Error in Python script "Expected 2D array, got 1D array instead:"?

PythonPython 3.xMachine LearningPredict

Python Problem Overview


I'm following this tutorial to make this ML prediction:

import numpy as np
import matplotlib.pyplot as plt
from matplotlib import style

style.use("ggplot")
from sklearn import svm
 
x = [1, 5, 1.5, 8, 1, 9]
y = [2, 8, 1.8, 8, 0.6, 11]
 
plt.scatter(x,y)
plt.show()
 
X = np.array([[1,2],
             [5,8],
             [1.5,1.8],
             [8,8],
             [1,0.6],
             [9,11]])
 
y = [0,1,0,1,0,1]
X.reshape(1, -1)
 
clf = svm.SVC(kernel='linear', C = 1.0)
clf.fit(X,y)
 
print(clf.predict([0.58,0.76]))

I'm using Python 3.6 and I get error "Expected 2D array, got 1D array instead:" I think the script is for older versions, but I don't know how to convert it to the 3.6 version.

Already try with the:

X.reshape(1, -1)

Python Solutions


Solution 1 - Python

You are just supposed to provide the predict method with the same 2D array, but with one value that you want to process (or more). In short, you can just replace

[0.58,0.76]

With

[[0.58,0.76]]

And it should work.

EDIT: This answer became popular so I thought I'd add a little more explanation about ML. The short version: we can only use predict on data that is of the same dimensionality as the training data (X) was.

In the example in question, we give the computer a bunch of rows in X (with 2 values each) and we show it the correct responses in y. When we want to predict using new values, our program expects the same - a bunch of rows. Even if we want to do it to just one row (with two values), that row has to be part of another array.

Solution 2 - Python

The problem is occurring when you run prediction on the array [0.58,0.76]. Fix the problem by reshaping it before you call predict():

import numpy as np
import matplotlib.pyplot as plt
from matplotlib import style

style.use("ggplot")
from sklearn import svm

x = [1, 5, 1.5, 8, 1, 9]
y = [2, 8, 1.8, 8, 0.6, 11]

plt.scatter(x,y)
plt.show()

X = np.array([[1,2],
             [5,8],
             [1.5,1.8],
             [8,8],
             [1,0.6],
             [9,11]])

y = [0,1,0,1,0,1]

clf = svm.SVC(kernel='linear', C = 1.0)
clf.fit(X,y)

test = np.array([0.58, 0.76])
print test       # Produces: [ 0.58  0.76]
print test.shape # Produces: (2,) meaning 2 rows, 1 col

test = test.reshape(1, -1)
print test       # Produces: [[ 0.58  0.76]]
print test.shape # Produces (1, 2) meaning 1 row, 2 cols

print(clf.predict(test)) # Produces [0], as expected

Solution 3 - Python

I use the below approach.

reg = linear_model.LinearRegression()
reg.fit(df[['year']],df.income)

reg.predict([[2136]])

 

Solution 4 - Python

I faced the same issue except that the data type of the instance I wanted to predict was a panda.Series object.

Well I just needed to predict one input instance. I took it from a slice of my data.

df = pd.DataFrame(list(BiogasPlant.objects.all()))
test = df.iloc[-1:]       # sliced it here

In this case, you'll need to convert it into a 1-D array and then reshape it.

 test2d = test.values.reshape(1,-1)

From the docs, values will convert Series into a numpy array.

Solution 5 - Python

I faced the same problem. You just have to make it an array and moreover you have to put double squared brackets to make it a single element of the 2D array as first bracket initializes the array and the second makes it an element of that array.

So simply replace the last statement by:

print(clf.predict(np.array[[0.58,0.76]]))

Solution 6 - Python

Just insert the argument between a double square bracket:

regressor.predict([[values]])

that worked for me

Solution 7 - Python

I was facing the same issue earlier but I have somehow found the solution, You can try reg.predict([[3300]]).

The API used to allow scalar value but now you need to give a 2D array.

Solution 8 - Python

With one feature my Dataframe list converts to a Series. I had to convert it back to a Dataframe list and it worked.

if type(X) is Series:
    X = X.to_frame()

Solution 9 - Python

Just enclose your numpy object with two square brackets or vice versa.

For example:

If initially your x = [8,9,12,7,5]

change it to x = [ [8,9,12,7,5] ].

That should fix the dimension issue

Solution 10 - Python

You can do it like this:

np.array(x)[:, None]

Solution 11 - Python

The X and Y matrix of Independent Variable and Dependent Variable respectively to DataFrame from int64 Type so that it gets converted from 1D array to 2D array.. i.e X=pd.DataFrame(X) and Y=pd.dataFrame(Y) where pd is of pandas class in python. and thus feature scaling in-turn doesn't lead to any error!

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionJonTargaryenView Question on Stackoverflow
Solution 1 - PythonOfer SadanView Answer on Stackoverflow
Solution 2 - Pythonstackoverflowuser2010View Answer on Stackoverflow
Solution 3 - PythonVikas RathourView Answer on Stackoverflow
Solution 4 - PythondevsawView Answer on Stackoverflow
Solution 5 - PythonSatyam MittalView Answer on Stackoverflow
Solution 6 - PythonCamunatasView Answer on Stackoverflow
Solution 7 - PythonFASIH AHMEDView Answer on Stackoverflow
Solution 8 - PythonsamuelruView Answer on Stackoverflow
Solution 9 - PythonMustapha BabatundeView Answer on Stackoverflow
Solution 10 - PythonMiguel TomásView Answer on Stackoverflow
Solution 11 - PythonChahat AgarwalView Answer on Stackoverflow