Fastest way to check if a string is JSON in PHP?
PhpJsonError HandlingJson DeserializationJsonresultPhp Problem Overview
I need a really, really fast method of checking if a string is JSON or not. I feel like this is not the best way:
function isJson($string) {
return ((is_string($string) &&
(is_object(json_decode($string)) ||
is_array(json_decode($string))))) ? true : false;
}
Any performance enthusiasts out there want to improve this method?
Php Solutions
Solution 1 - Php
function isJson($string) {
json_decode($string);
return json_last_error() === JSON_ERROR_NONE;
}
Solution 2 - Php
> Answer to the Question
The function json_last_error returns the last error occurred during the JSON encoding and decoding. So the fastest way to check the valid JSON is
// decode the JSON data
// set second parameter boolean TRUE for associative array output.
$result = json_decode($json);
if (json_last_error() === JSON_ERROR_NONE) {
// JSON is valid
}
// OR this is equivalent
if (json_last_error() === 0) {
// JSON is valid
}
Note that json_last_error is supported in PHP >= 5.3.0 only.
> Full program to check the exact ERROR
It is always good to know the exact error during the development time. Here is full program to check the exact error based on PHP docs.
function json_validate($string)
{
// decode the JSON data
$result = json_decode($string);
// switch and check possible JSON errors
switch (json_last_error()) {
case JSON_ERROR_NONE:
$error = ''; // JSON is valid // No error has occurred
break;
case JSON_ERROR_DEPTH:
$error = 'The maximum stack depth has been exceeded.';
break;
case JSON_ERROR_STATE_MISMATCH:
$error = 'Invalid or malformed JSON.';
break;
case JSON_ERROR_CTRL_CHAR:
$error = 'Control character error, possibly incorrectly encoded.';
break;
case JSON_ERROR_SYNTAX:
$error = 'Syntax error, malformed JSON.';
break;
// PHP >= 5.3.3
case JSON_ERROR_UTF8:
$error = 'Malformed UTF-8 characters, possibly incorrectly encoded.';
break;
// PHP >= 5.5.0
case JSON_ERROR_RECURSION:
$error = 'One or more recursive references in the value to be encoded.';
break;
// PHP >= 5.5.0
case JSON_ERROR_INF_OR_NAN:
$error = 'One or more NAN or INF values in the value to be encoded.';
break;
case JSON_ERROR_UNSUPPORTED_TYPE:
$error = 'A value of a type that cannot be encoded was given.';
break;
default:
$error = 'Unknown JSON error occured.';
break;
}
if ($error !== '') {
// throw the Exception or exit // or whatever :)
exit($error);
}
// everything is OK
return $result;
}
> Testing with Valid JSON INPUT
$json = '[{"user_id":13,"username":"stack"},{"user_id":14,"username":"over"}]';
$output = json_validate($json);
print_r($output);
> Valid OUTPUT
Array
(
[0] => stdClass Object
(
[user_id] => 13
[username] => stack
)
[1] => stdClass Object
(
[user_id] => 14
[username] => over
)
)
> Testing with invalid JSON
$json = '{background-color:yellow;color:#000;padding:10px;width:650px;}';
$output = json_validate($json);
print_r($output);
> Invalid OUTPUT
Syntax error, malformed JSON.
> Extra note for (PHP >= 5.2 && PHP < 5.3.0)
Since json_last_error is not supported in PHP 5.2, you can check if the encoding or decoding returns boolean FALSE. Here is an example
// decode the JSON data
$result = json_decode($json);
if ($result === FALSE) {
// JSON is invalid
}
Solution 3 - Php
All you really need to do is this...
if (is_object(json_decode($MyJSONArray)))
{
... do something ...
}
This request does not require a separate function even. Just wrap is_object around json_decode and move on. Seems this solution has people putting way too much thought into it.
Solution 4 - Php
Using json_decode to "probe" it might not actually be the fastest way. If it's a deeply nested structure, then instantiating a lot of objects of arrays to just throw them away is a waste of memory and time.
