Creating a dynamic choice field

PythonDjangoDjango FormsDjango Templates

Python Problem Overview


I'm having some trouble trying to understand how to create a dynamic choice field in django. I have a model set up something like:

class rider(models.Model):
     user = models.ForeignKey(User)
     waypoint = models.ManyToManyField(Waypoint)

class Waypoint(models.Model):
     lat = models.FloatField()
     lng = models.FloatField()

What I'm trying to do is create a choice Field whos values are the waypoints associated with that rider (which would be the person logged in).

Currently I'm overriding init in my forms like so:

class waypointForm(forms.Form):
     def __init__(self, *args, **kwargs):
          super(joinTripForm, self).__init__(*args, **kwargs)
          self.fields['waypoints'] = forms.ChoiceField(choices=[ (o.id, str(o)) for o in Waypoint.objects.all()])

But all that does is list all the waypoints, they're not associated with any particular rider. Any ideas? Thanks.

Python Solutions


Solution 1 - Python

you can filter the waypoints by passing the user to the form init

class waypointForm(forms.Form):
    def __init__(self, user, *args, **kwargs):
        super(waypointForm, self).__init__(*args, **kwargs)
        self.fields['waypoints'] = forms.ChoiceField(
            choices=[(o.id, str(o)) for o in Waypoint.objects.filter(user=user)]
        )

from your view while initiating the form pass the user

form = waypointForm(user)

in case of model form

class waypointForm(forms.ModelForm):
    def __init__(self, user, *args, **kwargs):
        super(waypointForm, self).__init__(*args, **kwargs)
        self.fields['waypoints'] = forms.ModelChoiceField(
            queryset=Waypoint.objects.filter(user=user)
        )

    class Meta:
        model = Waypoint

Solution 2 - Python

There's built-in solution for your problem: ModelChoiceField.

Generally, it's always worth trying to use ModelForm when you need to create/change database objects. Works in 95% of the cases and it's much cleaner than creating your own implementation.

Solution 3 - Python

the problem is when you do

def __init__(self, user, *args, **kwargs):
    super(waypointForm, self).__init__(*args, **kwargs)
    self.fields['waypoints'] = forms.ChoiceField(choices=[ (o.id, str(o)) for o in Waypoint.objects.filter(user=user)])

in a update request, the previous value will lost!

Solution 4 - Python

How about passing the rider instance to the form while initializing it?

class WaypointForm(forms.Form):
    def __init__(self, rider, *args, **kwargs):
      super(joinTripForm, self).__init__(*args, **kwargs)
      qs = rider.Waypoint_set.all()
      self.fields['waypoints'] = forms.ChoiceField(choices=[(o.id, str(o)) for o in qs])

# In view:
rider = request.user
form = WaypointForm(rider) 

Solution 5 - Python

You can declare the field as a first-class attribute of your form and just set choices dynamically:

class WaypointForm(forms.Form):
    waypoints = forms.ChoiceField(choices=[])

    def __init__(self, user, *args, **kwargs):
        super().__init__(*args, **kwargs)
        waypoint_choices = [(o.id, str(o)) for o in Waypoint.objects.filter(user=user)]
        self.fields['waypoints'].choices = waypoint_choices

You can also use a ModelChoiceField and set the queryset on init in a similar manner.

Solution 6 - Python

Underneath working solution with normal choice field. my problem was that each user have their own CUSTOM choicefield options based on few conditions.

class SupportForm(BaseForm):

    affiliated = ChoiceField(required=False, label='Fieldname', choices=[], widget=Select(attrs={'onchange': 'sysAdminCheck();'}))

    def __init__(self, *args, **kwargs):
    
        self.request = kwargs.pop('request', None)
        grid_id = get_user_from_request(self.request)
        for l in get_all_choices().filter(user=user_id):
            admin = 'y' if l in self.core else 'n'
            choice = (('%s_%s' % (l.name, admin)), ('%s' % l.name))
            self.affiliated_choices.append(choice)
        super(SupportForm, self).__init__(*args, **kwargs)
        self.fields['affiliated'].choices = self.affiliated_choice

Solution 7 - Python

If you need a dynamic choice field in django admin; This works for django >=2.1.

class CarAdminForm(forms.ModelForm):
    class Meta:
        model = Car

    def __init__(self, *args, **kwargs):
        super(CarForm, self).__init__(*args, **kwargs)

        # Now you can make it dynamic.
        choices = (
            ('audi', 'Audi'),
            ('tesla', 'Tesla')
        )

        self.fields.get('car_field').choices = choices

    car_field = forms.ChoiceField(choices=[])

@admin.register(Car)
class CarAdmin(admin.ModelAdmin):
    form = CarAdminForm

Hope this helps.

Solution 8 - Python

As pointed by Breedly and Liang, Ashok's solution will prevent you from getting the select value when posting the form.

One slightly different, but still imperfect, way to solve that would be:

class waypointForm(forms.Form):
    def __init__(self, user, *args, **kwargs):
        self.base_fields['waypoints'].choices = self._do_the_choicy_thing()
        super(waypointForm, self).__init__(*args, **kwargs)

This could cause some concurrence problems, though.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionwhatWhatView Question on Stackoverflow
Solution 1 - PythonAshokView Answer on Stackoverflow
Solution 2 - PythonAlexander LebedevView Answer on Stackoverflow
Solution 3 - PythonLiangView Answer on Stackoverflow
Solution 4 - PythonManoj GovindanView Answer on Stackoverflow
Solution 5 - PythonZagsView Answer on Stackoverflow
Solution 6 - PythonDeilView Answer on Stackoverflow
Solution 7 - PythonTobias ErnstView Answer on Stackoverflow
Solution 8 - PythonHaroldo_OKView Answer on Stackoverflow