Does a natural comparator exist in the standard api?

JavaComparatorComparable

Java Problem Overview


I need a comparator as part of a strategy pattern that can either use the natural ordering of the objects or some custom ordering. For the natural ordering case, I wrote a simple comparator:

private static class NaturalComparator<T extends Comparable<? super T>> implements Comparator<T> {
    @Override
    public int compare(T o1, T o2) {
        return o1.compareTo(o2);
    }
}

Seems simple enough, but I was wondering if anyone knew of one in the standard API. I looked at TreeMap, and it does it without such a class, so when that code was written, the apparent answer would be no, but perhaps it was added later.

Java Solutions


Solution 1 - Java

Added to Comparator in Java 8:

static <T extends Comparable<? super T>> Comparator<T> naturalOrder()

Use it like this, for example:

Comparator<Double> natural = Comparator.<Double>naturalOrder();
return natural.compare(1.0, 1.1));

Solution 2 - Java

Yes, the JDK definitely has it! Here it is:

Collections.reverseOrder(Collections.reverseOrder())

Just kidding. (But it's true. (Just don't actually use that. (Ever.)))

Solution 3 - Java

JDK does not have it, however it is called ComparableComparator and it exists in many frameworks such as Spring, Apache Commons, Hibernate and many others

Solution 4 - Java

I am not familiar with a default comparator in Java, but obviously, Comparator to compareTo is often a mere wrapper.

There is no general of "natural ordering" in the standard API, although certain built in types, like numbers, have an implementation of compareTo which then becomes their natural ordering.

TreeMap and TreeSet and all these should throw a RuntimeException if the object you put in does not implement Comparable. Thus, for example, you could throw in strings or numbers but not another collection.

The code of TreeMap does not use a comparator if one is not available - it uses compareTo instead. To use compareTo, it does a cast to Comparable, which is the source of the exceptions.

    private int compare(K k1, K k2) {
      return (comparator==null ? ((Comparable <K>)k1).compareTo(k2)
                                : comparator.compare((K)k1, (K)k2));
  }

Solution 5 - Java

I think if a class has a natural ordering, it is more usual in Java for it to implement Comparable rather than have a Comparator implementation for each class.

Thus, if the objects in question have a natural ordering defined, they must implement Comparable and have the compareTo method defined. No need to go looking for a Comparator. Most classes in java.util take either an optional Comparator if there is any specific ordering to be imposed, or simply try to call compareTo on the objects if there is no other ordering specified.

So, long story short: Implement Comparable whenever you want to impose a natural ordering on a class, only use a Comparator when you want something other than the natural ordering.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionYishaiView Question on Stackoverflow
Solution 1 - JavaJulienView Answer on Stackoverflow
Solution 2 - JavaKevin BourrillionView Answer on Stackoverflow
Solution 3 - JavaEugene RyzhikovView Answer on Stackoverflow
Solution 4 - JavaUriView Answer on Stackoverflow
Solution 5 - JavaMAKView Answer on Stackoverflow