Django Templating: how to access properties of the first item in a list

DjangoDjango Templates

Django Problem Overview


Pretty simple. I have a Python list that I am passing to a Django template.

I can specifically access the first item in this list using

{{ thelist|first }}

However, I also want to access a property of that item... ideally you'd think it would look like this:

{{ thelist|first.propertyName }}

But alas, it does not.

Is there any template solution to this, or am I just going to find myself passing an extra template variable...

Django Solutions


Solution 1 - Django

You can access any item in a list via its index number. In a template this works the same as any other property lookup:

{{ thelist.0.propertyName }}

Solution 2 - Django

You can combine the with template tag with the first template filter to access the property.

{% with thelist|first as first_object %}
    {{ first_object.propertyname }}
{% endwith %}

Solution 3 - Django

If you're trying to access a manytomany field, remember to add all, so it will look like object.m2m_field.all.0.item_property

Solution 4 - Django

a potentially clearer answer/syntax for accessing a ManyToManyField property in an object list provided to the django template would look like this:

{{ object_list.0.m2m_fieldname.all.0.item_property }}

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionM. RyanView Question on Stackoverflow
Solution 1 - DjangoDaniel RosemanView Answer on Stackoverflow
Solution 2 - DjangoMark LavinView Answer on Stackoverflow
Solution 3 - Djangouser1115538View Answer on Stackoverflow
Solution 4 - DjangoRealScatmanView Answer on Stackoverflow