Datetime current year and month in Python
PythonDatetimePython Problem Overview
I must have the current year and month in datetime.
I use this:
datem = datetime.today().strftime("%Y-%m")
datem = datetime.strptime(datem, "%Y-%m")
Is there maybe another way?
Python Solutions
Solution 1 - Python
Try this solution:
from datetime import datetime
currentSecond= datetime.now().second
currentMinute = datetime.now().minute
currentHour = datetime.now().hour
currentDay = datetime.now().day
currentMonth = datetime.now().month
currentYear = datetime.now().year
Solution 2 - Python
Use:
from datetime import datetime
today = datetime.today()
datem = datetime(today.year, today.month, 1)
I assume you want the first of the month.
Solution 3 - Python
Use:
from datetime import datetime
current_month = datetime.now().strftime('%m') // 02 //This is 0 padded
current_month_text = datetime.now().strftime('%h') // Feb
current_month_text = datetime.now().strftime('%B') // February
current_day = datetime.now().strftime('%d') // 23 //This is also padded
current_day_text = datetime.now().strftime('%a') // Fri
current_day_full_text = datetime.now().strftime('%A') // Friday
current_weekday_day_of_today = datetime.now().strftime('%w') //5 Where 0 is Sunday and 6 is Saturday.
current_year_full = datetime.now().strftime('%Y') // 2018
current_year_short = datetime.now().strftime('%y') // 18 without century
current_second= datetime.now().strftime('%S') //53
current_minute = datetime.now().strftime('%M') //38
current_hour = datetime.now().strftime('%H') //16 like 4pm
current_hour = datetime.now().strftime('%I') // 04 pm
current_hour_am_pm = datetime.now().strftime('%p') // 4 pm
current_microseconds = datetime.now().strftime('%f') // 623596 Rarely we need.
current_timzone = datetime.now().strftime('%Z') // UTC, EST, CST etc. (empty string if the object is naive).
Reference: 8.1.7. strftime() and strptime() Behavior
Reference: strftime() and strptime() Behavior
The above things are useful for any date parsing, not only now or today. It can be useful for any date parsing.
e.g.
my_date = "23-02-2018 00:00:00"
datetime.strptime(str(my_date),'%d-%m-%Y %H:%M:%S').strftime('%Y-%m-%d %H:%M:%S+00:00')
datetime.strptime(str(my_date),'%d-%m-%Y %H:%M:%S').strftime('%m')
And so on...
Solution 4 - Python
Late answer, but you can also use:
import time
ym = time.strftime("%Y-%m")
Solution 5 - Python
>>> from datetime import date
>>> date.today().month
2
>>> date.today().year
2020
>>> date.today().day
13
Solution 6 - Python
You can write the accepted answer as a one-liner using date.replace:
datem = datetime.today().replace(day=1)
Solution 7 - Python
The question asks to use datetime specifically.
This is a way that uses datetime only:
from datetime import datetime
year = datetime.now().year
month = datetime.now().month
Solution 8 - Python
You can always use a sub-string method:
import datetime;
today = str(datetime.date.today());
curr_year = int(today[:4]);
curr_month = int(today[5:7]);
This will get you the current month and year in integer format. If you want them to be strings you simply have to remove the " int " precedence while assigning values to the variables curr_year and curr_month.
Solution 9 - Python
using the regular expression extract the date and time from the string then convert the string date to a datetimeindex using strptime
import re
s = "Audio was recorded at 21:50:00 02/07/2019 (UTC) by device 243B1F05 at gain setting 2 while battery state was 3.6V."
t = re.search(' (\d{2}:\d{2}:\d{2} \d{2}\/\d{2}\/\d{4}) ', s).group(1)
date=datetime.datetime.strptime(t,'%H:%M:%S %m/%d/%Y')
print(type(date))