Like this:

    name=$(date &#39;+%Y-%m-%d&#39;)
    tar -zcvf &quot;$name.tar.gz&quot; code

or even in one line:
    
    tar -zcvf &quot;$(date &#39;+%Y-%m-%d&#39;).tar.gz&quot; code
  
Drop ``-z`` flag if you want ``.tar`` instead of ``.tar.gz``.

Use ``%y`` instead of ``%Y`` if you want just 2 digits of a year (``17`` instead of ``2017``).

``$()`` is used for [command substitution](http://wiki.bash-hackers.org/syntax/expansion/cmdsubst).

    tar -zcvf &quot;$(date &#39;+%F&#39;).tar.gz&quot; code-path

will produce full date; same as `%Y-%m-%d`. (see `man date` follow by `/`) to search and `%F`.

For example, it will generate:

    2015-07-21.tar.gz

If `code-path` is a directory it will compress and archive all the files in it.

On BSD System you may need to use it like this:

    /usr/bin/tar -czvf /home/user/backup-`(date +%y-%m-%d)`.tar.gz /some/file.txt



[root@node2rhel75:~]# tar -jcf /var/log/lvm_etc_backup-`(date +%F_%H-%M_%p)`.tar.bz2 /etc/lvm/; ls -lh /var/log/

tar: Removing leading `/&#39; from member names

-rw-r--r--  1 root   root     46 Jul 13 02:57 lvm_etc_backup-2021-07-13_02-57_AM.tar.bz2

[root@node2rhel75:~]# 

I am  trying to change the background of this SVG code to transparent without success. I&#39;m new to SVG and somehow I can&#39;t find the solution on google; can anybody help?

demo:http://jsfiddle.net/kougiland/SzfSJ/1/


&lt;!-- begin snippet: js hide: false console: true babel: false --&gt;

&lt;!-- language: lang-html --&gt;

    &lt;svg xmlns=&quot;http://www.w3.org/2000/svg&quot; width=&quot;300px&quot; height=&quot;100px&quot; viewBox=&quot;0 0 300 100&quot;&gt;
      &lt;rect x=&quot;0&quot; y=&quot;0&quot; width=&quot;300&quot; height=&quot;100&quot; stroke=&quot;transparent&quot; stroke-width=&quot;1&quot; /&gt;
      &lt;circle cx=&quot;0&quot; cy=&quot;50&quot; r=&quot;15&quot; fill=&quot;blue&quot; stroke=&quot;transparent&quot; stroke-width=&quot;1&quot;&gt;
        &lt;animateMotion path=&quot;M 0 0 H 300 Z&quot; dur=&quot;3s&quot; repeatCount=&quot;indefinite&quot; /&gt;
      &lt;/circle&gt;

      &lt;circle id=&quot;rotatingBall&quot; cx=&quot;0&quot; cy=&quot;50&quot; r=&quot;15&quot; fill=&quot;green&quot; stroke=&quot;transparent&quot; stroke-width=&quot;1&quot; opacity=&quot;0.8&quot;&gt;&lt;/circle&gt;
      &lt;animateTransform xlink:href=&quot;#rotatingBall&quot; attributeName=&quot;transform&quot; begin=&quot;0s&quot; dur=&quot;2s&quot; type=&quot;rotate&quot; from=&quot;0 20 20&quot; to=&quot;360 100 60&quot; repeatCount=&quot;indefinite&quot; /&gt;
    &lt;/svg&gt;

&lt;!-- end snippet --&gt;



SVG transparent background web

I&#39;m confused in `join()` method used in Threads in Java. In the following code:

    // Using join() to wait for threads to finish.
    class NewThread implements Runnable {

        String name; // name of thread
        Thread t;

        NewThread(String threadname) {
            name = threadname;
            t = new Thread(this, name);
            System.out.println(&quot;New thread: &quot; + t);
            t.start(); // Start the thread
        }
    // This is the entry point for thread.

