Convert time.Time to string

StringTimeGo

String Problem Overview


I'm trying to add some values from my database to a []string in Go. Some of these are timestamps.

I get the error:

> cannot use U.Created_date (type time.Time) as type string in array element

Can I convert time.Time to string?

type UsersSession struct {
    Userid int
    Timestamp time.Time
    Created_date time.Time
}

type Users struct {
    Name string
    Email string
    Country string
    Created_date time.Time
    Id int
    Hash string
    IP string
}

-

var usersArray = [][]string{}

rows, err := db.Query("SELECT u.id, u.hash, u.name, u.email, u.country, u.IP, u.created_date, us.timestamp, us.created_date FROM usersSession AS us LEFT JOIN users AS u ON u.id = us.userid WHERE us.timestamp + interval 30 minute >= now()")

U := Users{}
US := UsersSession{}

for rows.Next() {
    err = rows.Scan(&U.Id, &U.Hash, &U.Name, &U.Email, &U.Country, &U.IP, &U.Created_date, &US.Timestamp, &US.Created_date)
    checkErr(err)

    userid_string := strconv.Itoa(U.Id)
    user := []string{userid_string, U.Hash, U.Name, U.Email, U.Country, U.IP, U.Created_date, US.Timestamp, US.Created_date}
    // -------------
    // ^ this is where the error occurs
    // cannot use U.Created_date (type time.Time) as type string in array element (for US.Created_date and US.Timestamp aswell)
    // -------------

    usersArray = append(usersArray, user)
    log.Print("usersArray: ", usersArray)
}

EDIT

I added the following. It works now, thanks.

userCreatedDate := U.Created_date.Format("2006-01-02 15:04:05")
userSessionCreatedDate := US.Created_date.Format("2006-01-02 15:04:05")
userSessionTimestamp := US.Timestamp.Format("2006-01-02 15:04:05")

String Solutions


Solution 1 - String

You can use the Time.String() method to convert a time.Time to a string. This uses the format string "2006-01-02 15:04:05.999999999 -0700 MST".

If you need other custom format, you can use Time.Format(). For example to get the timestamp in the format of yyyy-MM-dd HH:mm:ss use the format string "2006-01-02 15:04:05".

Example:

t := time.Now()
fmt.Println(t.String())
fmt.Println(t.Format("2006-01-02 15:04:05"))

Output (try it on the Go Playground):

2009-11-10 23:00:00 +0000 UTC
2009-11-10 23:00:00

Note: time on the Go Playground is always set to the value seen above. Run it locally to see current date/time.

Also note that using Time.Format(), as the layout string you always have to pass the same time –called the reference time– formatted in a way you want the result to be formatted. This is documented at Time.Format():

> Format returns a textual representation of the time value formatted according to layout, which defines the format by showing how the reference time, defined to be > > Mon Jan 2 15:04:05 -0700 MST 2006 > > would be displayed if it were the value; it serves as an example of the desired output. The same display rules will then be applied to the time value.

Solution 2 - String

package main                                                                                                                                                           

import (
    "fmt"
    "time"
)

// @link https://golang.org/pkg/time/

func main() {

    //caution : format string is `2006-01-02 15:04:05.000000000`
    current := time.Now()

    fmt.Println("origin : ", current.String())
    // origin :  2016-09-02 15:53:07.159994437 +0800 CST

    fmt.Println("mm-dd-yyyy : ", current.Format("01-02-2006"))
    // mm-dd-yyyy :  09-02-2016

    fmt.Println("yyyy-mm-dd : ", current.Format("2006-01-02"))
    // yyyy-mm-dd :  2016-09-02

    // separated by .
    fmt.Println("yyyy.mm.dd : ", current.Format("2006.01.02"))
    // yyyy.mm.dd :  2016.09.02

    fmt.Println("yyyy-mm-dd HH:mm:ss : ", current.Format("2006-01-02 15:04:05"))
    // yyyy-mm-dd HH:mm:ss :  2016-09-02 15:53:07

    // StampMicro
    fmt.Println("yyyy-mm-dd HH:mm:ss: ", current.Format("2006-01-02 15:04:05.000000"))
    // yyyy-mm-dd HH:mm:ss:  2016-09-02 15:53:07.159994

    //StampNano
    fmt.Println("yyyy-mm-dd HH:mm:ss: ", current.Format("2006-01-02 15:04:05.000000000"))
    // yyyy-mm-dd HH:mm:ss:  2016-09-02 15:53:07.159994437
}    

Solution 3 - String

package main

import (
	"fmt"
	"time"
)

func main() {
	v , _ := time.Now().UTC().MarshalText()
	fmt.Println(string(v))
}

Output : 2009-11-10T23:00:00Z

Go Playground

Solution 4 - String

strconv.Itoa(int(time.Now().Unix()))

Solution 5 - String

Go Playground http://play.golang.org/p/DN5Py5MxaB

package main

import (
    "fmt"
    "time"
)

func main() {
    t := time.Now()
	// The Time type implements the Stringer interface -- it
    // has a String() method which gets called automatically by
    // functions like Printf().
    fmt.Printf("%s\n", t)
    
    // See the Constants section for more formats
    // http://golang.org/pkg/time/#Time.Format
    formatedTime := t.Format(time.RFC1123)
    fmt.Println(formatedTime)
}

Solution 6 - String

Please find the simple solution to convete Date & Time Format in Go Lang. Please find the example below.

Package Link: https://github.com/vigneshuvi/GoDateFormat.

Please find the plackholders:https://medium.com/@Martynas/formatting-date-and-time-in-golang-5816112bf098

package main


// Import Package
import (
    "fmt"
    "time"
    "github.com/vigneshuvi/GoDateFormat"
)

func main() {
    fmt.Println("Go Date Format(Today - 'yyyy-MM-dd HH:mm:ss Z'): ", GetToday(GoDateFormat.ConvertFormat("yyyy-MM-dd HH:mm:ss Z")))
    fmt.Println("Go Date Format(Today - 'yyyy-MMM-dd'): ", GetToday(GoDateFormat.ConvertFormat("yyyy-MMM-dd")))
    fmt.Println("Go Time Format(NOW - 'HH:MM:SS'): ", GetToday(GoDateFormat.ConvertFormat("HH:MM:SS")))
    fmt.Println("Go Time Format(NOW - 'HH:MM:SS tt'): ", GetToday(GoDateFormat.ConvertFormat("HH:MM:SS tt")))
}

func GetToday(format string) (todayString string){
    today := time.Now()
    todayString = today.Format(format);
    return
}

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionA.DView Question on Stackoverflow
Solution 1 - StringiczaView Answer on Stackoverflow
Solution 2 - StringHaoView Answer on Stackoverflow
Solution 3 - StringSonu SharmaView Answer on Stackoverflow
Solution 4 - StringfeuyeuxView Answer on Stackoverflow
Solution 5 - StringfirebitsbrView Answer on Stackoverflow
Solution 6 - StringVignesh KumarView Answer on Stackoverflow