Combine awaitables like Promise.all

PythonPython 3.xAsync AwaitFuturePython Asyncio

Python Problem Overview


In asynchronous JavaScript, it is easy to run tasks in parallel and wait for all of them to complete using Promise.all:

async function bar(i) {
  console.log('started', i);
  await delay(1000);
  console.log('finished', i);
}

async function foo() {
    await Promise.all([bar(1), bar(2)]);
}

// This works too:
async function my_all(promises) {
    for (let p of promises) await p;
}

async function foo() {
    await my_all([bar(1), bar(2), bar(3)]);
}

I tried to rewrite the latter in python:

import asyncio

async def bar(i):
  print('started', i)
  await asyncio.sleep(1)
  print('finished', i)

async def aio_all(seq):
  for f in seq:
    await f
    
async def main():
  await aio_all([bar(i) for i in range(10)])

loop = asyncio.get_event_loop()
loop.run_until_complete(main())
loop.close()

But it executes my tasks sequentially.

What is the simplest way to await multiple awaitables? Why doesn't my approach work?

Python Solutions


Solution 1 - Python

The equivalent would be using asyncio.gather:

import asyncio

async def bar(i):
  print('started', i)
  await asyncio.sleep(1)
  print('finished', i)

async def main():
  await asyncio.gather(*[bar(i) for i in range(10)])

loop = asyncio.get_event_loop()
loop.run_until_complete(main())
loop.close()

> Why doesn't my approach work?

Because when you await each item in seq, you block that coroutine. So in essence, you have synchronous code masquerading as async. If you really wanted to, you could implement your own version of asyncio.gather using loop.create_task or asyncio.ensure_future.

EDIT

The original answer used the lower-level asyncio.wait.

Solution 2 - Python

I noticed that asyncio.gather() may be a better way to await other than asyncio.wait() if we want ordered results.

As the docs indicates, the order of result values from asyncio.gather() method corresponds to the order of awaitables in aws. However, the order of result values from asyncio.wait() won't do the same thing.You can test it.

Solution 3 - Python

https://docs.python.org/3/library/asyncio-task.html#asyncio.gather

asyncio.gather() will return the list of output from each async function calls.

import asyncio

async def bar(i):
	print('started', i)
	await asyncio.sleep(1)
	print('finished', i)
	return i

async def main():
	values = await asyncio.gather(*[bar(i) for i in range(10)])
	print(values)

asyncio.run(main())

This method, gather, takes arbitrary number of args for the concurrent jobs instead of a list, so we unpack.

It's very common to need this intermediate value, values in my eg, instead of designing your function/method to have side effects.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionTamas HegedusView Question on Stackoverflow
Solution 1 - PythonJashandeep SohiView Answer on Stackoverflow
Solution 2 - Python请叫我小马哥View Answer on Stackoverflow
Solution 3 - PythonJames T.View Answer on Stackoverflow