So it might be faster to use preg_match and the RFC4627 regex to also ensure validity:
// in JS:
var my_JSON_object = !(/[^,:{}\[\]0-9.\-+Eaeflnr-u \n\r\t]/.test(
text.replace(/"(\\.|[^"\\])*"/g, '')));
The same in PHP:
return !preg_match('/[^,:{}\\[\\]0-9.\\-+Eaeflnr-u \\n\\r\\t]/',
preg_replace('/"(\\.|[^"\\\\])*"/', '', $json_string));
Not enough of a performance enthusiast to bother with benchmarks here however.
Solution 5 - Php
This will return true if your string represents a json array or object:
function isJson($str) {
$json = json_decode($str);
return $json && $str != $json;
}
It rejects json strings that only contains a number, string or boolean, although those strings are technically valid json.
var_dump(isJson('{"a":5}')); // bool(true)
var_dump(isJson('[1,2,3]')); // bool(true)
var_dump(isJson('1')); // bool(false)
var_dump(isJson('1.5')); // bool(false)
var_dump(isJson('true')); // bool(false)
var_dump(isJson('false')); // bool(false)
var_dump(isJson('null')); // bool(false)
var_dump(isJson('hello')); // bool(false)
var_dump(isJson('')); // bool(false)
It is the shortest way I can come up with.
Solution 6 - Php
The simplest and fastest way that I use is following;
$json_array = json_decode( $raw_json , true );
if( $json_array == NULL ) //check if it was invalid json string
die ('Invalid'); // Invalid JSON error
// you can execute some else condition over here in case of valid JSON
It is because json_decode() returns NULL if the entered string is not json or invalid json.
Simple function to validate JSON
If you have to validate your JSON in multiple places, you can always use the following function.
function is_valid_json( $raw_json ){
return ( json_decode( $raw_json , true ) == NULL ) ? false : true ; // Yes! thats it.
}
In the above function, you will get true in return if it is a valid JSON.
Solution 7 - Php
function is_json($str){
return json_decode($str) != null;
}
http://tr.php.net/manual/en/function.json-decode.php return value is null when invalid encoding detected.
Solution 8 - Php
I found this question after coming across something similar in my work, yesterday. My solution in the end was a hybrid of some of the approaches above:
function is_JSON($string) {
return (is_null(json_decode($string))) ? FALSE : TRUE;
}
Solution 9 - Php
You must validate your input to make sure the string you pass is not empty and is, in fact, a string. An empty string is not valid JSON.
function is_json($string) {
return !empty($string) && is_string($string) && is_array(json_decode($string, true)) && json_last_error() == 0;
}
I think in PHP it's more important to determine if the JSON object even has data, because to use the data you will need to call json_encode() or json_decode(). I suggest denying empty JSON objects so you aren't unnecessarily running encodes and decodes on empty data.
function has_json_data($string) {
$array = json_decode($string, true);
return !empty($string) && is_string($string) && is_array($array) && !empty($array) && json_last_error() == 0;
}
Solution 10 - Php
The fastest way is to "maybe decode" the possible JSON string
Is this really the fastest method?
If you want to decode complex objects or larger arrays, this is the fastest solution! Besides being fast, this is the only solution that can reliably handle any kind of input value - other functions throw errors or return incorrect results in some cases.
If your JSON string contains short values (e.g., strings, numbers or objects with only 1-2 attributes) then all solutions in this SO questions come to a similar performance.
