does Any == Object

Kotlin

Kotlin Problem Overview


The following code in kotlin:

Any().javaClass

Has value of java.lang.Object. Does that mean Any and Object are the same class? What are their relations?

Kotlin Solutions


Solution 1 - Kotlin

No.

From the Kotlin docs (Emphasis mine)

> All classes in Kotlin have a common superclass Any, that is a default > super for a class with no supertypes declared: > > > class Example // Implicitly inherits from Any > > Any is not java.lang.Object; in particular, it does not have any > members other than equals(), hashCode() and toString(). Please > consult the Java interoperability section for more details.

Further, from the section on mapped types we find:

> Kotlin treats some Java types specially. Such types are not loaded from > Java “as is”, but are mapped to corresponding Kotlin types. The mapping > only matters at compile time, the runtime representation remains > unchanged. Java’s primitive types are mapped to corresponding Kotlin > types (keeping platform types in mind): > > ... > > java.lang.Object kotlin.Any!

This says that at runtime java.lang.Object and kotlin.Any! are treated the same. But the ! also means that the type is a platform type, which has implication with respect to disabling null checks etc.

> Any reference in Java may be null, which makes Kotlin’s requirements of > strict null-safety impractical for objects coming from Java. Types of > Java declarations are treated specially in Kotlin and called platform > types. Null-checks are relaxed for such types, so that safety guarantees > for them are the same as in Java (see more below). > > ... > > When we call methods on variables of platform types, Kotlin does not > issue nullability errors at compile time, but the call may fail at > runtime, because of a null-pointer exception or an assertion that Kotlin > generates to prevent nulls from propagating:

Solution 2 - Kotlin

Kotlin compiler treats kotlin.Any and java.lang.Object as two different types, but at runtime they are represented with the same java.lang.Object class.

javaClass property returns the runtime class of an instance, so that's why you get the same java.lang.Object class in both cases.

There are also other types which are different at compile time, but the same at runtime; they are listed in the Mapped types section of the documentation.

Solution 3 - Kotlin

In fact, there is no java.lang.Object in aspect of Kotlin lang, so you certainly cannot say Any is Object. You can only say Any takes the place of Object in Kotlin.

Solution 4 - Kotlin

It's exactly the same. It just blocks the attributes that Kotlin doesn't want:

fun main() {
    val any = Any()//java Object
    val obj = Object()//java Object
    println(any::class)//Object class
    println(obj::class)//Object class
}

smali:

fun test(aaaaa: Any) {
}
  public final static test(Ljava/lang/Object;)V
    // annotable parameter count: 1 (visible)
    // annotable parameter count: 1 (invisible)
    @Lorg/jetbrains/annotations/NotNull;() // invisible, parameter 0
   L0
    ALOAD 0
    LDC "aaaaa"
    INVOKESTATIC kotlin/jvm/internal/Intrinsics.checkNotNullParameter (Ljava/lang/Object;Ljava/lang/String;)V
   L1
    LINENUMBER 4 L1
    RETURN
   L2
    LOCALVARIABLE aaaaa Ljava/lang/Object; L0 L2 0
    MAXSTACK = 2
    MAXLOCALS = 1

  @Lkotlin/Metadata;(mv={1, 4, 2}, bv={1, 0, 3}, k=2, d1={"\u0000\u000e\n\u0000\n\u0002\u0010\u0002\n\u0000\n\u0002\u0010\u0000\n\u0000\u001a\u000e\u0010\u0000\u001a\u00020\u00012\u0006\u0010\u0002\u001a\u00020\u0003\u00a8\u0006\u0004"}, d2={"test", "", "aaaaa", "", "SPWrapper.app"})
  // compiled from: T.kt
}

Solution 5 - Kotlin

"Any" is the analogue of java.lang.Object: a superclass of all classes in Kotlin.

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionoshaiView Question on Stackoverflow
Solution 1 - KotlinMichael AndersonView Answer on Stackoverflow
Solution 2 - KotlinIlyaView Answer on Stackoverflow
Solution 3 - KotlinWizard Z.View Answer on Stackoverflow
Solution 4 - Kotlin王 能View Answer on Stackoverflow
Solution 5 - KotlinGulzar BhatView Answer on Stackoverflow