        public void run() {
            try {
                for (int i = 5; i &gt; 0; i--) {
                    System.out.println(name + &quot;: &quot; + i);
                    Thread.sleep(1000);
                }
            } catch (InterruptedException e) {
                System.out.println(name + &quot; interrupted.&quot;);
            }
            System.out.println(name + &quot; exiting.&quot;);
        }
    }

    class DemoJoin {

        public static void main(String args[]) {
            NewThread ob1 = new NewThread(&quot;One&quot;);
            NewThread ob2 = new NewThread(&quot;Two&quot;);
            NewThread ob3 = new NewThread(&quot;Three&quot;);
            System.out.println(&quot;Thread One is alive: &quot;
                    + ob1.t.isAlive());
            System.out.println(&quot;Thread Two is alive: &quot;
                    + ob2.t.isAlive());
            System.out.println(&quot;Thread Three is alive: &quot;
                    + ob3.t.isAlive());
    // wait for threads to finish
            try {
                System.out.println(&quot;Waiting for threads to finish.&quot;);
                ob1.t.join();
                ob2.t.join();
                ob3.t.join();
            } catch (InterruptedException e) {
                System.out.println(&quot;Main thread Interrupted&quot;);
            }
            System.out.println(&quot;Thread One is alive: &quot;
                    + ob1.t.isAlive());
            System.out.println(&quot;Thread Two is alive: &quot;
                    + ob2.t.isAlive());
            System.out.println(&quot;Thread Three is alive: &quot;
                    + ob3.t.isAlive());
            System.out.println(&quot;Main thread exiting.&quot;);
        }
    }

Sample output from this program is shown here:

    New thread: Thread[One,5,main]
    New thread: Thread[Two,5,main]
    New thread: Thread[Three,5,main]
    Thread One is alive: true
    Thread Two is alive: true
    Thread Three is alive: true
    Waiting for threads to finish.
    One: 5
    Two: 5
    Three: 5
    One: 4
    Two: 4
    Three: 4
    One: 3
    Two: 3
    Three: 3
    One: 2
    Two: 2
    Three: 2
    One: 1
    Two: 1
    Three: 1
    Two exiting.
    Three exiting.
    One exiting.
    Thread One is alive: false
    Thread Two is alive: false
    Thread Three is alive: false
    Main thread Exiting

In the above code :

1. I&#39;m not able to understand the flow of execution of the program, And when `ob1` is created then the constructor is called where  `t.start()` is written but still `run()` method is not executed rather `main()` method continues execution. So why is this happening?

2. `join()` method is used to wait until the thread on which it is called does not terminates, but here in output we see alternate outputs of the thread why??

And if the use of `join` is this then what is the use of `synchronized`??

I know I&#39;m missing a basic concept here, but I&#39;m not able to figure it out so please help.

Java Multithreading concept and join() method

I&#39;m trying to create a backup script in bash, to tar the contents of a folder and move the resulting file somewhere, but I don&#39;t really know how to do it.

    #!/bin/bash
    name=&quot;$date +&quot;%y-%m-%d&quot;&quot;
    tar -zcvf $name code

But the result is that the file is just named `+%y-%m-%d`. How can I change the script to name the file by the date as intended?

Intended output: `2013-08-29.tar`

Creating tar file and naming by current date

I'm trying to create a backup script in bash, to tar the contents of a folder and move the resulting file somewhere, but I don't really know how to do it.
<pre><code class="hljs language-bash">#!/bin/bash
name="$date +"%y-%m-%d""
tar -zcvf $name code
</code></pre>
But the result is that the file is just named <code>+%y-%m-%d</code>. How can I change the script to name the file by the date as intended?
Intended output: <code>2013-08-29.tar</code>

In my `.bashrc` I define a function which I can use on the command line later:

    function mycommand() {
        ssh user@123.456.789.0 cd testdir;./test.sh &quot;$1&quot;
    }


When using this command, just the `cd` command is executed on the remote host; the `test.sh` command is executed on the local host. This is because the semicolon separates two different commands: the `ssh` command and the `test.sh` command. 

