Difference between Systemctl and service command


Apache Problem Overview

I always run my Apache server in this way:

sudo service apache2 start

But in many guides I saw commands like this:

sudo systemctl start apache2

Can somebody shortly write the difference between these commands and give me advice about what command I should use in everyday work?

Apache Solutions

Solution 1 - Apache

service operates on the files in /etc/init.d and was used in conjunction with the old init system. systemctl operates on the files in /lib/systemd. If there is a file for your service in /lib/systemd it will use that first and if not it will fall back to the file in /etc/init.d. Also If you are using OS like ubuntu-14.04 only service command will be available.

So if systemctl is available ,it will be better to use it

Solution 2 - Apache

With borrowing from this answer:

> service is an "high-level" command used for start, restart, stop and status > services in different Unixes and Linuxes. Depending on the > "lower-level" service manager, service redirects on different > binaries. > > For example, on CentOS 7 it redirects to systemctl, while on CentOS 6 > it directly called the relative /etc/init.d script. On the other > hand, in older Ubuntu releases it redirects to upstart. > > service is adequate for basic service management, while directly > calling systemctl give greater control options.

Moreover, systemctl runs services file from this path: /lib/systemd/

Solution 3 - Apache

Service started as a helper script for sysvinit an latter became a wrapper script that works regardless of having sysvinit or systemd.

Solution 4 - Apache

For my choice service is more reliable, especially in automatization tasks. It's wrapping commands for different init systems, thus you can use it for older distributions and expect the same result. And in my observation there is often no working reload command (update daemon config without process killing ) for systemd unit, when it works with service <service-name> reload normally.


All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionRoman RomanovView Question on Stackoverflow
Solution 1 - ApacheshahinView Answer on Stackoverflow
Solution 2 - ApacheBenyamin JafariView Answer on Stackoverflow
Solution 3 - ApachechomwittView Answer on Stackoverflow
Solution 4 - ApacheGennadiy BelousovView Answer on Stackoverflow