Convert an integer to a byte array
GoType ConversionGo Problem Overview
I have a function which receives a []byte
but what I have is an int
, what is the best way to go about this conversion ?
err = a.Write([]byte(myInt))
I guess I could go the long way and get it into a string and put that into bytes, but it sounds ugly and I guess there are better ways to do it.
Go Solutions
Solution 1 - Go
I agree with Brainstorm's approach: assuming that you're passing a machine-friendly binary representation, use the encoding/binary
library. The OP suggests that binary.Write()
might have some overhead. Looking at the source for the implementation of Write()
, I see that it does some runtime decisions for maximum flexibility.
func Write(w io.Writer, order ByteOrder, data interface{}) error {
// Fast path for basic types.
var b [8]byte
var bs []byte
switch v := data.(type) {
case *int8:
bs = b[:1]
b[0] = byte(*v)
case int8:
bs = b[:1]
b[0] = byte(v)
case *uint8:
bs = b[:1]
b[0] = *v
...
Right? Write() takes in a very generic data
third argument, and that's imposing some overhead as the Go runtime then is forced into encoding type information. Since Write()
is doing some runtime decisions here that you simply don't need in your situation, maybe you can just directly call the encoding functions and see if it performs better.
Something like this:
package main
import (
"encoding/binary"
"fmt"
)
func main() {
bs := make([]byte, 4)
binary.LittleEndian.PutUint32(bs, 31415926)
fmt.Println(bs)
}
Let us know how this performs.
Otherwise, if you're just trying to get an ASCII representation of the integer, you can get the string representation (probably with strconv.Itoa
) and cast that string to the []byte
type.
package main
import (
"fmt"
"strconv"
)
func main() {
bs := []byte(strconv.Itoa(31415926))
fmt.Println(bs)
}
Solution 2 - Go
Check out the "encoding/binary" package. Particularly the Read and Write functions:
binary.Write(a, binary.LittleEndian, myInt)
Solution 3 - Go
Sorry, this might be a bit late. But I think I found a better implementation on the go docs.
buf := new(bytes.Buffer)
var num uint16 = 1234
err := binary.Write(buf, binary.LittleEndian, num)
if err != nil {
fmt.Println("binary.Write failed:", err)
}
fmt.Printf("% x", buf.Bytes())
Solution 4 - Go
i thought int type has any method for getting int hash to bytes, but first i find math / big method for this https://golang.org/pkg/math/big/
var f int = 52452356235; // int
var s = big.NewInt(int64(f)) // int to big Int
var b = s.Bytes() // big Int to bytes
// b - byte slise
var r = big.NewInt(0).SetBytes(b) // bytes to big Int
var i int = int(r.Int64()) // big Int to int
https://play.golang.org/p/VAKSGw8XNQq
However, this method uses an absolute value. If you spend 1 byte more, you can transfer the sign
func IntToBytes(i int) []byte{
if i > 0 {
return append(big.NewInt(int64(i)).Bytes(), byte(1))
}
return append(big.NewInt(int64(i)).Bytes(), byte(0))
}
func BytesToInt(b []byte) int{
if b[len(b)-1]==0 {
return -int(big.NewInt(0).SetBytes(b[:len(b)-1]).Int64())
}
return int(big.NewInt(0).SetBytes(b[:len(b)-1]).Int64())
}
https://play.golang.org/p/mR5Sp5hu4jk
or new(https://play.golang.org/p/7ZAK4QL96FO)
(The package also provides functions for fill into an existing slice)
Solution 5 - Go
Adding this option for dealing with basic uint8 to byte[] conversion
foo := 255 // 1 - 255
ufoo := uint16(foo)
far := []byte{0,0}
binary.LittleEndian.PutUint16(far, ufoo)
bar := int(far[0]) // back to int
fmt.Println("foo, far, bar : ",foo,far,bar)
output :
foo, far, bar : 255 [255 0] 255
Solution 6 - Go
Here is another option, based on the Go source code [1]:
package main
import (
"encoding/binary"
"fmt"
"math/bits"
)
func encodeUint(x uint64) []byte {
buf := make([]byte, 8)
binary.BigEndian.PutUint64(buf, x)
return buf[bits.LeadingZeros64(x) >> 3:]
}
func main() {
for x := 0; x <= 64; x += 8 {
buf := encodeUint(1<<x-1)
fmt.Println(buf)
}
}
Result:
[]
[255]
[255 255]
[255 255 255]
[255 255 255 255]
[255 255 255 255 255]
[255 255 255 255 255 255]
[255 255 255 255 255 255 255]
[255 255 255 255 255 255 255 255]
Much faster than math/big
:
BenchmarkBig-12 28348621 40.62 ns/op
BenchmarkBit-12 731601145 1.641 ns/op
Solution 7 - Go
Convert Integer to byte slice.
import (
"bytes"
"encoding/binary"
"log"
)
func IntToBytes(num int64) []byte {
buff := new(bytes.Buffer)
bigOrLittleEndian := binary.BigEndian
err := binary.Write(buff, bigOrLittleEndian, num)
if err != nil {
log.Panic(err)
}
return buff.Bytes()
}
Solution 8 - Go
Maybe the simple way is using protobuf, see the Protocol Buffer Basics: Go
define message like
message MyData {
int32 id = 1;
}
get more in Defining your protocol format
// Write
out, err := proto.Marshal(mydata)
read more in Writing a Message
Solution 9 - Go
What's wrong with converting it to a string?
[]byte(fmt.Sprintf("%d", myint))