Extract Month and Year From Date in R

RDate

R Problem Overview


I have tried a number of methods to no avail. I have data in terms of a date (YYYY-MM-DD) and am trying to get in terms of just the month and year, such as: MM-YYYY or YYYY-MM.

Ultimately, I would like it to look like this:

ID    Date         Month_Yr
1     2004-02-06   2004-02
2     2006-03-14   2006-03
3     2007-07-16   2007-07
...   ...          ...

I am doing this in hopes of plotting money earned on average in a month, from a number of orders, over a period of time. Any help, or a push in the right direction would be much appreciated.

R Solutions


Solution 1 - R

This will add a new column to your data.frame with the specified format.

df$Month_Yr <- format(as.Date(df$Date), "%Y-%m")

df
#>   ID       Date Month_Yr
#> 1  1 2004-02-06  2004-02
#> 2  2 2006-03-14  2006-03
#> 3  3 2007-07-16  2007-07

# your data sample
  df <- data.frame( ID=1:3,Date = c("2004-02-06" , "2006-03-14" , "2007-07-16") )

a simple example:

dates <- "2004-02-06"

format(as.Date(dates), "%Y-%m")
> "2004-02"

side note: the data.table approach can be quite faster in case you're working with a big dataset.

library(data.table)
setDT(df)[, Month_Yr := format(as.Date(Date), "%Y-%m") ]

Solution 2 - R

Use substring?

d = "2004-02-06"
substr(d,0,7)
>"2004-02"

Solution 3 - R

Here's another solution using a package solely dedicated to working with dates and times in R:

library(tidyverse)
library(lubridate)

(df <- tibble(ID = 1:3, Date = c("2004-02-06" , "2006-03-14", "2007-07-16")))
#> # A tibble: 3 x 2
#>      ID Date      
#>   <int> <chr>     
#> 1     1 2004-02-06
#> 2     2 2006-03-14
#> 3     3 2007-07-16

df %>%
  mutate(
    Date = ymd(Date),
    Month_Yr = format_ISO8601(Date, precision = "ym")
  )
#> # A tibble: 3 x 3
#>      ID Date       Month_Yr
#>   <int> <date>     <chr>   
#> 1     1 2004-02-06 2004-02 
#> 2     2 2006-03-14 2006-03 
#> 3     3 2007-07-16 2007-07

Created on 2020-09-01 by the reprex package (v0.3.0)

Solution 4 - R

The zoo package has the function of as.yearmon can help to convert.

require(zoo)

df$ym <- as.yearmon(df$date, "%Y %m")

Solution 5 - R

The data.table package introduced the IDate class some time ago and zoo-package-like functions to retrieve months, days, etc (Check ?IDate). so, you can extract the desired info now in the following ways:

require(data.table)
df <- data.frame(id = 1:3,
                 date = c("2004-02-06" , "2006-03-14" , "2007-07-16"))
setDT(df)
df[ , date := as.IDate(date) ] # instead of as.Date()
df[ , yrmn := paste0(year(date), '-', month(date)) ]
df[ , yrmn2 := format(date, '%Y-%m') ]

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questiona.powellView Question on Stackoverflow
Solution 1 - Rrafa.pereiraView Answer on Stackoverflow
Solution 2 - RAllen HuangView Answer on Stackoverflow
Solution 3 - RAshirwadView Answer on Stackoverflow
Solution 4 - Ray__yaView Answer on Stackoverflow
Solution 5 - RandscharView Answer on Stackoverflow