Difference of two date time in sql server
SqlSql ServerDatetimeSql Problem Overview
Is there any way to take the difference between two datetime in sql server?
For example, my dates are
2010-01-22 15:29:55.0902010-01-22 15:30:09.153
So, the result should be 14.063 seconds.
Sql Solutions
Solution 1 - Sql
Just a caveat to add about DateDiff, it counts the number of times you pass the boundary you specify as your units, so is subject to problems if you are looking for a precise timespan. e.g.
select datediff (m, '20100131', '20100201')
gives an answer of 1, because it crossed the boundary from January to February, so even though the span is 2 days, datediff would return a value of 1 - it crossed 1 date boundary.
select datediff(mi, '2010-01-22 15:29:55.090' , '2010-01-22 15:30:09.153')
Gives a value of 1, again, it passed the minute boundary once, so even though it is approx 14 seconds, it would be returned as a single minute when using Minutes as the units.
Solution 2 - Sql
SELECT DATEDIFF (MyUnits, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
Substitute "MyUnits" based on DATEDIFF on MSDN
Solution 3 - Sql
SELECT DATEDIFF(day, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
Replace day with other units you want to get the difference in, like second, minute etc.
Solution 4 - Sql
I can mention four important functions of MS SQL Server that can be very useful:
-
The function DATEDIFF() is responsible to calculate differences between two dates, the result could be "year quarter month dayofyear day week hour minute second millisecond microsecond nanosecond", specified on the first parameter (datepart):
select datediff(day,'1997-10-07','2011-09-11')
-
You can use the function GETDATE() to get the actual time and calculate differences of some date and actual date:
select datediff(day,'1997-10-07', getdate() )
-
Another important function is DATEADD(), used to convert some value in datetime using the same datepart of the datediff, that you can add (with positive values) or substract (with negative values) to one base date:
select DATEADD(day, 45, getdate()) -- actual datetime adding 45 days select DATEADD( s,-638, getdate()) -- actual datetime subtracting 10 minutes and 38 seconds
-
The function CONVERT() was made to format the date like you need, it is not parametric function, but you can use part of the result to format the result like you need:
select convert( char(8), getdate() , 8) -- part hh:mm:ss of actual datetime select convert( varchar, getdate() , 112) -- yyyymmdd select convert( char(10), getdate() , 20) -- yyyy-mm-dd limited by 10 characters
DATETIME cold be calculated in seconds and one interesting result mixing these four function is to show a formated difference um hours, minutes and seconds (hh:mm:ss) between two dates:
declare @date1 datetime, @date2 datetime
set @date1=DATEADD(s,-638,getdate())
set @date2=GETDATE()
select convert(char(8),dateadd(s,datediff(s,@date1,@date2),'1900-1-1'),8)
... the result is 00:10:38 (638s = 600s + 38s = 10 minutes and 38 seconds)
Another example:
select distinct convert(char(8),dateadd(s,datediff(s, CRDATE , GETDATE() ),'1900-1-1'),8) from sysobjects order by 1
Solution 5 - Sql
I tried this way and it worked. I used SQL Server version 2016
SELECT DATEDIFF(MILLISECOND,'2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')/1000.00;
Different DATEDIFF Functions are:
SELECT DATEDIFF(year, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(quarter, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(month, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(dayofyear, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(day, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(week, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(hour, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(minute, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(second, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(millisecond, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
Ref: https://docs.microsoft.com/en-us/sql/t-sql/functions/datediff-transact-sql?view=sql-server-2017
Solution 6 - Sql
Ok we all know the answer involves DATEDIFF(). But that gives you only half the result you may be after. What if you want to get the results in human-readable format, in terms of Minutes and Seconds between two DATETIME values?
The CONVERT(), DATEADD() and of course DATEDIFF() functions are perfect for a more easily readable result that your clients can use, instead of a number.
i.e.
CONVERT(varchar(5), DATEADD(minute, DATEDIFF(MINUTE, date1, date2), 0), 114)
This will give you something like:
> HH:MM
If you want more precision, just increase the VARCHAR().
