element with the max height from a set of elements

Jquery

Jquery Problem Overview


I have a set of div elements. In jQuery, I would like to be able to find out the div with the maximum height and also the height of that div. For instance:

<div>
<div class="panel">
Line 1
Line 2
</div>
<div class="panel">
Line 1<br/>
Line 2<br/>
Line 3<br/>
Line 4<br/>
</div>
<div class="panel">
Line 1
</div>
<div class="panel">
Line 1
Line 2
</div>
</div>

By looking at the above, we know that the 2nd div (with 4 Lines) has the maximum height of all. How do I find this out? Could someone please help?

So far I've tried:

$("div.panel").height() which returns the height of the 1st div.

Jquery Solutions


Solution 1 - Jquery

Use .map() and Math.max.

var maxHeight = Math.max.apply(null, $("div.panel").map(function ()
{
    return $(this).height();
}).get());

If that's confusing to read, this might be clearer:

var heights = $("div.panel").map(function ()
    {
        return $(this).height();
    }).get();
    
maxHeight = Math.max.apply(null, heights);

Solution 2 - Jquery

The html that you posted should use some <br> to actually have divs with different heights. Like this:

<div>
    <div class="panel">
      Line 1<br>
      Line 2
    </div>
    <div class="panel">
      Line 1<br>
      Line 2<br>
      Line 3<br>
      Line 4
    </div>
    <div class="panel">
      Line 1
    </div>
    <div class="panel">
      Line 1<br>
      Line 2
    </div>
</div>

Apart from that, if you want a reference to the div with the max height you can do this:

var highest = null;
var hi = 0;
$(".panel").each(function(){
  var h = $(this).height();
  if(h > hi){
     hi = h;
     highest = $(this);  
  }    
});
//highest now contains the div with the highest so lets highlight it
highest.css("background-color", "red");

Solution 3 - Jquery

If you want to reuse in multiple places:

var maxHeight = function(elems){
    return Math.max.apply(null, elems.map(function ()
    {
        return $(this).height();
    }).get());
}

Then you can use:

maxHeight($("some selector"));

Solution 4 - Jquery

function startListHeight($tag) {
  
    function setHeight(s) {
        var max = 0;
        s.each(function() {
            var h = $(this).height();
            max = Math.max(max, h);
        }).height('').height(max);
    }
  
    $(window).on('ready load resize', setHeight($tag));
}

jQuery(function($) {
    $('#list-lines').each(function() {
        startListHeight($('li', this));
    });
});

#list-lines {
    margin: 0;
    padding: 0;
}

#list-lines li {
    float: left;
    display: table;
    width: 33.3334%;
    list-style-type: none;
}

#list-lines li img {
    width: 100%;
    height: auto;
}

#list-lines::after {
    content: "";
    display: block;
    clear: both;
    overflow: hidden;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>

<ul id="list-lines">
    <li>
        <img src="http://img2.vetton.ru//upl/1000/346/138/vetton_ru_sddu7-2560x1600.jpg" alt="" />
        <br /> Line 1
        <br /> Line 2
    </li>
    <li>
        <img src="http://img2.vetton.ru//upl/1000/346/138/vetton_ru_mixwall66-2560x1600.jpg" alt="" />
        <br /> Line 1
        <br /> Line 2
        <br /> Line 3
        <br /> Line 4
    </li>
    <li>
        <img src="http://img2.vetton.ru//upl/1000/346/138/vetton_ru_sddu7-2560x1600.jpg" alt="" />
        <br /> Line 1
    </li>
    <li>
        <img src="http://img2.vetton.ru//upl/1000/346/138/vetton_ru_mixwall66-2560x1600.jpg" alt="" />
        <br /> Line 1
        <br /> Line 2
    </li>
</ul>

Solution 5 - Jquery

ul, li {
  list-style: none;
  margin: 0;
  padding: 0;
}

ul {
  display: flex;
  flex-wrap: wrap;
}

ul li {
  width: calc(100% / 3);
}

img {
  width: 100%;
  height: auto;
}

<ul>
  <li>
    <img src="http://img2.vetton.ru//upl/1000/346/138/vetton_ru_sddu7-2560x1600.jpg" alt="">
    <br> Line 1
    <br> Line 2
  </li>
  <li>
    <img src="http://img2.vetton.ru//upl/1000/346/138/vetton_ru_mixwall66-2560x1600.jpg" alt="">
    <br> Line 1
    <br> Line 2
    <br> Line 3
    <br> Line 4
  </li>
  <li>
    <img src="http://img2.vetton.ru//upl/1000/346/138/vetton_ru_sddu7-2560x1600.jpg" alt="">
    <br> Line 1
  </li>
  <li>
    <img src="http://img2.vetton.ru//upl/1000/346/138/vetton_ru_mixwall66-2560x1600.jpg" alt="">
    <br> Line 1
    <br> Line 2
  </li>
</ul>

Solution 6 - Jquery

Solution 7 - Jquery

If you were interested in sorting entirely in standard JavaScript, or without using forEach():

var panels = document.querySelectorAll("div.panel");

// You'll need to slice the node_list before using .map()
var heights = Array.prototype.slice.call(panels).map(function (panel) {
    // return an array to hold the item and its value
    return [panel, panel.offsetHeight];
}),

// Returns a sorted array
var sortedHeights = heights.sort(function(a, b) { return a[1] > b[1]});

Solution 8 - Jquery

Easiest and clearest way I'd say is:

var maxHeight = 0, maxHeightElement = null;
$('.panel').each(function(){
   if ($(this).height() > maxHeight) {
       maxHeight = $(this).height();
       maxHeightElement = $(this);
   }
});

Solution 9 - Jquery

This might be helpful, in some way. Fixing some code from @diogo

$(window).on('load',function(){

// get the maxHeight using innerHeight() function
  var maxHeight = Math.max.apply(null, $("div.panel").map(function ()                                                        {
    return $(this).innerHeight();
  }).get());
  
// Set the height to all .panel elements
  $("div.panel").height( maxHeight );
  
});

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionlshettylView Question on Stackoverflow
Solution 1 - JqueryMatt BallView Answer on Stackoverflow
Solution 2 - JqueryVincent RamdhanieView Answer on Stackoverflow
Solution 3 - JqueryDiogo GomesView Answer on Stackoverflow
Solution 4 - Jquerymaestro888View Answer on Stackoverflow
Solution 5 - Jquerymaestro888View Answer on Stackoverflow
Solution 6 - JquerymhyView Answer on Stackoverflow
Solution 7 - JqueryPaul KaneView Answer on Stackoverflow
Solution 8 - JquerydavefrassoniView Answer on Stackoverflow
Solution 9 - JqueryJessiemar PedrosaView Answer on Stackoverflow