Disabling buttons on react native

I'm making an android app using react native and I've used TouchableOpacity component to create buttons.
I use a text input component to accept text from the user and the button should only be enabled once the text input matches a certain string.
I can think of a way to do this by initially rendering the button without the TouchableOpactiy wrapper and re-rendering with the wrapper once the input string matches.
But I'm guessing there is a much better way to do this. Can anyone help?

TouchableOpacity extends TouchableWithoutFeedback, so you can just use the disabled property :

<TouchableOpacity disabled={true}>
  <Text>I'm disabled</Text>
</TouchableOpacity>

React Native TouchableWithoutFeedback #disabled documentation

The new Pressable API has a disabled option too :

<Pressable disable={true}>
  {({ pressed }) => (
    <Text>I'm disabled</Text>
  )}
</Pressable>

Just do this

<TouchableOpacity activeOpacity={disabled ? 1 : 0.7} onPress={!disabled && onPress}>
  <View>
    <Text>{text}</Text>
  </View>
</TouchableOpacity>

This seems like the kind of thing that could be solved using a Higher Order Component. I could be wrong though because I'm struggling to understand it 100% myself, but maybe it'll be helpful to you (here's a couple links)...

• http://www.bennadel.com/blog/2888-experimenting-with-higher-order-components-in-reactjs.htm
• http://jamesknelson.com/structuring-react-applications-higher-order-components/

this native-base there is solution:

<Button
    block
    disabled={!learnedWordsByUser.length}
    style={{ marginTop: 10 }}
    onPress={learnedWordsByUser.length && () => {
      onFlipCardsGenerateNewWords(learnedWordsByUser)
      onFlipCardsBtnPress()
    }}
>
    <Text>Let's Review</Text>
</Button>

So it is very easy to disable any button in react native

<TouchableOpacity disabled={true}>
    <Text> 
          This is disabled button
   </Text>
</TouchableOpacity>

disabled is a prop in react native and when you set its value to "true" it will disable your button

Happy Cooding

TouchableOpacity receives activeOpacity. You can do something like this

<TouchableOpacity activeOpacity={enabled ? 0.5 : 1}>
</TouchableOpacity>

So if it's enabled, it will look normal, otherwise, it will look just like touchablewithoutfeedback.

To disable Text you have to set the opacity:0 in Text style like this:

<TouchableOpacity style={{opacity:0}}>
  <Text>I'm disabled</Text>
</TouchableOpacity>

You can build an CustButton with TouchableWithoutFeedback, and set the effect and logic you want with onPressIn, onPressout or other props.

I was able to fix this by putting a conditional in the style property.

const startQuizDisabled = () => props.deck.cards.length === 0;

<TouchableOpacity
  style={startQuizDisabled() ? styles.androidStartQuizDisable : styles.androidStartQuiz}
  onPress={startQuiz}
  disabled={startQuizDisabled()}
>
  <Text 
    style={styles.androidStartQuizBtn} 
  >Start Quiz</Text>
</TouchableOpacity>

const styles = StyleSheet.create({
androidStartQuiz: {
    marginTop:25,
    backgroundColor: "green",
    padding: 10,
    borderRadius: 5,
    borderWidth: 1
},
androidStartQuizDisable: {
    marginTop:25,
    backgroundColor: "green",
    padding: 10,
    borderRadius: 5,
    borderWidth: 1,
    opacity: 0.4
},
androidStartQuizBtn: {
    color: "white",
    fontSize: 24
}
})

I think the most efficient way is to wrap the touchableOpacity with a view and add the prop pointerEvents with a style condition.

<View style={this.state.disabled && commonStyles.buttonDisabled}        
      pointerEvents={this.state.disabled ? "none" : "auto"}>
  <TouchableOpacity
    style={styles.connectButton}>
  <Text style={styles.connectButtonText}">CONNECT </Text>
  </TouchableOpacity>
</View>

CSS:

buttonDisabled: {
    opacity: 0.7
  }

Here's my work around for this I hope it helps :

<TouchableOpacity
    onPress={() => {
        this.onSubmit()
    }}
    disabled={this.state.validity}
    style={this.state.validity ?
          SignUpStyleSheet.inputStyle :
          [SignUpStyleSheet.inputAndButton, {opacity: 0.5}]}>
    <Text style={SignUpStyleSheet.buttonsText}>Sign-Up</Text>
</TouchableOpacity>

in SignUpStyleSheet.inputStyle holds the style for the button when it disabled or not, then in style={this.state.validity ? SignUpStyleSheet.inputStyle : [SignUpStyleSheet.inputAndButton, {opacity: 0.5}]} I add the opacity property if the button is disabled.

You can enable and disable button or by using condition or directly by default it will be disable : true

 // in calling function of button 
    handledisableenable()
        {
         // set the state for disabling or enabling the button
           if(ifSomeConditionReturnsTrue)
            {
                this.setState({ Isbuttonenable : true })
            }
          else
          {
             this.setState({ Isbuttonenable : false})
          }
        }

<TouchableOpacity onPress ={this.handledisableenable} disabled= 
     {this.state.Isbuttonenable}>
           
    <Text> Button </Text>
</TouchableOpacity>

Use disabled true property

<TouchableOpacity disabled={true}> </TouchableOpacity>

Here is the simplest solution ever:

You can add onPressOut event to the TouchableOpcaity and do whatever you want to do. It will not let user to press again until onPressOut is done

You can use the disabled prop in TouchableOpacity when your input does not match the string

<TouchableOpacity disabled = { stringMatched ? false : true }>
    <Text>Some Text</Text>
</TouchableOpacity>

where stringMatched is a state.