Here's a quick overview with comparison - you can find the test-cases in the linked gist. The last column uses the code from this answer:
PHP version: 7.4.21
test1: json_last_error() == JSON_ERROR_NONE
test2: is_object( json_decode() )
test3: json_decode() && $res != $string
test4: preg_match()
test5: "maybe decode" approach
| test1 | test2 | test3 | test4 | test5
#0 | 0.0147 | 0.0109 ✓︎ | 0.0119 | 0.0177 | 0.0194
#1 | 0.0129 | 0.0106 | 0.0098 | - INV - | 0.0078 ✓︎
#2 | 0.0076 | 0.0075 | 0.0063 ✓︎ | 0.0083 | 0.0133
#3 | 0.0126 | 0.0105 | 0.0096 ✓︎ | - INV - | 0.0172
#4 | 0.0070 | - INV - | 0.0061 ✓︎ | 0.0141 | 0.0134
#5 | 0.0114 | - INV - | 0.0101 | 0.0075 ✓︎ | 0.0168
#6 | 0.0203 | - INV - | 0.0195 | 0.0073 ✓︎ | 0.0259
#7 | 0.0046 | - INV - | - INV - | 0.0077 | 0.0031 ✓︎
#8 | 0.0066 | - INV - | - INV - | 0.0081 | 0.0020 ✓︎
#9 | 1.0781 | - INV - | 1.0555 | 0.0998 ✓︎ | 1.0385
#10 | 0.3183 ✓︎ | 0.3246 | 0.3270 | 1.0186 | 0.3311
#11 | 0.0071 | 0.0068 | 0.0067 ✓︎ | - INV - | 0.0079
#12 | - ERR - | - ERR - | - ERR - | - ERR - | 0.0025 ✓︎
#13 | - ERR - | - ERR - | - ERR - | - ERR - | 0.0024 ✓︎
Avg | 0.1251 | 0.0618 ✓︎ | 0.1463 | 0.1321 | 0.1072
Note that the fastest solution produces the most incorrect results. From all other solutions, the "maybe decode" approach is not only the fastest, but also the only solution with correct results.
Here is the full performance comparison script, there you can see the test-data I used for the comparison: https://gist.github.com/stracker-phil/6a80e6faedea8dab090b4bf6668ee461
The "maybe decode" logic/code
We first perform some type checks and string comparisons before attempting to decode the JSON string. This gives us the best performance because json_decode() can be slow.
/**
* Returns true, when the given parameter is a valid JSON string.
*/
function is_json( $value ) {
// Numeric strings are always valid JSON.
if ( is_numeric( $value ) ) { return true; }
// A non-string value can never be a JSON string.
if ( ! is_string( $value ) ) { return false; }
// Any non-numeric JSON string must be longer than 2 characters.
if ( strlen( $value ) < 2 ) { return false; }
// "null" is valid JSON string.
if ( 'null' === $value ) { return true; }
// "true" and "false" are valid JSON strings.
if ( 'true' === $value ) { return true; }
if ( 'false' === $value ) { return false; }
// Any other JSON string has to be wrapped in {}, [] or "".
if ( '{' != $value[0] && '[' != $value[0] && '"' != $value[0] ) { return false; }
// Verify that the trailing character matches the first character.
$last_char = $value[strlen($value) -1];
if ( '{' == $value[0] && '}' != $last_char ) { return false; }
if ( '[' == $value[0] && ']' != $last_char ) { return false; }
if ( '"' == $value[0] && '"' != $last_char ) { return false; }
// See if the string contents are valid JSON.
return null !== json_decode( $value );
}
Extra: Use this logic to safely double-decode JSON
This function uses the same logic but either returns the decoded JSON object or the original value.
I use this function in a parser that recursively decodes a complex object. Some attributes might be decoded already by an earlier iteration. That function recognizes this and does not attempt to double decode the value again.
/**
* Tests, if the given $value parameter is a JSON string.
* When it is a valid JSON value, the decoded value is returned.
* When the value is no JSON value (i.e. it was decoded already), then
* the original value is returned.
