filteredArrayUsingPredicate does not exist in swift Array
SwiftIos8Xcode6Swift Problem Overview
I have "UserDetails" struct objects in array..I want to filter the objects from array. But there is no option for "filteredArrayUsingPredicate" in Swift array.
My array creation
var arrayOfUsers:UserDetails[] = UserDetails[]()
my userdetails code is
struct UserDetails{
var userName:String
var userID:String
var userAge:String
func userDescription()->String{
return "name " + userName + "age " + userID
}
}
my code to create objects
for a in 1...1000{
var user:UserDetails = UserDetails(userName: "name", userID: String(a), userAge: "22")
arrayOfUsers.append(user)
}
Now I want to filter arrayOfUsers
which one has userID "1".
Swift Solutions
Solution 1 - Swift
Swift arrays have a .filter
method that takes a closure -- this will do it:
let filteredArray = arrayOfUsers.filter() { $0.userID == "1" }
Closures can be simplified in a variety of ways. The full declaration of the closure would look more like this:
var filteredArray = arrayOfUsers.filter( { (user: UserDetails) -> Bool in
return user.userID == "1"
})
The difference between the two is that the first is using trailing closure syntax, shorthand argument names, type inference, and implicit return. You can read more about closures in Apple's Swift documentation.
Solution 2 - Swift
you can also use NSPredicate
var customerNameDict = ["firstName":"karthi","LastName":"alagu","MiddleName":"prabhu"];
var clientNameDict = ["firstName":"Selva","LastName":"kumar","MiddleName":"m"];
var employeeNameDict = ["firstName":"karthi","LastName":"prabhu","MiddleName":"kp"];
var attributeValue = "karthi";
var arrNames:Array = [customerNameDict,clientNameDict,employeeNameDict];
var namePredicate =
NSPredicate(format: "firstName like %@",attributeValue);
let filteredArray = arrNames.filter { namePredicate.evaluateWithObject($0) };
println("names = ,\(filteredArray)");
//struct filtering
struct myStruct
{
var userid:String;
var details:String;
init() {
userid = "default value";
details = "default";
}
};
var f1 = myStruct();
f1.userid = "1";
f1.details = "Good boy";
var f2 = myStruct();
f2.userid = "2";
f2.details = "Bad boy";
var arrNames1:Array = [f1,f2];
let filteredArrayStruct = arrNames1.filter( { (user: myStruct) -> Bool in
return user.userid == "1"
})
println("filter array count = \(filteredArrayStruct.count)");
for filteredValues in filteredArrayStruct
{
println("filteredArrayStruct = ,\(filteredValues.details)");
}
Solution 3 - Swift
If you are filtering a dictionary you can do it like this.
var visitors = [["age" : 22], ["age" : 41], ["age" : 23], ["age" : 30]]
var filteredVisitors = visitors.filter({
$0["age"] < 30
})
println(filteredVisitors)
//[["age" : 22], ["age" : 23]]
Well the same applies to structs where you would filter its property
struct Person {
var age : Int?
init(age: Int) {
self.age = age
}
}
var eventAttendees = [Person(age: 22), Person(age: 41), Person(age: 23), Person(age: 30)]
var filteredAttendees = eventAttendees.filter({
$0.age < 30
})
You can refer to this articles for more info. Filtering a Swift Array of Dictionaries or Object property
Solution 4 - Swift
In swift 3 or 4 you can use NSPredicate With Array
let pred : NSPredicate = NSPredicate(format: "points_status = %@", "0")
let approvalRequestArray = approvalRequestOriginalArray.filtered(using: pred) as NSArray
let provincesStartingWithM = NSPredicate(format: "name contains [cd] 'a'")
provinces.filtered(using: provincesStartingWithM)
For More information, You can Visit this link GitHub
Solution 5 - Swift
As it turns out, you don't have to compare only one filter at a time. You can apply logical conditionals to broaden the scope of the predicate. For example:
var foundArray = tempArray.filter{ String(describing:$0.id) .contains(searchText) ||
$0.name .contains(searchText) || $0.summary! .contains(searchText) ||
String(describing: $0.airDate).contains(searchText) || String(describing: $0.airTime).contains(searchText) ||
String(describing: $0.runTime).contains(searchText)}
works like a champ.