Converting JSON data to Java object

JavaJsonJacksonGson

Java Problem Overview

I want to be able to access properties from a JSON string within my Java action method. The string is available by simply saying myJsonString = object.getJson(). Below is an example of what the string can look like:

{
    'title': 'ComputingandInformationsystems',
    'id': 1,
    'children': 'true',
    'groups': [{
        'title': 'LeveloneCIS',
        'id': 2,
        'children': 'true',
        'groups': [{
            'title': 'IntroToComputingandInternet',
            'id': 3,
            'children': 'false',
            'groups': []
        }]
    }]
}

In this string every JSON object contains an array of other JSON objects. The intention is to extract a list of IDs where any given object possessing a group property that contains other JSON objects. I looked at Google's Gson as a potential JSON plugin. Can anyone offer some form of guidance as to how I can generate Java from this JSON string?

Java Solutions

Solution 1 - Java

> I looked at Google's Gson as a potential JSON plugin. Can anyone offer some form of guidance as to how I can generate Java from this JSON string?

Google Gson supports generics and nested beans. The [] in JSON represents an array and should map to a Java collection such as List or just a plain Java array. The {} in JSON represents an object and should map to a Java Map or just some JavaBean class.

You have a JSON object with several properties of which the groups property represents an array of nested objects of the very same type. This can be parsed with Gson the following way:

package com.stackoverflow.q1688099;

import java.util.List;
import com.google.gson.Gson;

public class Test {

    public static void main(String... args) throws Exception {
        String json = 
            "{"
                + "'title': 'Computing and Information systems',"
                + "'id' : 1,"
                + "'children' : 'true',"
                + "'groups' : [{"
                    + "'title' : 'Level one CIS',"
                    + "'id' : 2,"
                    + "'children' : 'true',"
                    + "'groups' : [{"
                        + "'title' : 'Intro To Computing and Internet',"
                        + "'id' : 3,"
                        + "'children': 'false',"
                        + "'groups':[]"
                    + "}]" 
                + "}]"
            + "}";

        // Now do the magic.
        Data data = new Gson().fromJson(json, Data.class);

        // Show it.
        System.out.println(data);
    }

}

class Data {
    private String title;
    private Long id;
    private Boolean children;
    private List<Data> groups;

    public String getTitle() { return title; }
    public Long getId() { return id; }
    public Boolean getChildren() { return children; }
    public List<Data> getGroups() { return groups; }

    public void setTitle(String title) { this.title = title; }
    public void setId(Long id) { this.id = id; }
    public void setChildren(Boolean children) { this.children = children; }
    public void setGroups(List<Data> groups) { this.groups = groups; }
    
    public String toString() {
        return String.format("title:%s,id:%d,children:%s,groups:%s", title, id, children, groups);
    }
}

Fairly simple, isn't it? Just have a suitable JavaBean and call Gson#fromJson().

See also:

Solution 2 - Java

Bewaaaaare of Gson! It's very cool, very great, but the second you want to do anything other than simple objects, you could easily need to start building your own serializers (which isn't that hard).

Also, if you have an array of Objects, and you deserialize some json into that array of Objects, the true types are LOST! The full objects won't even be copied! Use XStream.. Which, if using the jsondriver and setting the proper settings, will encode ugly types into the actual json, so that you don't loose anything. A small price to pay (ugly json) for true serialization.

Note that Jackson fixes these issues, and is faster than GSON.

Solution 3 - Java

Oddly, the only decent JSON processor mentioned so far has been GSON.

Here are more good choices:

  • Jackson (Github) -- powerful data binding (JSON to/from POJOs), streaming (ultra fast), tree model (convenient for untyped access)
  • Flex-JSON -- highly configurable serialization

EDIT (Aug/2013):

One more to consider:

  • Genson -- functionality similar to Jackson, aimed to be easier to configure by developer

Solution 4 - Java

Or with Jackson:

String json = "...";
ObjectMapper m = new ObjectMapper();
Set<Product> products = m.readValue(json, new TypeReference<Set<Product>>() {});

Solution 5 - Java

If, by any change, you are in an application which already uses http://restfb.com/ then you can do:

import com.restfb.json.JsonObject;

...

JsonObject json = new JsonObject(jsonString);
json.get("title");

etc.

Solution 6 - Java

Easy and working java code to convert JSONObject to Java Object

Employee.java

import java.util.HashMap;
import java.util.Map;

import javax.annotation.Generated;

import com.fasterxml.jackson.annotation.JsonAnyGetter;
import com.fasterxml.jackson.annotation.JsonAnySetter;
import com.fasterxml.jackson.annotation.JsonIgnore;
import com.fasterxml.jackson.annotation.JsonInclude;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.annotation.JsonPropertyOrder;

@JsonInclude(JsonInclude.Include.NON_NULL)
@Generated("org.jsonschema2pojo")
@JsonPropertyOrder({
"id",
"firstName",
"lastName"
})
public class Employee {

@JsonProperty("id")
private Integer id;
@JsonProperty("firstName")
private String firstName;
@JsonProperty("lastName")
private String lastName;
@JsonIgnore
private Map<String, Object> additionalProperties = new HashMap<String, Object>();