I tried defining the function as follows (note the single quotes):

    function mycommand() {
        ssh user@123.456.789.0 &#39;cd testdir;./test.sh &quot;$1&quot;&#39;
    }

I tried to keep the `cd` command and the `test.sh` command together, but the argument `$1` is not resolved, independent of what I give to the function. It is always tried to execute a command

    ./test.sh $1

on the remote host. 

How do I properly define `mycommand`, so the script `test.sh` is executed on the remote host after changing into the directory `testdir`, with the ability to pass on the argument given to `mycommand` to `test.sh`?

How to execute a remote command over ssh with arguments?

I&#39;m trying to find UNIX or bash command to run a command after connecting to an ssh server.  For example:

    ssh name@ip &quot;tmux list-sessions&quot;

The above code works, it lists the sessions, but it then immediately disconnects.  Putting it in the sshrc on the server side works, but I need to be able to type it in client side.  I want to be able to run a command, it logs in, opens up the window, then runs the command I&#39;ve set. Ive tried 

    [command] | ssh name@ip

    ssh name@ip [command]

    ssh name@ip &quot;[command]&quot;

    ssh -t name@ip [command]

Run ssh and immediately execute command

I&#39;m trying to create a script that simplifies the process of creating a new user on an iOS device. Here are the steps broken down. 

```bash
fullname=&quot;USER INPUT&quot;
user=&quot;USER INPUT&quot;
group=$user
uid=1000
gid=1000
home=/var/$user
echo &quot;$group:*:$gid:$user&quot; &gt;&gt; /private/etc/group
echo &quot;$user::$uid:$gid::0:0:$fullname:$home:/bin/sh&quot; &gt;&gt; /private/etc/master.passwd
passwd $user
mkdir $home
chown $user:$group $home
```

As you can see some fields require input. How can I request input for a variable in script? 

How to read user input into a variable in Bash?

I would like my Bash script to print an error message if the required argument count is not met.

I tried the following code:

    #!/bin/bash
    echo Script name: $0
    echo $# arguments 
    if [$# -ne 1]; 
    	then echo &quot;illegal number of parameters&quot;
    fi

For some unknown reason I&#39;ve got the following error:

    test: line 4: [2: command not found

What am I doing wrong?

Check number of arguments passed to a Bash script

I have the following json file:

    {
        &quot;FOO&quot;: {
            &quot;name&quot;: &quot;Donald&quot;,
            &quot;location&quot;: &quot;Stockholm&quot;
        },
        &quot;BAR&quot;: {
            &quot;name&quot;: &quot;Walt&quot;,
            &quot;location&quot;: &quot;Stockholm&quot;
        },
        &quot;BAZ&quot;: {
            &quot;name&quot;: &quot;Jack&quot;,
            &quot;location&quot;: &quot;Whereever&quot;
        }
    }

I am using jq and want to get the &quot;name&quot; elements of the objects where &#39;location&#39; is &#39;Stockholm&#39;. 

I know I can get all names by

    cat json | jq .[] | jq .&quot;name&quot;
    &quot;Jack&quot;
    &quot;Walt&quot;
    &quot;Donald&quot;

But I can&#39;t figure out how to print only certain objects, given the value of a sub key (here: `&quot;location&quot; : &quot;Stockholm&quot;`). 

Content Type	Original Author	Original Content on Stackoverflow
Question	Anonymous Entity	View Question on Stackoverflow
Solution 1 - Bash	Aleks-Daniel Jakimenko-A.	View Answer on Stackoverflow
Solution 2 - Bash	Gianfranco P.	View Answer on Stackoverflow
Solution 3 - Bash	Kyle Coots	View Answer on Stackoverflow
Solution 4 - Bash	linuxstudent	View Answer on Stackoverflow

Creating tar file and naming by current date

Bash Problem Overview

Bash Solutions

Solution 1 - Bash

Solution 2 - Bash

Solution 3 - Bash

Solution 4 - Bash

Java Multithreading concept and join() method

SVG transparent background web

Attributions