*/
function get_data( $value, $as_object = false ) {
if ( is_numeric( $value ) ) { return 0 + $value; }
if ( ! is_string( $value ) ) { return $value; }
if ( strlen( $value ) < 2 ) { return $value; }
if ( 'null' === $value ) { return null; }
if ( 'true' === $value ) { return true; }
if ( 'false' === $value ) { return false; }
if ( '{' != $value[0] && '[' != $value[0] && '"' != $value[0] ) { return $value; }
$json_data = json_decode( $value, $as_object );
if ( is_null( $json_data ) ) { return $value; }
return $json_data;
}
Note: When passing a non-string to any of the other solution in this SO question, you will get dramatically degraded performance + wrong return values (or even fatal errors). This code is bulletproof and highly performant.
Solution 11 - Php
This will do it:
function isJson($string) {
$decoded = json_decode($string); // decode our JSON string
if ( !is_object($decoded) && !is_array($decoded) ) {
/*
If our string doesn't produce an object or array
it's invalid, so we should return false
*/
return false;
}
/*
If the following line resolves to true, then there was
no error and our JSON is valid, so we return true.
Otherwise it isn't, so we return false.
*/
return (json_last_error() == JSON_ERROR_NONE);
}
if ( isJson($someJsonString) ) {
echo "valid JSON";
} else {
echo "not valid JSON";
}
As shown in other answers, json_last_error() returns any error from our last json_decode(). However there are some edge use cases where this function alone is not comprehensive enough. For example, if you json_decode() an integer (eg: 123), or a string of numbers with no spaces or other characters (eg: "123"), the json_last_error() function will not catch an error.
To combat this, I've added an extra step that ensures the result of our json_decode() is either an object or an array. If it's not, then we return false.
To see this in action, check these two examples:
Solution 12 - Php
Using PHPBench with the following class, the below results were achieved:
<?php
declare(strict_types=1);
/**
* @Revs(1000)
* @Iterations(100)
*/
class BenchmarkJson
{
public function benchCatchValid(): bool
{
$validJson = '{"validJson":true}';
try {
json_decode($validJson, true, 512, JSON_THROW_ON_ERROR);
return true;
} catch(\JsonException $exception) {}
return false;
}
public function benchCatchInvalid(): bool
{
$invalidJson = '{"invalidJson"';
try {
json_decode($invalidJson, true, 512, JSON_THROW_ON_ERROR);
return true;
} catch(\JsonException $exception) {}
return false;
}
public function benchLastErrorValid(): bool
{
$validJson = '{"validJson":true}';
json_decode($validJson, true);
return (json_last_error() === JSON_ERROR_NONE);
}
public function benchLastErrorInvalid(): bool
{
$invalidJson = '{"invalidJson"';
json_decode($invalidJson, true);
return (json_last_error() === JSON_ERROR_NONE);
}
public function benchNullValid(): bool
{
$validJson = '{"validJson":true}';
return (json_decode($validJson, true) !== null);
}
public function benchNullInvalid(): bool
{
$invalidJson = '{"invalidJson"';
return (json_decode($invalidJson, true) !== null);
}
}
6 subjects, 600 iterations, 6,000 revs, 0 rejects, 0 failures, 0 warnings
(best [mean mode] worst) = 0.714 [1.203 1.175] 1.073 (μs)
⅀T: 721.504μs μSD/r 0.089μs μRSD/r: 7.270%
suite: 1343ab9a3590de6065bc0bc6eeb344c9f6eba642, date: 2020-01-21, stime: 12:50:14
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+
| benchmark | subject | set | revs | its | mem_peak | best | mean | mode | worst | stdev | rstdev | diff |
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+
| BenchmarkJson | benchCatchValid | 0 | 1000 | 100 | 2,980,168b | 0.954μs | 1.032μs | 1.016μs | 1.428μs | 0.062μs | 6.04% | 1.33x |
| BenchmarkJson | benchCatchInvalid | 0 | 1000 | 100 | 2,980,184b | 2.033μs | 2.228μs | 2.166μs | 3.001μs | 0.168μs | 7.55% | 2.88x |
| BenchmarkJson | benchLastErrorValid | 0 | 1000 | 100 | 2,980,184b | 1.076μs | 1.195μs | 1.169μs | 1.616μs | 0.083μs | 6.97% | 1.54x |
| BenchmarkJson | benchLastErrorInvalid | 0 | 1000 | 100 | 2,980,184b | 0.785μs | 0.861μs | 0.863μs | 1.132μs | 0.056μs | 6.54% | 1.11x |
| BenchmarkJson | benchNullValid | 0 | 1000 | 100 | 2,980,168b | 0.985μs | 1.124μs | 1.077μs | 1.731μs | 0.114μs | 10.15% | 1.45x |
| BenchmarkJson | benchNullInvalid | 0 | 1000 | 100 | 2,980,184b | 0.714μs | 0.775μs | 0.759μs | 1.073μs | 0.049μs | 6.36% | 1.00x |
+---------------+-----------------------+-----+------+-----+------------+---------+---------+---------+---------+---------+--------+-------+
Conclusion: The fastest way to check if json is valid is to return json_decode($json, true) !== null).
