Does Python have a toString() equivalent, and can I convert a class to String?

PythonDjango Templates

Python Problem Overview


I'm writing a ToDo list app to help myself get started with Python. The app is running on GAE and I'm storing todo items in the Data Store. I want to display everyone's items to them, and them alone. The problem is that the app currently displays all items to all users, so I can see what you write, and you see what I write. I thought casting my todo.author object to a string and seeing if it matches the user's name would be a good start, but I can't figure out how to do that.

This is what I have in my main.py

...	
user = users.get_current_user()

if user:
    nickname = user.nickname()
    todos = Todo.all()
    template_values = {'nickname':nickname, 'todos':todos}
...

def post(self):

    todo = Todo()
    todo.author = users.get_current_user()
    todo.item = self.request.get("item")
    todo.completed = False

    todo.put()		
    self.redirect('/')

In my index.html I had this originally:

<input type="text" name="item" class="form-prop" placeholder="What needs to be done?" required/>
...
 <ul>
{% for todo in todos %}
  <input type="checkbox"> {{todo.item}} <hr />
{% endfor %}
</ul>

but I'd like to display items only to the user who created them. I thought of trying

{% for todo in todos %}
	{% ifequal todo.author nickname %}
  <input type="checkbox"> {{todo.item}} <hr />
	{% endifequal %}
{% endfor %}

to no avail. The list turns up blank. I assumed it is because todo.author is not a string. Can I read the value out as a string, or can I cast the object to String?

Thanks!

Edit: Here is my Todo class

class Todo(db.Model):
    author = db.UserProperty()
    item = db.StringProperty()
    completed = db.BooleanProperty()
    date = db.DateTimeProperty(auto_now_add=True)

Will changing my author to a StringProperty effect anything negatively? Maybe I can forgo casting altogether.

Python Solutions


Solution 1 - Python

In python, the str() method is similar to the toString() method in other languages. It is called passing the object to convert to a string as a parameter. Internally it calls the __str__() method of the parameter object to get its string representation.

In this case, however, you are comparing a UserProperty author from the database, which is of type users.User with the nickname string. You will want to compare the nickname property of the author instead with todo.author.nickname in your template.

Solution 2 - Python

In Python we can use the __str__() method.

We can override it in our class like this:

class User: 
    def __init__(self):
        self.firstName = ''
        self.lastName = ''
        ...
        
    def __str__(self):
        return self.firstName + " " + self.lastName

and when running

print(user)

it will call the function __str__(self) and print the firstName and lastName

Solution 3 - Python

str() is the equivalent.

However you should be filtering your query. At the moment your query is all() Todo's.

todos = Todo.all().filter('author = ', users.get_current_user().nickname()) 

or

todos = Todo.all().filter('author = ', users.get_current_user())

depending on what you are defining author as in the Todo model. A StringProperty or UserProperty.

Note nickname is a method. You are passing the method and not the result in template values.

Solution 4 - Python

You should define the __unicode__ method on your model, and the template will call it automatically when you reference the instance.

Solution 5 - Python

In function post():

todo.author = users.get_current_user()

So, to get str(todo.author), you need str(users.get_current_user()). What is returned by get_current_user() function ?

If it is an object, check does it contain a str()" function?

I think the error lies there.

Solution 6 - Python

Another way is using the __dict__ special attribute, for example:

str(user.__dict__)

or

print(user.__dict__)

More information about special attributes here

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionAmru E.View Question on Stackoverflow
Solution 1 - PythonJeff LockhartView Answer on Stackoverflow
Solution 2 - PythonAmirouche ZeggaghView Answer on Stackoverflow
Solution 3 - PythonTim HoffmanView Answer on Stackoverflow
Solution 4 - PythonDaniel RosemanView Answer on Stackoverflow
Solution 5 - PythonsinhayashView Answer on Stackoverflow
Solution 6 - PythonVitaly OlegovitchView Answer on Stackoverflow