Curl Command to Repeat URL Request
LinuxUrlCurlLinux Problem Overview
Whats the syntax for a linux command that hits a URL repeatedly, x number of times. I don't need to do anything with the data, I just need to replicate hitting refresh 20 times in a browser.
Linux Solutions
Solution 1 - Linux
You could use URL sequence substitution with a dummy query string (if you want to use CURL and save a few keystrokes):
curl http://www.myurl.com/?[1-20]
If you have other query strings in your URL, assign the sequence to a throwaway variable:
curl http://www.myurl.com/?myVar=111&fakeVar=[1-20]
Check out the URL section on the man page: https://curl.haxx.se/docs/manpage.html
Solution 2 - Linux
for i in `seq 1 20`; do curl http://url; done
Or if you want to get timing information back, use ab:
ab -n 20 http://url/
Solution 3 - Linux
You might be interested in Apache Bench tool which is basically used to do simple load testing.
example :
ab -n 500 -c 20 http://www.example.com/
> n = total number of request, c = number of concurrent request
Solution 4 - Linux
If you want to add an interval before executing the cron the next time you can add a sleep
> for i in {1..100}; do echo $i && curl "http://URL" >> /tmp/output.log && sleep 120; done
Solution 5 - Linux
You can use any bash looping constructs like FOR, with is compatible to Linux and Mac.
https://tiswww.case.edu/php/chet/bash/bashref.html#Looping-Constructs
In your specific case you can define N iterations, with N is a number defining how many curl executions you want.
for n in {1..N}; do curl <arguments>; done
ex:
for n in {1..20}; do curl -d @notification.json -H 'Content-Type: application/json' localhost:3000/dispatcher/notify; done