CONVERT(varchar(12), DATEADD(minute, DATEDIFF(MINUTE, date1, date2), 0), 114)
> HH:MM.SS.MS
Solution 7 - Sql
Internally in SQL Server dates are stored as 2 integers. The first integer is the number of dates before or after the base date (1900/01/01). The second integer stores the number of clock ticks after midnight, each tick is 1/300 of a second.
Because of this, I often find the simplest way to compare dates is to simply substract them. This handles 90% of my use cases. E.g.,
select date1, date2, date2 - date1 as DifferenceInDays
from MyTable
...
When I need an answer in units other than days, I will use DateDiff.
Solution 8 - Sql
There are a number of ways to look at a date difference, and more when comparing date/times. Here's what I use to get the difference between two dates formatted as "HH:MM:SS":
ElapsedTime AS
RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
I used this for a calculated column, but you could trivially rewrite it as a UDF or query calculation. Note that this logic rounds down fractional seconds; 00:00.00 to 00:00.999 is considered zero seconds, and displayed as "00:00:00".
If you anticipate that periods may be more than a few days long, this code switches to D:HH:MM:SS format when needed:
ElapsedTime AS
CASE WHEN DATEDIFF(S, StartDate, EndDate) >= 359999
THEN
CAST(DATEDIFF(S, StartDate, EndDate) / 86400 AS VARCHAR(7)) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 86400 / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
ELSE
RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
END
Solution 9 - Sql
The following query should give the exact stuff you are looking out for.
select datediff(second, '2010-01-22 15:29:55.090' , '2010-01-22 15:30:09.153')
Here is the link from MSDN for what all you can do with datediff function . https://msdn.microsoft.com/en-us/library/ms189794.aspx
Solution 10 - Sql
SELECT DATEDIFF(yyyy, '2011/08/25', '2017/08/25') AS DateDiff
It's gives you difference between two dates in Year
Here (2017-2011)=6 as a result
Syntax:
DATEDIFF(interval, date1, date2)
Solution 11 - Sql
Use This for DD:MM:SS:
SELECT CONVERT(VARCHAR(max), Datediff(dd, '2019-08-14 03:16:51.360',
'2019-08-15 05:45:37.610'))
+ ':'
+ CONVERT(CHAR(8), Dateadd(s, Datediff(s, '2019-08-14 03:16:51.360',
'2019-08-15 05:45:37.610'), '1900-1-1'), 8)
Solution 12 - Sql
So this isn't my answer but I just found this while searching around online for a question like this as well. This guy set up a procedure to calculate hours, minutes and seconds. The link and the code:
--Creating Function
If OBJECT_ID('UFN_HourMinuteSecond') Is Not Null
Drop Function dbo.UFN_HourMinuteSecond
Go
Exec(
'Create Function dbo.UFN_HourMinuteSecond
(
@StartDateTime DateTime,
@EndDateTime DateTime
) Returns Varchar(10)
As
Begin
Declare @Seconds Int,
@Minute Int,
@Hour Int,
@Elapsed Varchar(10)
Select @Seconds = ABS(DateDiff(SECOND ,@StartDateTime,@EndDateTime))
If @Seconds >= 60
Begin
select @Minute = @Seconds/60
select @Seconds = @Seconds%60
If @Minute >= 60
begin
select @hour = @Minute/60
select @Minute = @Minute%60
end
Else
Goto Final
End
Final:
Select @Hour = Isnull(@Hour,0), @Minute = IsNull(@Minute,0), @Seconds = IsNull(@Seconds,0)
select @Elapsed = Cast(@Hour as Varchar) + '':'' + Cast(@Minute as Varchar) + '':'' + Cast(@Seconds as Varchar)
Return (@Elapsed)
End'
)
Solution 13 - Sql
declare @dt1 datetime='2012/06/13 08:11:12', @dt2 datetime='2012/06/12 02:11:12'
select CAST((@dt2-@dt1) as time(0))
Solution 14 - Sql
PRINT DATEDIFF(second,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153')
Solution 15 - Sql
select
datediff(millisecond,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153') / 1000.0 as Secs
result:
Secs
14.063
Just thought I'd mention it.