Solution 13 - Php
Easy method is to check the json result..
$result = @json_decode($json,true);
if (is_array($result)) {
echo 'JSON is valid';
}else{
echo 'JSON is not valid';
}
Solution 14 - Php
in GuzzleHttp:
/**
* Wrapper for json_decode that throws when an error occurs.
*
* @param string $json JSON data to parse
* @param bool $assoc When true, returned objects will be converted
* into associative arrays.
* @param int $depth User specified recursion depth.
* @param int $options Bitmask of JSON decode options.
*
* @return mixed
* @throws \InvalidArgumentException if the JSON cannot be decoded.
* @link http://www.php.net/manual/en/function.json-decode.php
*/
function json_decode($json, $assoc = false, $depth = 512, $options = 0)
{
$data = \json_decode($json, $assoc, $depth, $options);
if (JSON_ERROR_NONE !== json_last_error()) {
throw new \InvalidArgumentException(
'json_decode error: ' . json_last_error_msg());
}
return $data;
}
/**
* Wrapper for JSON encoding that throws when an error occurs.
*
* @param mixed $value The value being encoded
* @param int $options JSON encode option bitmask
* @param int $depth Set the maximum depth. Must be greater than zero.
*
* @return string
* @throws \InvalidArgumentException if the JSON cannot be encoded.
* @link http://www.php.net/manual/en/function.json-encode.php
*/
function json_encode($value, $options = 0, $depth = 512)
{
$json = \json_encode($value, $options, $depth);
if (JSON_ERROR_NONE !== json_last_error()) {
throw new \InvalidArgumentException(
'json_encode error: ' . json_last_error_msg());
}
return $json;
}
Solution 15 - Php
//Tested thoroughly, Should do the job:
public static function is_json(string $json):bool
{
json_decode($json);
if (json_last_error() === JSON_ERROR_NONE) {
return true;
}
return false;
}
Solution 16 - Php
Earlier i was just checking for a null value, which was wrong actually.
$data = "ahad";
$r_data = json_decode($data);
if($r_data){//json_decode will return null, which is the behavior we expect
//success
}
The above piece of code works fine with strings. However as soon as i provide number, it breaks up.for example.
$data = "1213145";
$r_data = json_decode($data);
if($r_data){//json_decode will return 1213145, which is the behavior we don't expect
//success
}
To fix it what i did was very simple.
$data = "ahad";
$r_data = json_decode($data);
if(($r_data != $data) && $r_data)
print "Json success";
else
print "Json error";
Solution 17 - Php
We need to check if passed string is not numeric because in this case json_decode raises no error.
function isJson($str) {
$result = false;
if (!preg_match("/^\d+$/", trim($str))) {
json_decode($str);
$result = (json_last_error() == JSON_ERROR_NONE);
}
return $result;
}
Solution 18 - Php
Another simple way
function is_json($str)
{
return is_array(json_decode($str,true));
}
Solution 19 - Php
I've tried some of those solution but nothing was working for me. I try this simple thing :
$isJson = json_decode($myJSON);
if ($isJson instanceof \stdClass || is_array($isJson)) {
echo("it's JSON confirmed");
} else {
echo("nope");
}
I think it's a fine solutiuon since JSON decode without the second parameter give an object.
