CSS gradient checkerboard pattern

I want to create a checkerboard pattern using gradients. I've found an example and modified it to my needs, however it only works with -moz prefix. When I remove the -moz prefix, the pattern is completely different.

How can I make this -moz checkerboard pattern work with unprefixed linear-gradient?

body {
  background-image:
  linear-gradient(45deg, #808080 25%, transparent 25%), 
  linear-gradient(-45deg, #808080 25%, transparent 25%),
  linear-gradient(45deg, transparent 75%, #808080 75%),
  linear-gradient(-45deg, transparent 75%, #808080 75%);
  
  background-size:20px 20px;    
  background-position:0 0, 10px 0, 10px -10px, 0px 10px;
}

Just modify the background-position like in the below snippet to get the required output. This works fine in Firefox, Chrome, Opera, IE11 and Edge.

body {
  background-image: linear-gradient(45deg, #808080 25%, transparent 25%), linear-gradient(-45deg, #808080 25%, transparent 25%), linear-gradient(45deg, transparent 75%, #808080 75%), linear-gradient(-45deg, transparent 75%, #808080 75%);
  background-size: 20px 20px;
  background-position: 0 0, 0 10px, 10px -10px, -10px 0px;
}

The problem seems to be happening because of a difference in the way the angles are handled by the -moz linear gradient and the standard one. -45deg in the -moz linear gradient seems to be equal to 135deg in the standard gradient (but changing the angle is resulting in a strange dot in the middle).

The below screenshots show the difference (both taken in the latest Firefox v44.0).

Output with -moz-linear-gradient:

Output with linear gradient:

It's 2020 and this can now be created with a single CSS gradient (if you don't need to support IE/ pre-Chromium Edge).

html {
  background: repeating-conic-gradient(#808080 0% 25%, transparent 0% 50%) 
              50% / 20px 20px
}

I wrote a detailed explanation on CSS Tricks for how this works.

The 45deg version works nicely, but can end up showing a line between the triangles at different zoom levels or on retina screens. Depending on what browsers you need to support you can also use background-blend-mode: difference (Caniuse currently shows support nearly everywhere except IE), you can tint the checks using an additional background image:

body {
    background-image: /* tint image */
                      linear-gradient(to right, rgba(192, 192, 192, 0.75), rgba(192, 192, 192, 0.75)),
                      /* checkered effect */
                      linear-gradient(to right, black 50%, white 50%),
                      linear-gradient(to bottom, black 50%, white 50%);
    background-blend-mode: normal, difference, normal;
    background-size: 2em 2em;
}

This was Chrome's implementation for when you opened an image with transparency for a while (though they later removed it in favor of just using a solid background).

body {
    background-position: 0px 0px, 10px 10px;
    background-size: 20px 20px;
    background-image: linear-gradient(45deg, #eee 25%, transparent 25%, transparent 75%, #eee 75%, #eee 100%),linear-gradient(45deg, #eee 25%, white 25%, white 75%, #eee 75%, #eee 100%);
}

Thanks Harry for the inspiration - here's an scss mixin to do that

@mixin checkers($size: 50px, $contrast: 0.07) {
  $checkerColor: rgba(#000, $contrast);
  $angle: 45deg;
  $tp: 25%;

  background-image: linear-gradient($angle, $checkerColor $tp, transparent $tp),
    linear-gradient(-$angle, $checkerColor $tp, transparent $tp),
    linear-gradient($angle, transparent 3 * $tp, $checkerColor 3 * $tp),
    linear-gradient(-$angle, transparent 3 * $tp, $checkerColor 3 * $tp);
  background-size: $size $size;
  background-position: 0 0, 0 $size/2, $size/2 -1 * $size/2, -1 * $size/2 0;
}