Solution 16 - Sql
CREATE FUNCTION getDateDiffHours(@fdate AS datetime,@tdate as datetime) RETURNS varchar (50) AS BEGIN DECLARE @cnt int DECLARE @cntDate datetime DECLARE @dayDiff int DECLARE @dayDiffWk int DECLARE @hrsDiff decimal(18)
DECLARE @markerFDate datetime
DECLARE @markerTDate datetime
DECLARE @fTime int
DECLARE @tTime int
DECLARE @nfTime varchar(8)
DECLARE @ntTime varchar(8)
DECLARE @nfdate datetime
DECLARE @ntdate datetime
-------------------------------------
--DECLARE @fdate datetime
--DECLARE @tdate datetime
--SET @fdate = '2005-04-18 00:00:00.000'
--SET @tdate = '2005-08-26 15:06:07.030'
-------------------------------------
DECLARE @tempdate datetime
--setting weekends
SET @fdate = dbo.getVDate(@fdate)
SET @tdate = dbo.getVDate(@tdate)
--RETURN @fdate
SET @fTime = datepart(hh,@fdate)
SET @tTime = datepart(hh,@tdate)
--RETURN @fTime
if datediff(hour,@fdate, @tdate) <= 9
RETURN(convert(varchar(50),0) + ' Days ' + convert(varchar(50),datediff(hour,@fdate, @tdate))) + ' Hours'
else
--setting working hours
SET @nfTime = dbo.getV00(convert(varchar(2),datepart(hh,@fdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,@fdate))) + ':'+ dbo.getV00(convert(varchar(2),datepart(ss,@fdate)))
SET @ntTime = dbo.getV00(convert(varchar(2),datepart(hh,@tdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,@tdate))) + ':'+ dbo.getV00(convert(varchar(2),datepart(ss,@tdate)))
IF @fTime > 17
begin
set @nfTime = '17:00:00'
end
else
begin
IF @fTime < 8
set @nfTime = '08:00:00'
end
IF @tTime > 17
begin
set @ntTime = '17:00:00'
end
else
begin
IF @tTime < 8
set @ntTime = '08:00:00'
end
-- used for working out whole days
SET @nfdate = dateadd(day,1,@fdate)
SET @ntdate = @tdate
SET @nfdate = convert(varchar,datepart(yyyy,@nfdate)) + '-' + convert(varchar,datepart(mm,@nfdate)) + '-' + convert(varchar,datepart(dd,@nfdate))
SET @ntdate = convert(varchar,datepart(yyyy,@ntdate)) + '-' + convert(varchar,datepart(mm,@ntdate)) + '-' + convert(varchar,datepart(dd,@ntdate))
SET @cnt = 0
SET @dayDiff = 0
SET @cntDate = @nfdate
SET @dayDiffWk = convert(decimal(18,2),@ntdate-@nfdate)
--select @nfdate,@ntdate
WHILE @cnt < @dayDiffWk
BEGIN
IF (NOT DATENAME(dw, @cntDate) = 'Saturday') AND (NOT DATENAME(dw, @cntDate) = 'Sunday')
BEGIN
SET @dayDiff = @dayDiff + 1
END
SET @cntDate = dateadd(day,1,@cntDate)
SET @cnt = @cnt + 1
END
--SET @dayDiff = convert(decimal(18,2),@ntdate-@nfdate) --datediff(day,@nfdate,@ntdate)
--SELECT @dayDiff
set @fdate = convert(varchar,datepart(yyyy,@fdate)) + '-' + convert(varchar,datepart(mm,@fdate)) + '-' + convert(varchar,datepart(dd,@fdate)) + ' ' + @nfTime
set @tdate = convert(varchar,datepart(yyyy,@tdate)) + '-' + convert(varchar,datepart(mm,@tdate)) + '-' + convert(varchar,datepart(dd,@tdate)) + ' ' + @ntTime
set @markerFDate = convert(varchar,datepart(yyyy,@fdate)) + '-' + convert(varchar,datepart(mm,@fdate)) + '-' + convert(varchar,datepart(dd,@fdate)) + ' ' + '17:00:00'