EDIT : If you know what will be the input, you can adapt this code to your needs. In my case I know I have a Json wich begin by "{", so i don't need to check if it's an array.
Solution 20 - Php
Should be something like this:
function isJson($string)
{
// 1. Speed up the checking & prevent exception throw when non string is passed
if (is_numeric($string) ||
!is_string($string) ||
!$string) {
return false;
}
$cleaned_str = trim($string);
if (!$cleaned_str || !in_array($cleaned_str[0], ['{', '['])) {
return false;
}
// 2. Actual checking
$str = json_decode($string);
return (json_last_error() == JSON_ERROR_NONE) && $str && $str != $string;
}
UnitTest
public function testIsJson()
{
$non_json_values = [
"12",
0,
1,
12,
-1,
'',
null,
0.1,
'.',
"''",
true,
false,
[],
'""',
'[]',
' {',
' [',
];
$json_values = [
'{}',
'{"foo": "bar"}',
'[{}]',
' {}',
' {} '
];
foreach ($non_json_values as $non_json_value) {
$is_json = isJson($non_json_value);
$this->assertFalse($is_json);
}
foreach ($json_values as $json_value) {
$is_json = isJson($json_value);
$this->assertTrue($is_json);
}
}
Solution 21 - Php
Hi here's a little snippet from my library, in this first condition I'm just checking if the data is json then return it if correctly decoded, please note the substr usage for performance ( I haven't seen yet any json file not begining neither by { or [
$input=trim($input);
if ((substr($input, 0, 1) == '{' && substr($input, -1) == '}') or (substr($input, 0, 1) == '[' && substr($input, -1) == ']')) {
$output = json_decode($input, 1);
if (in_array(gettype($output),['object','array'])) {
#then it's definitely JSON
}
}
Solution 22 - Php
I don't know about performance or elegance of my solution, but it's what I'm using:
if (preg_match('/^[\[\{]\"/', $string)) {
$aJson = json_decode($string, true);
if (!is_null($aJson)) {
... do stuff here ...
}
}
Since all my JSON encoded strings start with {" it suffices to test for this with a RegEx. I'm not at all fluent with RegEx, so there might be a better way to do this. Also: strpos() might be quicker.
Just trying to give in my tuppence worth.
P.S. Just updated the RegEx string to /^[\[\{]\"/ to also find JSON array strings. So it now looks for either [" or {" at the beginning of the string.
Solution 23 - Php
function isJson($string) {
$obj = json_decode($string);
return json_last_error() === JSON_ERROR_NONE && gettype($obj ) == "object";
}
this works and doesn't return true for numbers
new update
The above solution does not have good performance if the JSON is long and you don't need to use $obj
if you just want check, it's better to use below function
function isJson($string) {
if(is_numeric($string)) return false;
json_decode($string);
return json_last_error() === JSON_ERROR_NONE;
}
Solution 24 - Php
Expanding on this answer How about the following:
<?php
$json = '[{"user_id":13,"username":"stack"},{"user_id":14,"username":"over"}]';
//$json = '12';
function isJson($string) {
json_decode($string);
if(json_last_error() == JSON_ERROR_NONE) {
if(substr($string,0,1) == '[' && substr($string,-1) == ']') { return TRUE; }
else if(substr($string,0,1) == '{' && substr($string,-1) == '}') { return TRUE; }
else { return FALSE; }
}
}
echo isJson($json);
?>
Solution 25 - Php
Another suggestion from me :)
function isJson(string $string) {
return ($result = json_decode($string, true)) ? $result : $string;
}
Solution 26 - Php
This is what I recommend
if (!in_array(substr($string, 0, 1), ['{', '[']) || !in_array(substr($string, -1), ['}', ']'])) {
return false;
} else {
json_decode($string);
return (json_last_error() === JSON_ERROR_NONE);
}
Solution 27 - Php
$r = (array)json_decode($arr);
if(!is_array($r) || count($r) < 1) return false;
Solution 28 - Php
If a local file stations.json is invalid, missing, or is more than one month old, do something.
