id = 88;
arr = $.grep(arr, function(data, index) {
   return data.id != id
});

Solution 10 - Javascript

Array.prototype.removeAt = function(id) {
    for (var item in this) {
        if (this[item].id == id) {
            this.splice(item, 1);
            return true;
        }
    }
    return false;
}

This should do the trick, jsfiddle

Solution 11 - Javascript

sift is a powerful collection filter for operations like this and much more advanced ones. It works client side in the browser or server side in Node.js.

var collection = [
    {"id":"88",  "name":"Lets go testing"},
    {"id":"99",  "name":"Have fun boys and girls"},
    {"id":"108", "name":"You are awesome!"}
];
var sifted = sift({id: {$not: 88}}, collection);

It supports filters like $in, $nin, $exists, $gte, $gt, $lte, $lt, $eq, $ne, $mod, $all, $and, $or, $nor, $not, $size, $type, and $regex, and strives to be API-compatible with MongoDB collection filtering.

Solution 12 - Javascript

I agree with the previous answers. A simple way if you want to find an object by id and remove it is simply like the below code:

var obj = JSON.parse(data);
var newObj = obj.filter(item => item.Id != 88);

Solution 13 - Javascript

Make sure you coerce the object id to an integer if you test for strict equality:

var result = $.grep(data, function(e, i) { 
  return +e.id !== id;
});

Demo

Solution 14 - Javascript

If you are using Underscore.js, it is easy to remove an object based on a key.

Example:

  var temp1=[{id:1,name:"safeer"},  // Temporary array
             {id:2,name:"jon"},
             {id:3,name:"James"},
             {id:4,name:"deepak"},
             {id:5,name:"ajmal"}];

  var id = _.pluck(temp1,'id'); // Get id array from temp1
  var ids=[2,5,10];             // ids to be removed
  var bool_ids=[];
  _.each(ids,function(val){
     bool_ids[val]=true;
  });
  _.filter(temp1,function(val){
     return !bool_ids[val.id];
  });

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