Concatenate string with field value in MySQL

PhpMysqlSqlConcatenation

Php Problem Overview


I have the need to concatenate a string with a field value in a MySQL query in order to LEFT JOIN two tables.

Table one has a column called "category_id" with numeric values, such as 61, 78, 94 and such.

Table two has a column called "query" which refers to a request route mechanism, and it has values such as "product_id=68", "category_id=74", "manufacturer_id=99" and so on.

So in my query I require to join the tables when ever a concatenated string derived from a set string and the value of the "category_id" column matches the query field.

My SQL statement is currently:

SELECT * FROM tableOne 
LEFT JOIN tableTwo
ON tableTwo.query = 'category_id=' + tableOne.category_id

I have tried using the || operator instead of the + operator, but still no luck. Is it possible to do this in MySQL, or have I jumped the gun here?

Php Solutions


Solution 1 - Php

Have you tried using the concat() function?

ON tableTwo.query = concat('category_id=',tableOne.category_id)

Solution 2 - Php

SELECT ..., CONCAT( 'category_id=', tableOne.category_id) as query2  FROM tableOne 
LEFT JOIN tableTwo
ON tableTwo.query = query2

Solution 3 - Php

Here is a great answer to that:

SET sql_mode='PIPES_AS_CONCAT';

Find more here: https://stackoverflow.com/a/24777235/4120319

Here's the full SQL:

SET sql_mode='PIPES_AS_CONCAT';

SELECT * FROM tableOne 
LEFT JOIN tableTwo
ON tableTwo.query = 'category_id=' || tableOne.category_id;

Solution 4 - Php

MySQL uses CONCAT() to concatenate strings

SELECT * FROM tableOne 
LEFT JOIN tableTwo
ON tableTwo.query = CONCAT('category_id=', tableOne.category_id)

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionBenView Question on Stackoverflow
Solution 1 - PhpWillView Answer on Stackoverflow
Solution 2 - PhpchadzhengView Answer on Stackoverflow
Solution 3 - PhpDavid NamenyiView Answer on Stackoverflow
Solution 4 - PhpChrisView Answer on Stackoverflow