if (!is_array(json_decode(@file_get_contents("stations.json"))) || time() > filemtime("stations.json") + (60*60*24*31)){
// The json file is invalid, missing, or is more than 1 month old
// Get a fresh version
} else {
// Up to date
}
Solution 29 - Php
Freshly-made function for PHP 5.2 compatibility, if you need the decoded data on success:
function try_json_decode( $json, & $success = null ){
// non-strings may cause warnings
if( !is_string( $json )){
$success = false;
return $json;
}
$data = json_decode( $json );
// output arg
$success =
// non-null data: success!
$data !== null ||
// null data from 'null' json: success!
$json === 'null' ||
// null data from ' null ' json padded with whitespaces: success!
preg_match('/^\s*null\s*$/', $json );
// return decoded or original data
return $success ? $data : $json;
}
Usage:
$json_or_not = ...;
$data = try_json_decode( $json_or_not, $success );
if( $success )
process_data( $data );
else what_the_hell_is_it( $data );
Some tests:
var_dump( try_json_decode( array(), $success ), $success );
// ret = array(0){}, $success == bool(false)
var_dump( try_json_decode( 123, $success ), $success );
// ret = int(123), $success == bool(false)
var_dump( try_json_decode(' ', $success ), $success );
// ret = string(6) " ", $success == bool(false)
var_dump( try_json_decode( null, $success ), $success );
// ret = NULL, $success == bool(false)
var_dump( try_json_decode('null', $success ), $success );
// ret = NULL, $success == bool(true)
var_dump( try_json_decode(' null ', $success ), $success );
// ret = NULL, $success == bool(true)
var_dump( try_json_decode(' true ', $success ), $success );
// ret = bool(true), $success == bool(true)
var_dump( try_json_decode(' "hello" ', $success ), $success );
// ret = string(5) "hello", $success == bool(true)
var_dump( try_json_decode(' {"a":123} ', $success ), $success );
// ret = object(stdClass)#2 (1) { ["a"]=> int(123) }, $success == bool(true)
Solution 30 - Php
function is_json($input) {
$input = trim($input);
if (substr($input,0,1)!='{' OR substr($input,-1,1)!='}')
return false;
return is_array(@json_decode($input, true));
}
Solution 31 - Php
A simple modification to henrik's answer to touch most required possibilities. ( including " {} and [] " )
function isValidJson($string) {
json_decode($string);
if(json_last_error() == JSON_ERROR_NONE) {
if( $string[0] == "{" || $string[0] == "[" ) {
$first = $string [0];
if( substr($string, -1) == "}" || substr($string, -1) == "]" ) {
$last = substr($string, -1);
if($first == "{" && $last == "}"){
return true;
}
if($first == "[" && $last == "]"){
return true;
}
return false;
}
return false;
}
return false;
}
return false;
}
Solution 32 - Php
Here's a performant and simple function I created (which uses basic string validation before using json_decode for larger strings):
function isJson($string) {
$response = false;
if (
is_string($string) &&
($string = trim($string)) &&
($stringLength = strlen($string)) &&
(
(
stripos($string, '{') === 0 &&
(stripos($string, '}', -1) + 1) === $stringLength
) ||
(
stripos($string, '[{') === 0 &&
(stripos($string, '}]', -1) + 2) === $stringLength
)
) &&
($decodedString = json_decode($string, true)) &&
is_array($decodedString)
) {
$response = true;
}
return $response;
}