set @markerTDate = convert(varchar,datepart(yyyy,@tdate)) + '-' + convert(varchar,datepart(mm,@tdate)) + '-' + convert(varchar,datepart(dd,@tdate)) + ' ' + '08:00:00'
--select @fdate,@tdate
--select @markerFDate,@markerTDate
set @hrsDiff = convert(decimal(18,2),datediff(hh,@fdate,@markerFDate))
--select @hrsDiff
set @hrsDiff = @hrsDiff + convert(int,datediff(hh,@markerTDate,@tdate))
--select @fdate,@tdate
IF convert(varchar,datepart(yyyy,@fdate)) + '-' + convert(varchar,datepart(mm,@fdate)) + '-' + convert(varchar,datepart(dd,@fdate)) = convert(varchar,datepart(yyyy,@tdate)) + '-' + convert(varchar,datepart(mm,@tdate)) + '-' + convert(varchar,datepart(dd,@tdate))
BEGIN
--SET @hrsDiff = @hrsDiff - 9
Set @hrsdiff = datediff(hour,@fdate,@tdate)
END
--select FLOOR((@hrsDiff / 9))
IF (@hrsDiff / 9) > 0
BEGIN
SET @dayDiff = @dayDiff + FLOOR(@hrsDiff / 9)
SET @hrsDiff = @hrsDiff - FLOOR(@hrsDiff / 9)*9
END
--select convert(varchar(50),@dayDiff) + ' Days ' + convert(varchar(50),@hrsDiff) + ' Hours'
RETURN(convert(varchar(50),@dayDiff) + ' Days ' + convert(varchar(50),@hrsDiff)) + ' Hours'
END
Solution 17 - Sql
Sol-1:
select
StartTime
, EndTime
, CONVERT(NVARCHAR,(EndTime-StartTime), 108) as TimeDiff
from
[YourTable]
Sol-2:
select
StartTime
, EndTime
, DATEDIFF(hh, StartTime, EndTime)
, DATEDIFF(mi, StartTime, EndTime) % 60
from
[YourTable]
Sol-3:
select
DATEPART(hour,[EndTime]-[StartTime])
, DATEPART(minute,[EndTime]-[StartTime])
from
[YourTable]
Datepart works the best
Solution 18 - Sql
Please check below trick to find the date difference between two dates
DATEDIFF(DAY,ordr.DocDate,RDR1.U_ProgDate) datedifff
where you can change according your requirement as you want difference of days or month or year or time.
Solution 19 - Sql
For Me This worked Perfectly Convert(varchar(8),DATEADD(SECOND,DATEDIFF(SECOND,LogInTime,LogOutTime),0),114)
and the Output is HH:MM:SS which is shown accurately in my case.
Solution 20 - Sql
Please try
DECLARE @articleDT DATETIME;
DECLARE @nowDate DATETIME;
-- Time of the ARTICLE created
SET @articleDT = '2012-04-01 08:10:16';
-- Simulation of NOW datetime
-- (in real world you would probably use GETDATE())
SET @nowDate = '2012-04-10 11:35:36';
-- Created 9 days ago.
SELECT 'Created ' + CAST(DATEDIFF(day, @articleDT, @nowDate) AS NVARCHAR(50)) + ' days ago.';
-- Created 1 weeks, 2 days, 3 hours, 25 minutes and 20 seconds ago.
SELECT 'Created '
+ CAST(DATEDIFF(second, @articleDT, @nowDate) / 60 / 60 / 24 / 7 AS NVARCHAR(50)) + ' weeks, '
+ CAST(DATEDIFF(second, @articleDT, @nowDate) / 60 / 60 / 24 % 7 AS NVARCHAR(50)) + ' days, '
+ CAST(DATEDIFF(second, @articleDT, @nowDate) / 60 / 60 % 24 AS NVARCHAR(50)) + ' hours, '
+ CAST(DATEDIFF(second, @articleDT, @nowDate) / 60 % 60 AS NVARCHAR(50)) + ' minutes and '
+ CAST(DATEDIFF(second, @articleDT, @nowDate) % 60 AS NVARCHAR(50)) + ' seconds ago.';
Solution 21 - Sql
Check DateDiff out on Books Online.