/**
*
* @return
* The id
*/
@JsonProperty("id")
public Integer getId() {
return id;
}

/**
*
* @param id
* The id
*/
@JsonProperty("id")
public void setId(Integer id) {
this.id = id;
}

/**
*
* @return
* The firstName
*/
@JsonProperty("firstName")
public String getFirstName() {
return firstName;
}

/**
*
* @param firstName
* The firstName
*/
@JsonProperty("firstName")
public void setFirstName(String firstName) {
this.firstName = firstName;
}

/**
*
* @return
* The lastName
*/
@JsonProperty("lastName")
public String getLastName() {
return lastName;
}

/**
*
* @param lastName
* The lastName
*/
@JsonProperty("lastName")
public void setLastName(String lastName) {
this.lastName = lastName;
}

@JsonAnyGetter
public Map<String, Object> getAdditionalProperties() {
return this.additionalProperties;
}

@JsonAnySetter
public void setAdditionalProperty(String name, Object value) {
this.additionalProperties.put(name, value);
}

}

LoadFromJSON.java

import org.codehaus.jettison.json.JSONObject;

import com.fasterxml.jackson.databind.ObjectMapper;

public class LoadFromJSON {

	public static void main(String args[]) throws Exception {
		JSONObject json = new JSONObject();
		json.put("id", 2);
		json.put("firstName", "hello");
		json.put("lastName", "world");

		byte[] jsonData = json.toString().getBytes();

		ObjectMapper mapper = new ObjectMapper();
		Employee employee = mapper.readValue(jsonData, Employee.class);

		System.out.print(employee.getLastName());

	}
}

Solution 7 - Java

HashMap keyArrayList = new HashMap();
Iterator itr = yourJson.keys();
while (itr.hasNext())
{
    String key = (String) itr.next();
    keyArrayList.put(key, yourJson.get(key).toString());
}

Solution 8 - Java

If you use any kind of special maps with keys or values also of special maps, you will find it's not contemplated by the implementation of google.

Solution 9 - Java

Depending on the input JSON format(string/file) create a jSONString. Sample Message class object corresponding to JSON can be obtained as below:

Message msgFromJSON = new ObjectMapper().readValue(jSONString, Message.class);

Solution 10 - Java

What's wrong with the standard stuff?

JSONObject jsonObject = new JSONObject(someJsonString);
JSONArray jsonArray = jsonObject.getJSONArray("someJsonArray");
String value = jsonArray.optJSONObject(i).getString("someJsonValue");

Solution 11 - Java

Give boon a try:

https://github.com/RichardHightower/boon

It is wicked fast:

https://github.com/RichardHightower/json-parsers-benchmark

Don't take my word for it... check out the gatling benchmark.

https://github.com/gatling/json-parsers-benchmark

(Up to 4x is some cases, and out of the 100s of test. It also has a index overlay mode that is even faster. It is young but already has some users.)

It can parse JSON to Maps and Lists faster than any other lib can parse to a JSON DOM and that is without Index Overlay mode. With Boon Index Overlay mode, it is even faster.

It also has a very fast JSON lax mode and a PLIST parser mode. :) (and has a super low memory, direct from bytes mode with UTF-8 encoding on the fly).

It also has the fastest JSON to JavaBean mode too.

It is new, but if speed and simple API is what you are looking for, I don't think there is a faster or more minimalist API.

Solution 12 - Java

The easiest way is that you can use this softconvertvalue method which is a custom method in which you can convert jsonData into your specific Dto class.

Dto response = softConvertValue(jsonData, Dto.class);
    
    
public static <T> T softConvertValue(Object fromValue, Class<T> toValueType) 
{
    ObjectMapper objMapper = new ObjectMapper();
    return objMapper
        .configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false)
        .convertValue(fromValue, toValueType);
}
Categories
Recommended Java Solutions
Recommended Json Solutions
Recommended Jackson Solutions
Recommended Gson Solutions

Previous Solution:

How can I properly compare two Integers in Java?

JavaIntegerAutoboxing

Next Solution:

Can I make fast forwarding be off by default in git?

GitMergeBranchRebaseFast Forward

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionFaiyetView Question on Stackoverflow
Solution 1 - JavaBalusCView Answer on Stackoverflow
Solution 2 - JavaJorView Answer on Stackoverflow
Solution 3 - JavaStaxManView Answer on Stackoverflow
Solution 4 - JavaGene De LisaView Answer on Stackoverflow
Solution 5 - JavacherouvimView Answer on Stackoverflow
Solution 6 - JavaRahul RainaView Answer on Stackoverflow
Solution 7 - JavaHEATView Answer on Stackoverflow
Solution 8 - JavaJuanmaView Answer on Stackoverflow
Solution 9 - JavaShailendra SinghView Answer on Stackoverflow
Solution 10 - JavaKevinView Answer on Stackoverflow
Solution 11 - JavaRickHighView Answer on Stackoverflow
Solution 12 - JavaDipen ChawlaView Answer on Stackoverflow